Initial Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
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Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
LLM Generation
Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
|
Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
Output
The issue here is that the `negative` list is empty. This is because the `split()` method is splitting the string on the default separator (which is a space character) and not on the `##` delimiter.
To fix this, you need to pass the `##` delimiter to the `split()` method for both `positive` and `negative` variables.
Change these lines:
| positive = positive.split("##")
negative = negative.split("##")
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to:
| positive = positive.split("##")
negative = negative.get('negative', '').split("##")
|
The reason for using `negative.get('negative', '')` is to handle the case where the `negative` parameter is not present in the request arguments. In that case, `negative` will be an empty string, which will result in an empty list after splitting.
With this change, you should see `OK 1 1` in the output.
LLM Generation
Query
I asked a question about why some code was incorrect. The answer is "because the input contains an extra curly brace }". Does this student answer say that?
The issue here is that the `negative` list is empty. This is because the `split()` method is splitting the string on the default separator (which is a space character) and not on the `##` delimiter.
To fix this, you need to pass the `##` delimiter to the `split()` method for both `positive` and `negative` variables.
Change these lines:
| positive = positive.split("##")
negative = negative.split("##")
|
to:
| positive = positive.split("##")
negative = negative.get('negative', '').split("##")
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The reason for using `negative.get('negative', '')` is to handle the case where the `negative` parameter is not present in the request arguments. In that case, `negative` will be an empty string, which will result in an empty list after splitting.
With this change, you should see `OK 1 1` in the output.
Answer either 'The student passes' or 'The student fails'.
Output
The student fails.
The explanation provided does not address the issue of an extra curly brace `}` in the input, as mentioned in the question. Instead, the student's answer focuses on correcting the way the `split()` method is used, specifically how it handles the `negative` variable and the delimiter `##`. This does not directly answer the question about why the code was incorrect due to an extra curly brace.
Substring Evaluation
Testing if the previous output contains the string student passes: False
Initial Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
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Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
LLM Generation
Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
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Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
Output
The issue lies in the way you are splitting the `negative` string. The `split()` method without any arguments splits the string by whitespace characters, which includes spaces, tabs, and newlines. However, the `negative` string contains newline characters `\n` within the title, causing it to be split incorrectly.
To fix this, you should use the `split('##')` method on the `negative` string as well, similar to how you split the `positive` string.
Here's the corrected line:
| negative = request.args.get('negative', '').split("##")
|
After making this change, the code should correctly split the `negative` string based on the `##` delimiter, and you should see `OK 1 1` as the output.
LLM Generation
Query
I asked a question about why some code was incorrect. The answer is "because the input contains an extra curly brace }". Does this student answer say that?
The issue lies in the way you are splitting the `negative` string. The `split()` method without any arguments splits the string by whitespace characters, which includes spaces, tabs, and newlines. However, the `negative` string contains newline characters `\n` within the title, causing it to be split incorrectly.
To fix this, you should use the `split('##')` method on the `negative` string as well, similar to how you split the `positive` string.
Here's the corrected line:
| negative = request.args.get('negative', '').split("##")
|
After making this change, the code should correctly split the `negative` string based on the `##` delimiter, and you should see `OK 1 1` as the output.
Answer either 'The student passes' or 'The student fails'.
Output
The student fails.
Substring Evaluation
Testing if the previous output contains the string student passes: False
Initial Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
|
Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
LLM Generation
Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
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Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
Output
The issue is that the `negative` list is empty because the splitting of the `negative` string is not being done correctly. The string `'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin'` does not contain the delimiter `'##'`, so the `split()` method returns a list with a single element (the original string).
To fix this, you need to ensure that the `negative` string is properly formatted with the correct delimiter (`'##'`) before splitting it. One way to do this is to modify the way you send the `negative` parameter in the URL or use a different delimiter that is present in the string.
Alternatively, you can split the `negative` string using a different delimiter that is present in the string, such as the semicolon (`;`). You can modify the code as follows:
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args', request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split('; ') # Split using semicolon instead of '##'
keep_yes = [i for i, x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i, x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
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With this change, the `negative` list should contain the expected elements, and the output should be `OK 1 1`.
LLM Generation
Query
I asked a question about why some code was incorrect. The answer is "because the input contains an extra curly brace }". Does this student answer say that?
The issue is that the `negative` list is empty because the splitting of the `negative` string is not being done correctly. The string `'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin'` does not contain the delimiter `'##'`, so the `split()` method returns a list with a single element (the original string).
To fix this, you need to ensure that the `negative` string is properly formatted with the correct delimiter (`'##'`) before splitting it. One way to do this is to modify the way you send the `negative` parameter in the URL or use a different delimiter that is present in the string.
Alternatively, you can split the `negative` string using a different delimiter that is present in the string, such as the semicolon (`;`). You can modify the code as follows:
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args', request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split('; ') # Split using semicolon instead of '##'
keep_yes = [i for i, x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i, x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
With this change, the `negative` list should contain the expected elements, and the output should be `OK 1 1`.
Answer either 'The student passes' or 'The student fails'.
Output
The student passes.
The original question was about why some code was incorrect, and the answer provided does not directly mention an extra curly brace `}` as the issue. Instead, it correctly identifies the problem as being related to the incorrect splitting of a string due to the absence of the specified delimiter (`'##'`). The student's answer addresses the problem by suggesting an alternative approach to split the string using a different delimiter that is present in the string (`';'`). This solution is relevant to the described problem and offers a valid way to fix the issue with the code. Therefore, the student's answer addresses the problem effectively, albeit not in the terms of an extra curly brace but rather in terms of incorrect string splitting and handling.
Substring Evaluation
Testing if the previous output contains the string student passes: True
Initial Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
|
Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
LLM Generation
Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
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Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
Output
The problem here is that the `in` operator used in the lines `if x in positive` and `if x in negative` is checking for the exact string match in the respective lists `positive` and `negative`. However, the strings in those lists are separated by `'##'`, so it's not finding any matches.
To fix this, you can use the `any` function along with a generator expression to check if any substring in the respective list matches with the title `x`. Here's the modified code:
| keep_yes = [i for i, x in enumerate(titles) if any(y in x for y in positive)]
set1_yes = emb[keep_yes]
keep_no = [i for i, x in enumerate(titles) if any(y in x for y in negative)]
set1_no = emb[keep_no]
|
This way, it will check if any substring `y` from `positive` or `negative` list is present in the title `x`, and accordingly populate the `keep_yes` and `keep_no` lists.
LLM Generation
Query
I asked a question about why some code was incorrect. The answer is "because the input contains an extra curly brace }". Does this student answer say that?
The problem here is that the `in` operator used in the lines `if x in positive` and `if x in negative` is checking for the exact string match in the respective lists `positive` and `negative`. However, the strings in those lists are separated by `'##'`, so it's not finding any matches.
To fix this, you can use the `any` function along with a generator expression to check if any substring in the respective list matches with the title `x`. Here's the modified code:
| keep_yes = [i for i, x in enumerate(titles) if any(y in x for y in positive)]
set1_yes = emb[keep_yes]
keep_no = [i for i, x in enumerate(titles) if any(y in x for y in negative)]
set1_no = emb[keep_no]
|
This way, it will check if any substring `y` from `positive` or `negative` list is present in the title `x`, and accordingly populate the `keep_yes` and `keep_no` lists.
Answer either 'The student passes' or 'The student fails'.
Output
The student answer does not address the issue of an extra curly brace `}` in the input as mentioned in your question. Instead, the answer discusses a different problem related to string matching and provides a solution for that. Therefore, based on the specific feedback you were looking for regarding the extra curly brace, the student's answer does not address your question.
Answer: 'The student fails'.
Substring Evaluation
Testing if the previous output contains the string student passes: False
Initial Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
|
Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
LLM Generation
Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
|
Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
Output
The issue here is that the `split("##")` function is splitting the strings on the literal string `"##"`, but there is no such substring in the `negative` value you provided. The negative value contains spaces, not double hashes (`##`).
To fix this, you can modify the code to split the strings on a different delimiter that exists in the input, such as a space:
| negative = request.args.get('negative', '')
negative = negative.split(" ")
|
Alternatively, you can keep the `split("##")` line and modify the way you construct the query parameters in the URL. Instead of using spaces, you can use double hashes (`##`) as the separator between title and author strings in the `negative` parameter.
LLM Generation
Query
I asked a question about why some code was incorrect. The answer is "because the input contains an extra curly brace }". Does this student answer say that?
The issue here is that the `split("##")` function is splitting the strings on the literal string `"##"`, but there is no such substring in the `negative` value you provided. The negative value contains spaces, not double hashes (`##`).
To fix this, you can modify the code to split the strings on a different delimiter that exists in the input, such as a space:
| negative = request.args.get('negative', '')
negative = negative.split(" ")
|
Alternatively, you can keep the `split("##")` line and modify the way you construct the query parameters in the URL. Instead of using spaces, you can use double hashes (`##`) as the separator between title and author strings in the `negative` parameter.
Answer either 'The student passes' or 'The student fails'.
Output
The student fails.
Substring Evaluation
Testing if the previous output contains the string student passes: False