Initial Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
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Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
LLM Generation
Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
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Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
Output
The issue lies in how you are splitting the 'negative' string. In the provided code, you are using '##' as the delimiter to split the string, but in the example input, there is no '##' present in the 'negative' string. As a result, the 'negative' string is not being split into separate elements, and the 'negative' list remains empty.
To fix this, you should modify the delimiter used for splitting the 'negative' string to match the actual delimiter present in the input. Based on the example input, it appears that the delimiter is simply a space character. So, you can change the following line:
| negative = negative.split("##")
|
to:
| negative = negative.split(" ")
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By making this change, the 'negative' string will be properly split into separate elements based on the space delimiter, and the 'negative' list will contain the expected elements. Consequently, when you calculate the length of 'set1_no', it should be 1 instead of 0, and you should see the output "OK 1 1".
LLM Generation
Query
I asked a question about why some code was incorrect. The answer is "because the input contains an extra curly brace }". Does this student answer say that?
The issue lies in how you are splitting the 'negative' string. In the provided code, you are using '##' as the delimiter to split the string, but in the example input, there is no '##' present in the 'negative' string. As a result, the 'negative' string is not being split into separate elements, and the 'negative' list remains empty.
To fix this, you should modify the delimiter used for splitting the 'negative' string to match the actual delimiter present in the input. Based on the example input, it appears that the delimiter is simply a space character. So, you can change the following line:
| negative = negative.split("##")
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to:
| negative = negative.split(" ")
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By making this change, the 'negative' string will be properly split into separate elements based on the space delimiter, and the 'negative' list will contain the expected elements. Consequently, when you calculate the length of 'set1_no', it should be 1 instead of 0, and you should see the output "OK 1 1".
Answer either 'The student passes' or 'The student fails'.
Output
The student fails.
The provided answer does not address the issue of an extra curly brace `}` in the input, as mentioned in the question. Instead, it discusses an unrelated issue regarding the incorrect use of a delimiter for splitting a string.
Substring Evaluation
Testing if the previous output contains the string student passes: False
Initial Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
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Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
LLM Generation
Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
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Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
Output
The issue is that the `negative` input is being treated as a single string, rather than a list of strings separated by "##". This is because the `negative` input contains spaces and other characters that are not being properly split.
To fix this, you can modify the line where you split the `negative` input to handle the more complex string format. One way to do this is by using a regular expression to split on the pattern `' Authors: '`:
| negative = re.split(r' Authors: ', negative)
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This will correctly split the `negative` input into a list of two strings:
| ['Title: On Evaluating Adversarial Robustness', 'Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}']
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After this change, `len(set1_no)` should be 1, and you should see the output "OK 1 1".
Note: Make sure to import the `re` module at the top of your script with `import re` for this solution to work.
LLM Generation
Query
I asked a question about why some code was incorrect. The answer is "because the input contains an extra curly brace }". Does this student answer say that?
The issue is that the `negative` input is being treated as a single string, rather than a list of strings separated by "##". This is because the `negative` input contains spaces and other characters that are not being properly split.
To fix this, you can modify the line where you split the `negative` input to handle the more complex string format. One way to do this is by using a regular expression to split on the pattern `' Authors: '`:
| negative = re.split(r' Authors: ', negative)
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This will correctly split the `negative` input into a list of two strings:
| ['Title: On Evaluating Adversarial Robustness', 'Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}']
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After this change, `len(set1_no)` should be 1, and you should see the output "OK 1 1".
Note: Make sure to import the `re` module at the top of your script with `import re` for this solution to work.
Answer either 'The student passes' or 'The student fails'.
Output
The student's answer does not directly address the question about why some code was incorrect due to an extra curly brace `}`. Instead, the student's response focuses on a different issue related to the incorrect handling of the `negative` input, which is treated as a single string instead of being split into a list of strings. The solution provided involves using a regular expression to split the `negative` input on a specific pattern, which is unrelated to the presence of an extra curly brace.
Therefore, based on the information provided, the answer is: The student fails.
Substring Evaluation
Testing if the previous output contains the string student passes: False
Initial Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
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Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
LLM Generation
Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
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Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
Output
The issue is that the `negative` string is not being split correctly. In the provided code, `negative.split("##")` is used to split the `negative` string, but the example `negative` string does not contain the delimiter "##".
To fix this, you should change the delimiter used for splitting the `negative` string to match the actual delimiter present in the string. Based on the example, it seems that the delimiter is a single space character (' ').
Here's the corrected code:
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args', request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split(" ") # Change the delimiter to a space character
keep_yes = [i for i, x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i, x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
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By changing `negative.split("##")` to `negative.split(" ")`, the `negative` string will be split correctly based on the space character delimiter. This should result in the expected output of `OK 1 1`.
LLM Generation
Query
I asked a question about why some code was incorrect. The answer is "because the input contains an extra curly brace }". Does this student answer say that?
The issue is that the `negative` string is not being split correctly. In the provided code, `negative.split("##")` is used to split the `negative` string, but the example `negative` string does not contain the delimiter "##".
To fix this, you should change the delimiter used for splitting the `negative` string to match the actual delimiter present in the string. Based on the example, it seems that the delimiter is a single space character (' ').
Here's the corrected code:
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args', request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split(" ") # Change the delimiter to a space character
keep_yes = [i for i, x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i, x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
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By changing `negative.split("##")` to `negative.split(" ")`, the `negative` string will be split correctly based on the space character delimiter. This should result in the expected output of `OK 1 1`.
Answer either 'The student passes' or 'The student fails'.
Output
The student fails.
Substring Evaluation
Testing if the previous output contains the string student passes: False
Initial Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
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Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
LLM Generation
Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
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Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
Output
The issue is with how you are splitting the 'negative' parameter. The value of 'negative' contains the entire string "Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin", but you are splitting it using "##". However, there is no "##" separator in the 'negative' string, so the split operation results in a list with only one element, which is the entire string.
To fix this, you should modify the splitting logic for the 'negative' parameter to match the format of the input string. One possible change is to split the string using a different separator that actually exists in the input, such as splitting on "Authors:". Here's the modified code:
| negative = request.args.get('negative', '')
negative = negative.split("Authors:")
negative = [author.strip() for author in negative if author.strip()]
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In this modification, we split the 'negative' string using "Authors:" as the separator. This will create a list with two elements: the title part and the authors part. We then use a list comprehension to remove any leading/trailing whitespace from each element and remove any empty elements.
After this change, the 'negative' list should contain the expected elements, and you should see the output "OK 1 1" indicating that both 'positive' and 'negative' lists have one element each.
LLM Generation
Query
I asked a question about why some code was incorrect. The answer is "because the input contains an extra curly brace }". Does this student answer say that?
The issue is with how you are splitting the 'negative' parameter. The value of 'negative' contains the entire string "Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin", but you are splitting it using "##". However, there is no "##" separator in the 'negative' string, so the split operation results in a list with only one element, which is the entire string.
To fix this, you should modify the splitting logic for the 'negative' parameter to match the format of the input string. One possible change is to split the string using a different separator that actually exists in the input, such as splitting on "Authors:". Here's the modified code:
| negative = request.args.get('negative', '')
negative = negative.split("Authors:")
negative = [author.strip() for author in negative if author.strip()]
|
In this modification, we split the 'negative' string using "Authors:" as the separator. This will create a list with two elements: the title part and the authors part. We then use a list comprehension to remove any leading/trailing whitespace from each element and remove any empty elements.
After this change, the 'negative' list should contain the expected elements, and you should see the output "OK 1 1" indicating that both 'positive' and 'negative' lists have one element each.
Answer either 'The student passes' or 'The student fails'.
Output
The student answer does not directly address the issue of an extra curly brace as mentioned in your question. Instead, the student's response focuses on correcting the logic for splitting the 'negative' parameter based on a misunderstanding of the input string's format. The student suggests modifying the code to split the string using "Authors:" as a separator, which is unrelated to the problem of an extra curly brace. Therefore, based on the specific feedback you were looking for regarding an extra curly brace, the student's answer does not address that issue.
Answer: The student fails.
Substring Evaluation
Testing if the previous output contains the string student passes: False
Initial Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
|
Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
LLM Generation
Query
Why isn't this working
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16 | @app.route('/getsimilar', methods=['GET'])
def getsimilar():
print('args',request.args)
positive = request.args.get('positive', '')
positive = positive.split("##")
negative = request.args.get('negative', '')
negative = negative.split("##")
keep_yes = [i for i,x in enumerate(titles) if x in positive]
set1_yes = emb[keep_yes]
keep_no = [i for i,x in enumerate(titles) if x in negative]
set1_no = emb[keep_no]
print("OK", len(set1_yes), len(set1_no))
|
I see
| args ImmutableMultiDict([('positive', 'Title: Towards Evaluating the Robustness of Neural Networks
Authors: Nicholas Carlini; David Wagner'), ('negative', 'Title: On Evaluating Adversarial Robustness Authors: Nicholas Carlini; Anish Athalye; Nicolas Papernot; Wieland Brendel; Jonas Rauber; Dimitris Tsipras; Ian Goodfellow; Aleksander Madry; Alexey Kurakin}')])
OK 1 0
|
Why don't I see OK 1 1? Instead it just says OK 1 0. List exactly one reason explaining what's wrong and what one change would fix it.
Output
The issue is that the `negative` string is treated as a single item when splitting it using `negative.split("##")`. The string contains multiple fields like "Title:", "Authors:", etc., but it doesn't have any "##" separator between them.
To fix this, you should split the `negative` string using a different separator that actually exists between the title-author pairs. Based on the provided input, it seems that the title-author pairs are separated by a closing curly brace `}` followed by an opening curly brace `{`.
Here's the change you can make to fix the issue:
| negative = negative.split("}{")
|
By splitting the `negative` string using `}{`, you will correctly separate the title-author pairs into individual elements of the `negative` list. This change should result in `OK 1 1` being printed, indicating that both `set1_yes` and `set1_no` have one element each.
LLM Generation
Query
I asked a question about why some code was incorrect. The answer is "because the input contains an extra curly brace }". Does this student answer say that?
The issue is that the `negative` string is treated as a single item when splitting it using `negative.split("##")`. The string contains multiple fields like "Title:", "Authors:", etc., but it doesn't have any "##" separator between them.
To fix this, you should split the `negative` string using a different separator that actually exists between the title-author pairs. Based on the provided input, it seems that the title-author pairs are separated by a closing curly brace `}` followed by an opening curly brace `{`.
Here's the change you can make to fix the issue:
| negative = negative.split("}{")
|
By splitting the `negative` string using `}{`, you will correctly separate the title-author pairs into individual elements of the `negative` list. This change should result in `OK 1 1` being printed, indicating that both `set1_yes` and `set1_no` have one element each.
Answer either 'The student passes' or 'The student fails'.
Output
The student passes.
Substring Evaluation
Testing if the previous output contains the string student passes: True