I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To find out how long the battery will last, we first need to calculate the current flowing through the resistor using Ohm's Law. Ohm's Law states that \(V = IR\), where \(V\) is the voltage (in volts), \(I\) is the current (in amperes), and \(R\) is the resistance (in ohms). Given: - Voltage drop (\(V\)) = 30mV = 0.03V (since 1mV = 0.001V) - Resistance (\(R\)) = 2.5 ohms - Battery capacity = 3Ah (Ampere-hours) First, calculate the current (\(I\)): \[I = \frac{V}{R} = \frac{0.03V}{2.5\Omega} = 0.012A\] Now, to find out how long the battery will last, we use the formula: \[Battery\ Life\ (hours) = \frac{Battery\ Capacity\ (Ah)}{Current\ (A)}\] \[Battery\ Life = \frac{3Ah}{0.012A} = 250\ hours\] Therefore, the 3Ah battery will last approximately 250 hours.
Testing if the previous output matches the regex 250.{,10}hours: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To find out how long a 3Ah (ampere-hour) battery will last given a voltage drop of 30mv (millivolts) across a 2.5 ohm resistor, we first need to calculate the current flowing through the resistor using Ohm's law, which states that \(I = \frac{V}{R}\), where \(I\) is the current in amperes, \(V\) is the voltage in volts, and \(R\) is the resistance in ohms. Given: - \(V = 30mv = 0.030V\) (since 1mv = 0.001V) - \(R = 2.5\Omega\) Substituting the given values into Ohm's law: \[I = \frac{0.030V}{2.5\Omega} = 0.012A\] Now, to find out how long the battery will last, we use the formula for battery life, which is given by: \[Battery\ Life (hours) = \frac{Battery\ Capacity (Ah)}{Current (A)}\] Given: - Battery Capacity = 3Ah - Current = 0.012A Substituting these values into the formula for battery life: \[Battery\ Life = \frac{3Ah}{0.012A} = 250\ hours\] Therefore, the 3Ah battery will last for 250 hours.
Testing if the previous output matches the regex 250.{,10}hours: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To determine how long a 3Ah (3000mAh) battery will last given a voltage drop of 30mV (0.03V) over a 2.5 ohm resistor, we first need to calculate the current flowing through the circuit. According to Ohm's Law: \[ V = IR \] Where: - \( V \) is the voltage (in volts) - \( I \) is the current (in amperes) - \( R \) is the resistance (in ohms) Rearranging the equation to solve for \( I \): \[ I = \frac{V}{R} \] Substituting the given values: \[ I = \frac{0.03V}{2.5\Omega} = 0.012A \] Now, to find out how long a 3Ah battery will last, we use the formula: \[ \text{Time} = \frac{\text{Battery Capacity (Ah)}}{\text{Current (A)}} \] Substituting the values: \[ \text{Time} = \frac{3Ah}{0.012A} = 250 \text{ hours} \] Therefore, a 3Ah battery will last approximately 250 hours.
Testing if the previous output matches the regex 250.{,10}hours: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To find out how long the 3Ah (ampere-hour) battery will last, we first need to calculate the current flowing through the 2.5 ohm resistor using Ohm's law (V = IR, where V is voltage, I is current, and R is resistance). Given: - Voltage drop (V) = 30mV = 0.03V (converting millivolts to volts) - Resistance (R) = 2.5 ohms First, calculate the current (I): \[I = \frac{V}{R} = \frac{0.03V}{2.5\Omega} = 0.012A\] Now, to determine how long the 3Ah battery will last, we use the formula: \[Time (hours) = \frac{Battery\ Capacity (Ah)}{Current (A)}\] Plugging in the numbers: \[Time = \frac{3Ah}{0.012A} = 250\ hours\] So, the battery will last '250 hours'.
Testing if the previous output matches the regex 250.{,10}hours: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To find out how long a 3Ah battery will last, we first need to calculate the current flowing through the circuit using Ohm's Law, which states \(I = \frac{V}{R}\), where \(I\) is the current in amperes, \(V\) is the voltage in volts, and \(R\) is the resistance in ohms. Given a voltage drop (\(V\)) of 30mv (or 0.03V) over a resistor with a resistance (\(R\)) of 2.5 ohms, the current (\(I\)) can be calculated as follows: \[I = \frac{V}{R} = \frac{0.03V}{2.5\Omega} = 0.012A\] Now, to find out how long a 3Ah (Ampere-hour) battery will last, we divide the battery capacity by the current: \[Time = \frac{Battery\ Capacity}{Current} = \frac{3Ah}{0.012A} = 250\ hours\] Therefore, a 3Ah battery will last approximately 250 hours.
Testing if the previous output matches the regex 250.{,10}hours: True