I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To calculate how long the battery will last, we first need to determine the current flowing through the resistor. We can use Ohm's Law to do this: V = I * R 30mV = I * 2.5 ohms I = 30mV / 2.5 ohms I = 0.012 A Now that we know the current flowing through the resistor is 0.012 A, we can calculate how long a 3Ah battery will last: 3 Ah / 0.012 A = 250 hours Therefore, the battery will last for 250 hours.
Testing if the previous output matches the regex 250.{,10}hours: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To calculate how long a 3Ah battery will last, we need to first find the current flowing through the circuit using Ohm's Law: V = I * R 30mV = I * 2.5 ohm I = 30mV / 2.5 ohm I = 0.012 A Now, we can calculate the battery life using the formula: Battery life = Battery capacity / Current Battery life = 3Ah / 0.012 A Battery life = 250 hours Therefore, a 3Ah battery will last 250 hours.
Testing if the previous output matches the regex 250.{,10}hours: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To calculate the current flowing through the resistor, we use Ohm's Law: V = IR 30mV = I * 2.5 ohms I = 0.03V / 2.5 ohms I = 0.012A Now, to calculate how long a 3Ah battery will last with a current draw of 0.012A: Time = Capacity / Current Time = 3Ah / 0.012A Time = 250 hours Therefore, the 3Ah battery will last for 250 hours.
Testing if the previous output matches the regex 250.{,10}hours: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To calculate the total voltage drop across the resistor, we can use Ohm's Law: V = I * R where V is the voltage drop, I is the current, and R is the resistance. Given that the voltage drop is 30mV and the resistance is 2.5 ohms, we can calculate the current flowing through the resistor: I = V / R I = 30mV / 2.5 ohms I = 0.03V / 2.5 ohms I = 0.012A Next, we need to calculate how long a 3Ah (amp-hour) battery will last with a current draw of 0.012A: Time = Capacity / Current Time = 3Ah / 0.012A Time = 250 hours Therefore, the 3Ah battery will last for 250 hours.
Testing if the previous output matches the regex 250.{,10}hours: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
To calculate how long the battery will last, we first need to determine the current flowing through the resistor. Using Ohm's Law (V = IR), we can rearrange the formula to solve for current: V = IR 30mV = I * 2.5 ohms I = 30mV / 2.5 ohms I = 0.012 A Next, we need to determine how long the battery will last with a 3Ah capacity. We can use the formula: Time = Capacity / Current Time = 3 Ah / 0.012 A Time ≈ 250 hours Therefore, the battery will last approximately 250 hours.
Testing if the previous output matches the regex 250.{,10}hours: True