I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To determine how long a 3Ah battery will last given a 30mV voltage drop over a 2.5-ohm resistor, we need to follow these steps: 1. **Calculate the current flowing through the resistor using Ohm's Law:** \[ I = \frac{V}{R} \] where \( V \) is the voltage drop (30mV or 0.03V) and \( R \) is the resistance (2.5 ohms). \[ I = \frac{0.03 \, \text{V}}{2.5 \, \Omega} = 0.012 \, \text{A} \] 2. **Determine the battery's capacity in ampere-hours (Ah):** The battery has a capacity of 3Ah. 3. **Calculate the duration the battery will last:** \[ \text{Duration} = \frac{\text{Battery Capacity}}{\text{Current Draw}} \] \[ \text{Duration} = \frac{3 \, \text{Ah}}{0.012 \, \text{A}} = 250 \, \text{hours} \] Therefore, the 3Ah battery will last **250 hours**.
Testing if the previous output matches the regex 250.{,10}hours: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To determine how long a 3Ah battery will last, we first need to calculate the current flowing through the 2.5 ohm resistor using the measured voltage drop of 30mV. The current \( I \) can be calculated using Ohm's law: \[ I = \frac{V}{R} \] Where: - \( V = 30 \) mV (or \( 0.03 \) V) - \( R = 2.5 \) ohms Substituting the values: \[ I = \frac{0.03 \text{ V}}{2.5 \text{ ohms}} = 0.012 \text{ A} \] Now, we have the current \( I = 0.012 \) A (or 12 mA). Next, we need to determine how long the 3Ah battery will last at this current draw. The battery's capacity is 3Ah, and we can use the formula: \[ \text{Time} = \frac{\text{Battery Capacity}}{\text{Current Draw}} \] Substituting the values: \[ \text{Time} = \frac{3 \text{ Ah}}{0.012 \text{ A}} = 250 \text{ hours} \] Therefore, the 3Ah battery will last 250 hours under the given conditions. **Answer: 250 hours**
Testing if the previous output matches the regex 250.{,10}hours: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To determine how long a 3Ah battery will last given a voltage drop of 30mV over a 2.5 ohm resistor, we need to follow these steps: 1. **Calculate the current through the resistor using Ohm's Law:** \[ I = \frac{V}{R} \] where \( V = 30 \text{ mV} = 0.03 \text{ V} \) and \( R = 2.5 \text{ ohms} \). \[ I = \frac{0.03 \text{ V}}{2.5 \text{ ohms}} = 0.012 \text{ A} = 12 \text{ mA} \] 2. **Determine the battery life:** The battery capacity is 3Ah (3000 mAh). The current drawn by the resistor is 12 mA. \[ \text{Battery life} = \frac{\text{Battery capacity}}{\text{Current drawn}} \] \[ \text{Battery life} = \frac{3000 \text{ mAh}}{12 \text{ mA}} = 250 \text{ hours} \] Therefore, the 3Ah battery will last 250 hours. **Answer:** 250 hours
Testing if the previous output matches the regex 250.{,10}hours: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To determine how long a 3Ah battery will last given the voltage drop and resistance, we need to calculate the current flowing through the resistor and then use the battery's capacity to find the duration. First, we calculate the current using Ohm's Law: \[ I = \frac{V}{R} \] where \( V \) is the voltage drop and \( R \) is the resistance. Given: \[ V = 30 \, \text{mV} = 0.03 \, \text{V} \] \[ R = 2.5 \, \Omega \] \[ I = \frac{0.03 \, \text{V}}{2.5 \, \Omega} = 0.012 \, \text{A} \] Now, we know the battery's capacity is 3Ah (3 ampere-hours). To find out how long the battery will last, we use the formula: \[ \text{Duration} = \frac{\text{Battery Capacity}}{\text{Current}} \] \[ \text{Duration} = \frac{3 \, \text{Ah}}{0.012 \, \text{A}} = 250 \, \text{hours} \] So, the battery will last for 250 hours. Answer: 250 hours.
Testing if the previous output matches the regex 250.{,10}hours: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To determine how long a 3Ah battery will last given a voltage drop of 30mV over a 2.5 ohm resistor, we need to follow these steps: 1. **Calculate the current flowing through the resistor using Ohm's Law (V = IR):** \[ I = \frac{V}{R} = \frac{30 \, \text{mV}}{2.5 \, \Omega} \] Converting 30mV to volts: \[ 30 \, \text{mV} = 0.03 \, \text{V} \] Substituting the values: \[ I = \frac{0.03 \, \text{V}}{2.5 \, \Omega} = 0.012 \, \text{A} = 12 \, \text{mA} \] 2. **Calculate the battery life using the battery capacity and the current:** \[ \text{Battery life} = \frac{\text{Battery capacity}}{\text{Current}} \] Given the battery capacity is 3Ah and the current is 12mA: \[ \text{Battery life} = \frac{3 \, \text{Ah}}{0.012 \, \text{A}} \] \[ \text{Battery life} = 250 \, \text{hours} \] Therefore, the 3Ah battery will last **250 hours**.
Testing if the previous output matches the regex 250.{,10}hours: True