I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
Let me solve this step by step: 1. Using Ohm's Law (V=IR), I can find the current: * I = V/R = 0.030V/2.5Ω = 0.012A (or 12mA) 2. With a 3Ah battery and a 0.012A draw: * Time = Battery Capacity/Current Draw * Time = 3Ah/0.012A = 250 hours 250 hours
Testing if the previous output matches the regex 250.{,10}hours
: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
Let me solve this step by step: 1. Using Ohm's Law (V=IR), I can find the current: * I = V/R * I = 0.030V/2.5Ω * I = 0.012A or 12mA 2. With a 3Ah battery and current of 0.012A: * Time = Battery Capacity/Current * Time = 3Ah/0.012A * Time = 250 hours 250 hours
Testing if the previous output matches the regex 250.{,10}hours
: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
Let me help you solve this step by step: 1. Using Ohm's Law: V = IR * V = 0.03V (30mV) * R = 2.5Ω * I = V/R = 0.03/2.5 = 0.012A (12mA) 2. Battery life calculation: * Battery capacity = 3Ah * Current draw = 0.012A * Time = Capacity/Current * Time = 3/0.012 = 250 hours 250 hours
Testing if the previous output matches the regex 250.{,10}hours
: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
Let me solve this step by step: 1. Using Ohm's Law (V=IR), I can find the current: * I = V/R * I = 0.030V/2.5Ω * I = 0.012A or 12mA 2. With a 3Ah battery and a current draw of 0.012A: * Time = Battery Capacity/Current Draw * Time = 3Ah/0.012A * Time = 250 hours 250 hours
Testing if the previous output matches the regex 250.{,10}hours
: True
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'
Let me solve this step by step: 1. Using Ohm's Law (V=IR), find the current: * I = V/R * I = 0.030V/2.5Ω * I = 0.012A or 12mA 2. Battery capacity is 3Ah (Ampere-hours) * Time = Capacity/Current * Time = 3Ah/0.012A * Time = 250 hours 250 hours
Testing if the previous output matches the regex 250.{,10}hours
: True