Initial Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

LLM Generation

Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

Output

To calculate the battery life, we need to find the current flowing through the resistor and then use the battery capacity to determine the time it will last. Given information: - Voltage drop across the resistor = 30 mV = 0.03 V - Resistance = 2.5 Ω - Battery capacity = 3 Ah Step 1: Calculate the current flowing through the resistor using Ohm's law. Current (I) = Voltage (V) / Resistance (R) I = 0.03 V / 2.5 Ω I = 0.012 A = 12 mA Step 2: Calculate the time the battery will last using the battery capacity and current. Time = Battery capacity / Current Time = 3 Ah / 0.012 A Time = 250 hours Therefore, the battery will last '250 hours' with the given voltage drop and resistance.

Regex Evaluation

Testing if the previous output matches the regex 250.{,10}hours: True

Initial Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

LLM Generation

Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

Output

To calculate the battery life, we need to find the current flowing through the resistor and then use the battery capacity to determine the time it will last. Given information: - Voltage drop across the resistor = 30 mV = 0.03 V - Resistance of the resistor = 2.5 ohms - Battery capacity = 3 Ah (Ampere-hours) Step 1: Find the current flowing through the resistor using Ohm's law. Current (I) = Voltage (V) / Resistance (R) I = 0.03 V / 2.5 ohms I = 0.012 A = 12 mA Step 2: Calculate the battery life using the battery capacity and the current draw. Battery life = Battery capacity / Current Battery life = 3 Ah / 0.012 A Battery life = 250 hours Therefore, the battery will last 250 hours. Answer: 250 hours

Regex Evaluation

Testing if the previous output matches the regex 250.{,10}hours: True

Initial Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

LLM Generation

Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

Output

To calculate the battery life, we need to find the current flowing through the resistor and then use the battery capacity to determine the duration. Given information: - Voltage drop across the resistor = 30 mV = 0.03 V - Resistance = 2.5 Ω - Battery capacity = 3 Ah Step 1: Find the current flowing through the resistor using Ohm's law. Current (I) = Voltage (V) / Resistance (R) I = 0.03 V / 2.5 Ω I = 0.012 A = 12 mA Step 2: Calculate the battery life using the battery capacity and current. Battery life = Battery capacity (Ah) / Current (A) Battery life = 3 Ah / 0.012 A Battery life = 250 hours Therefore, the battery will last 250 hours. Answer: 250 hours

Regex Evaluation

Testing if the previous output matches the regex 250.{,10}hours: True

Initial Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

LLM Generation

Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

Output

To find the battery life, we need to calculate the current flowing through the resistor and then use the battery capacity (3Ah) to determine the time it will last. Given information: - Voltage drop across the resistor = 30 mV = 0.03 V - Resistance = 2.5 ohms - Battery capacity = 3 Ah Step 1: Calculate the current flowing through the resistor using Ohm's law. Current (I) = Voltage (V) / Resistance (R) I = 0.03 V / 2.5 ohms I = 0.012 A = 12 mA Step 2: Calculate the battery life using the battery capacity and current. Battery life = Battery capacity (Ah) / Current (A) Battery life = 3 Ah / 0.012 A Battery life = 250 hours Therefore, the battery will last approximately 250 hours with the given load. Answer: 250 hours

Regex Evaluation

Testing if the previous output matches the regex 250.{,10}hours: True

Initial Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

LLM Generation

Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

Output

To find the battery life in hours, we need to calculate the current flowing through the resistor and then use the battery capacity to determine the time it will last. Given information: - Voltage drop across the resistor = 30 mV = 0.03 V - Resistance of the resistor = 2.5 Ω - Battery capacity = 3 Ah (Ampere-hours) Step 1: Calculate the current flowing through the resistor using Ohm's law. Current (I) = Voltage (V) / Resistance (R) I = 0.03 V / 2.5 Ω I = 0.012 A or 12 mA Step 2: Calculate the battery life in hours using the battery capacity and current. Battery life (in hours) = Battery capacity (Ah) / Current (A) Battery life = 3 Ah / 0.012 A Battery life = 250 hours Therefore, the answer is: 250 hours

Regex Evaluation

Testing if the previous output matches the regex 250.{,10}hours: True