Initial Query

Shorten this python code. Keep the name the same. 

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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

You can simplify the function by using the `dict.get` method, which reduces the need for the conditional expression. Here's the shortened version: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
**Explanation:** - **`x.get(y, -5)`**: This replaces the `x[y] if y in x else -5` conditional check. The `get` method returns the value for the specified key if it exists; otherwise, it returns `-5`. - **List Comprehensions**: The overall structure remains the same, maintaining clarity while making the code more concise. This version maintains the original functionality while being more succinct.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

You can simplify the function by using the `dict.get` method, which retrieves the value for a given key if it exists, or returns a default value (`-5` in this case) otherwise. This eliminates the need for the conditional expression `x[y] if y in x else -5`. Here’s the shortened version of your function: 

1
2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True