Initial Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

LLM Generation

Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

Output

## Calculating Battery Life Here's how to calculate the battery life: **1. Calculate the current:** Using Ohm's Law (V = IR), we can calculate the current flowing through the resistor: 

1
I = V / R = 30 mV / 2.5 ohms = 0.012 A
**2. Calculate the battery life:** The battery life can be calculated by dividing the battery capacity (3Ah) by the current draw (0.012A): 
1
Battery life = Battery capacity / Current draw = 3 Ah / 0.012 A = 250 hours
Therefore, the 3Ah battery will last **250 hours** with a voltage drop of 30mV over a 2.5-ohm resistor.

Regex Evaluation

Testing if the previous output matches the regex 250.{,10}hours: True

Initial Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

LLM Generation

Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

Output

Ohm's Law states that $V=IR$, where: * $V$ is the voltage in volts. * $I$ is the current in amperes. * $R$ is the resistance in ohms. Hence the current flowing through the resistor is $I=V/R=30\text{ mV}/2.5\text{ }\Omega=12\text{ mA}$. The battery capacity is the amount of charge it can store, measured in ampere-hours (Ah). It tells you how long the battery can supply a certain current before it is depleted. To calculate the battery life, we use the following formula: $Battery\ life = \frac{Battery\ capacity}{Current\ draw}$ In this case, the battery capacity is 3Ah and the current draw is 12mA, which is 0.012A. Therefore, the battery life is: $Battery\ life = \frac{3Ah}{0.012A} = 250 hours$ Therefore, the answer is '***250 hours***'

Regex Evaluation

Testing if the previous output matches the regex 250.{,10}hours: True

Initial Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

LLM Generation

Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

Output

## Calculating the battery life Here's how to calculate the battery life: 1. **Calculate the current:** Using Ohm's Law (V = IR), we can find the current flowing through the resistor: I = V / R = 30mV / 2.5Ω = 0.012A = 12mA 2. **Calculate the battery life:** We can calculate the battery life by dividing the battery capacity (3Ah) by the current draw (12mA): Battery life = Battery capacity / Current draw = 3Ah / 0.012A = 250 hours Therefore, the 3Ah battery will last approximately **250 hours** with a voltage drop of 30mV across a 2.5-ohm resistor.

Regex Evaluation

Testing if the previous output matches the regex 250.{,10}hours: True