I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To determine how long a 3Ah battery will last with a voltage drop of 30mV over a 2.5 ohm resistor, we first need to calculate the current flowing through the resistor using Ohm's Law: \[ I = \frac{V}{R} \] Where: - \( V = 30 \, \text{mV} = 0.030 \, \text{V} \) - \( R = 2.5 \, \Omega \) Now, substituting the values: \[ I = \frac{0.030 \, \text{V}}{2.5 \, \Omega} = 0.012 \, \text{A} \text{ or } 12 \, \text{mA} \] Now, we can calculate how long the 3Ah battery will last by using the formula: \[ \text{Time} = \frac{\text{Capacity}}{\text{Current}} \] Where: - Capacity = 3 Ah - Current = 0.012 A Substituting the values: \[ \text{Time} = \frac{3 \, \text{Ah}}{0.012 \, \text{A}} = 250 \, \text{hours} \] Therefore, the battery will last **250 hours**. So the answer is: **250 hours**.
Testing if the previous output matches the regex 250.{,10}hours: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To find out how long the battery will last, we first need to calculate the current flowing through the resistor using Ohm's Law, which states: \[ V = I \times R \] Where: - \( V \) is the voltage (30 mV or 0.030 V) - \( I \) is the current in amperes - \( R \) is the resistance (2.5 ohms) Rearranging the formula to solve for current: \[ I = \frac{V}{R} \] Substituting the values: \[ I = \frac{0.030 \, \text{V}}{2.5 \, \Omega} = 0.012 \, \text{A} \, (or \, 12 \, mA) \] Now, we have the current flowing through the resistor as 0.012 A. Next, we need to determine how long a 3 Ah battery can supply this current. The time can be calculated using the formula: \[ \text{Time (hours)} = \frac{\text{Capacity (Ah)}}{\text{Current (A)}} \] Substituting the values: \[ \text{Time} = \frac{3 \, \text{Ah}}{0.012 \, \text{A}} = 250 \, \text{hours} \] Thus, the battery will last **250 hours**. The final answer is: **250 hours**
Testing if the previous output matches the regex 250.{,10}hours: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To determine how long a 3Ah battery will last under a load that causes a 30mV drop across a 2.5 ohm resistor, we first need to calculate the current flowing through the resistor using Ohm's Law: \[ I = \frac{V}{R} \] Where: - \( V = 30 \text{ mV} = 0.030 \text{ V} \) - \( R = 2.5 \text{ ohms} \) Now, substituting the values: \[ I = \frac{0.030 \text{ V}}{2.5 \text{ ohms}} = 0.012 \text{ A} \text{ or } 12 \text{ mA} \] Next, we can calculate how long the 3Ah battery will last at this current draw. The capacity of the battery is 3Ah, which means it can supply 3A for 1 hour, or equivalently, 0.012A for: \[ \text{Time} = \frac{\text{Battery Capacity}}{\text{Current}} = \frac{3 \text{ Ah}}{0.012 \text{ A}} \] Calculating this gives: \[ \text{Time} = 250 \text{ hours} \] Thus, the answer is: **250 hours**
Testing if the previous output matches the regex 250.{,10}hours: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To calculate how long a 3Ah battery will last with a 30mV drop across a 2.5 ohm resistor, we first need to determine the current flowing through the resistor using Ohm's Law: \[ I = \frac{V}{R} \] Where: - \( V \) is the voltage (30mV or 0.030V) - \( R \) is the resistance (2.5 ohms) Now, substituting the values: \[ I = \frac{0.030 \text{ V}}{2.5 \text{ ohms}} = 0.012 \text{ A} \text{ or } 12 \text{ mA} \] Next, we calculate how long the 3Ah battery can last when supplying a current of 12mA: The capacity of the battery in milliampere-hours (mAh) is: \[ 3 \text{ Ah} = 3000 \text{ mAh} \] Now, we can calculate the battery life in hours: \[ \text{Battery Life (hours)} = \frac{\text{Battery Capacity (mAh)}}{\text{Current (mA)}} = \frac{3000 \text{ mAh}}{12 \text{ mA}} = 250 \text{ hours} \] Therefore, the battery will last **250 hours**. So the final answer is: **250 hours**
Testing if the previous output matches the regex 250.{,10}hours: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To find out how long a 3 Ah battery will last given a voltage drop of 30 mV over a 2.5-ohm resistor, we first need to calculate the current flowing through the resistor using Ohm's Law (V = I * R). 1. Convert the voltage drop from millivolts to volts: \[ V = 30 \, \text{mV} = 0.030 \, \text{V} \] 2. Use Ohm's Law to calculate the current (I): \[ I = \frac{V}{R} = \frac{0.030 \, \text{V}}{2.5 \, \Omega} = 0.012 \, \text{A} \text{ or } 12 \, \text{mA} \] 3. Now, we can determine how long the 3 Ah battery will last. The battery capacity is 3 Ah, and the current draw is 0.012 A. The time (in hours) can be calculated using the formula: \[ \text{Time} = \frac{\text{Battery Capacity}}{\text{Current}} = \frac{3 \, \text{Ah}}{0.012 \, \text{A}} = 250 \, \text{hours} \] Thus, the battery will last **250 hours**. Final answer: **250 hours**
Testing if the previous output matches the regex 250.{,10}hours: True