Write a function strides() that given an array of tokens T as numpy array, using strided trick, returns [T[0:50], T[10:60], T[20: 70] ... ]
Write a function strides() that given an array of tokens T as numpy array, using strided trick, returns [T[0:50], T[10:60], T[20: 70] ... ]
To achieve the desired functionality using NumPy's strided tricks, you can use the `numpy.lib.stride_tricks.as_strided` function. This function allows you to create a view of the array with a different shape and strides, which can be used to efficiently create overlapping windows of the array. Here's how you can implement the `strides()` function:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 | import numpy as np def strides(T, window_size=50, step_size=10): # Calculate the number of windows num_windows = (len(T) - window_size) // step_size + 1 # Use as_strided to create the overlapping windows strided_view = np.lib.stride_tricks.as_strided( T, shape=(num_windows, window_size), strides=(T.strides[0] * step_size, T.strides[0]) ) return strided_view # Example usage: T = np.arange(100) # Example array result = strides(T) print(result) |
1 2 3 4 5 | [[ 0 1 2 ... 47 48 49] [10 11 12 ... 57 58 59] [20 21 22 ... 67 68 69] ... [70 71 72 ... 97 98 99]] |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 | import numpy as np def strides(T, window_size=50, step_size=10): # Calculate the number of windows num_windows = (len(T) - window_size) // step_size + 1 # Use as_strided to create the overlapping windows strided_view = np.lib.stride_tricks.as_strided( T, shape=(num_windows, window_size), strides=(T.strides[0] * step_size, T.strides[0]) ) return strided_view |
Testing if the previous output contains the string as_strided
: True
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 | import numpy as np def strides(T, window_size=50, step_size=10): # Calculate the number of windows num_windows = (len(T) - window_size) // step_size + 1 # Use as_strided to create the overlapping windows strided_view = np.lib.stride_tricks.as_strided( T, shape=(num_windows, window_size), strides=(T.strides[0] * step_size, T.strides[0]) ) return strided_view answer = strides(np.arange(100)).shape expected = (6, 50) assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' answer = strides(np.arange(100)).sum() expected = 14850 assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' print('All tests passed') |
All tests passed
Testing if the previous output contains the string All tests passed
: True