Initial Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

LLM Generation

Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

Output

Let's solve this step by step: 1) First, calculate the current through the resistor • Voltage = 30 mV = 0.030 V • Resistance = 2.5 Ω • Current = Voltage / Resistance • Current = 0.030 V / 2.5 Ω = 0.012 A 2) Battery capacity is 3 Ah (3 ampere-hours) 3) Time the battery will last: • Time = Battery Capacity / Current • Time = 3 Ah / 0.012 A = 250 hours Therefore, the battery will last 250 hours. The answer is: 250 hours

Regex Evaluation

Testing if the previous output matches the regex 250.{,10}hours: True

Initial Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

LLM Generation

Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

Output

Let's solve this step by step: 1) First, calculate the current through the resistor using Ohm's Law: V = I * R 0.030V = I * 2.5Ω I = 0.030V / 2.5Ω = 0.012A (or 12mA) 2) Battery capacity is 3Ah (ampere-hours) 3) To find battery life, divide battery capacity by current: Battery life = 3Ah / 0.012A = 250 hours Therefore, the battery will last 250 hours. The answer in the requested format is: 250 hours

Regex Evaluation

Testing if the previous output matches the regex 250.{,10}hours: True

Initial Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

LLM Generation

Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

Output

Let's solve this step by step: 1) First, calculate the current using Ohm's law: • Voltage drop = 30 mV = 0.030 V • Resistance = 2.5 Ω • Current = Voltage ÷ Resistance • Current = 0.030 V ÷ 2.5 Ω = 0.012 A (or 12 mA) 2) Battery capacity is 3 Ah (Ampere-hours) 3) To find how long the battery will last, divide battery capacity by current: • Time = Battery Capacity ÷ Current • Time = 3 Ah ÷ 0.012 A = 250 hours The answer is: 250 hours

Regex Evaluation

Testing if the previous output matches the regex 250.{,10}hours: True

Initial Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

LLM Generation

Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

Output

Let's solve this step by step: 1) First, calculate the current through the resistor using Ohm's Law: I = V/R I = 0.030V / 2.5Ω I = 0.012A (12 mA) 2) The battery capacity is 3Ah (Ampere-hours) 3) To find how long the battery will last, divide battery capacity by current: Time = 3Ah / 0.012A Time = 250 hours Therefore, the battery will last 250 hours. The answer format is: 250 hours

Regex Evaluation

Testing if the previous output matches the regex 250.{,10}hours: True

Initial Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

LLM Generation

Query

I measure a voltage drop of 30mv over a 2.5 ohm resistor. How long will a 3Ah battery last? Write your ansser 'XXX hours'

Output

Let's solve this step by step: 1) First, calculate the current through the resistor: V = I × R 0.030V = I × 2.5Ω I = 0.030V ÷ 2.5Ω I = 0.012A (or 12 mA) 2) Battery capacity is 3Ah (3 ampere-hours) 3) Time to drain the battery: Time = Battery Capacity ÷ Current Time = 3Ah ÷ 0.012A Time = 250 hours Therefore, the answer is: 250 hours

Regex Evaluation

Testing if the previous output matches the regex 250.{,10}hours: True