Initial Query

Here's some data QUERY A361 Found at: 160392127418 Number of times present: 4 Found at: 150158692866 Number of times present: 3 Found at: 122340445248 Number of times present: 17 Found at: 137248651778 Number of times present: 84 Found at: 131891981708 Number of times present: 66 QUERY 32B57 Found at: 194561247604 Number of times present: 4 Found at: 82888490886 Number of times present: 3 Found at: 115836535414 Number of times present: 19 Found at: 79615924948 Number of times present: 80 Write a python function called `process` that will take data like this as an argument and return a dict where the keys are the like A361/32B57 and the values are how often its present in total.

LLM Generation

Query

Here's some data QUERY A361 Found at: 160392127418 Number of times present: 4 Found at: 150158692866 Number of times present: 3 Found at: 122340445248 Number of times present: 17 Found at: 137248651778 Number of times present: 84 Found at: 131891981708 Number of times present: 66 QUERY 32B57 Found at: 194561247604 Number of times present: 4 Found at: 82888490886 Number of times present: 3 Found at: 115836535414 Number of times present: 19 Found at: 79615924948 Number of times present: 80 Write a python function called `process` that will take data like this as an argument and return a dict where the keys are the like A361/32B57 and the values are how often its present in total.

Output

### Process Function 

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import re

def process(data):
    """
    Process the given data and return a dictionary with query names as keys and total presence counts as values.

    Args:
        data (str): The input data containing query information.

    Returns:
        dict: A dictionary with query names as keys and total presence counts as values.
    """
    # Initialize an empty dictionary to store the query presence counts
    query_counts = {}

    # Split the data into query blocks
    query_blocks = re.split(r'QUERY \w+', data)[1:]

    # Process each query block
    for i, block in enumerate(query_blocks):
        # Extract the query name from the original data
        query_name = re.search(r'QUERY (\w+)', data).group(1)
        data = data.replace(query_name, '', 1)

        # Initialize the query count to 0 if it's not already in the dictionary
        if query_name not in query_counts:
            query_counts[query_name] = 0

        # Extract the presence counts from the block
        presence_counts = re.findall(r'Number of times present: (\d+)', block)

        # Add the presence counts to the query count
        query_counts[query_name] += sum(map(int, presence_counts))

    return query_counts

# Example usage:
data = """
QUERY A361
Found at: 160392127418
Number of times present: 4


Found at: 150158692866
Number of times present: 3


Found at: 122340445248
Number of times present: 17


Found at: 137248651778
Number of times present: 84


Found at: 131891981708
Number of times present: 66


QUERY 32B57
Found at: 194561247604
Number of times present: 4


Found at: 82888490886
Number of times present: 3


Found at: 115836535414
Number of times present: 19


Found at: 79615924948
Number of times present: 80
"""

result = process(data)
print(result)
This will output: 
1
{'A361': 174, '32B57': 106}
This means that the query "A361" is present a total of 174 times, and the query "32B57" is present a total of 106 times.

Extract Code

I extracted the following code from that output: 

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import re

def process(data):
    """
    Process the given data and return a dictionary with query names as keys and total presence counts as values.

    Args:
        data (str): The input data containing query information.

    Returns:
        dict: A dictionary with query names as keys and total presence counts as values.
    """
    # Initialize an empty dictionary to store the query presence counts
    query_counts = {}

    # Split the data into query blocks
    query_blocks = re.split(r'QUERY \w+', data)[1:]

    # Process each query block
    for i, block in enumerate(query_blocks):
        # Extract the query name from the original data
        query_name = re.search(r'QUERY (\w+)', data).group(1)
        data = data.replace(query_name, '', 1)

        # Initialize the query count to 0 if it's not already in the dictionary
        if query_name not in query_counts:
            query_counts[query_name] = 0

        # Extract the presence counts from the block
        presence_counts = re.findall(r'Number of times present: (\d+)', block)

        # Add the presence counts to the query count
        query_counts[query_name] += sum(map(int, presence_counts))

    return query_counts

def main():
    # Example usage:
    data = """
QUERY A361
Found at: 160392127418
Number of times present: 4


Found at: 150158692866
Number of times present: 3


Found at: 122340445248
Number of times present: 17


Found at: 137248651778
Number of times present: 84


Found at: 131891981708
Number of times present: 66


QUERY 32B57
Found at: 194561247604
Number of times present: 4


Found at: 82888490886
Number of times present: 3


Found at: 115836535414
Number of times present: 19


Found at: 79615924948
Number of times present: 80
"""

    result = process(data)
    print(result)

if __name__ == "__main__":
    main()

Run Code Interpreter

Running the following program: 

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import re

def process(data):
    """
    Process the given data and return a dictionary with query names as keys and total presence counts as values.

    Args:
        data (str): The input data containing query information.

    Returns:
        dict: A dictionary with query names as keys and total presence counts as values.
    """
    # Initialize an empty dictionary to store the query presence counts
    query_counts = {}

    # Split the data into query blocks
    query_blocks = re.split(r'QUERY \w+', data)[1:]

    # Process each query block
    for i, block in enumerate(query_blocks):
        # Extract the query name from the original data
        query_name = re.search(r'QUERY (\w+)', data).group(1)
        data = data.replace(query_name, '', 1)

        # Initialize the query count to 0 if it's not already in the dictionary
        if query_name not in query_counts:
            query_counts[query_name] = 0

        # Extract the presence counts from the block
        presence_counts = re.findall(r'Number of times present: (\d+)', block)

        # Add the presence counts to the query count
        query_counts[query_name] += sum(map(int, presence_counts))

    return query_counts

def main():
    # Example usage:
    data = """
QUERY A361
Found at: 160392127418
Number of times present: 4


Found at: 150158692866
Number of times present: 3


Found at: 122340445248
Number of times present: 17


Found at: 137248651778
Number of times present: 84


Found at: 131891981708
Number of times present: 66


QUERY 32B57
Found at: 194561247604
Number of times present: 4


Found at: 82888490886
Number of times present: 3


Found at: 115836535414
Number of times present: 19


Found at: 79615924948
Number of times present: 80
"""

    result = process(data)
    print(result)

if __name__ == "__main__":
    main()





answer = process('QUERY A361\nFound at: 160392127418\nNumber of times present: 4\n\n\nFound at: 150158692866\nNumber of times present: 4\n\n\nFound at: 122340445248\nNumber of times present: 17\n\n\nFound at: 137248651778\nNumber of times present: 84\n\n\nFound at: 131891981708\nNumber of times present: 66\n\n\nQUERY 32B57\nFound at: 194561247604\nNumber of times present: 4\n\n\nFound at: 82888490886\nNumber of times present: 3\n\n\nFound at: 115836535414\nNumber of times present: 19\n\n\nFound at: 79615924948\nNumber of times present: 81\n')
expected = {'A361': 175, '32B57': 107}
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: {'A361': 174, '32B57': 106} All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True