Initial Query

Shorten this python code. Keep the name the same. 

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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's a shorter version of the code using list comprehension and the `get()` method: 

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def foo(arr, keys):
    return [ [x.get(y, -5) for y in keys] for x in arr ]
Or, you can use a conditional expression to make it even shorter: 
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def foo(arr, keys):
    return [ [x.get(y, -5) if y in x else -5 for y in keys] for x in arr ]
The `get()` method returns the value of the item with the specified key if it exists in the dictionary, otherwise it returns the default value specified as the second argument. In this case, it returns `-5` if the key is not found in the dictionary. The conditional expression `x.get(y, -5) if y in x else -5` can be used to shorten the code further by avoiding the explicit check for `y in x`. It returns the value of `x.get(y, -5)` if `y` is in `x`, otherwise it returns `-5`. Note that the shorter code may not be as readable as the original code, so it's important to balance brevity with readability.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [ [x.get(y, -5) if y in x else -5 for y in keys] for x in arr ]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [ [x.get(y, -5) if y in x else -5 for y in keys] for x in arr ]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

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2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's a possible shorter version of the code: 

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def foo(arr, keys):
    return [list(map(lambda x: x.get(y, -5), arr)) for y in keys]
This version uses the `map` function to apply the `get` method of dictionaries to each item in `arr`. The `lambda` function is used to create an anonymous function that takes a dictionary `x` and a key `y` and returns the value of the key if it exists in the dictionary, or `-5` otherwise. The `list` function is used to convert the map output to a list. Note that this version assumes that all elements in `arr` are dictionaries. If that's not the case, you may need to modify the code to handle non-dict elements appropriately.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [list(map(lambda x: x.get(y, -5), arr)) for y in keys]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [list(map(lambda x: x.get(y, -5), arr)) for y in keys]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 11, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got [[2], [-5], [4], [-5]] instead of [[2, -5, 4, -5]]

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: False

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here is one way to shorten the code: 

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def foo(arr, keys):
  return [[x.get(y, -5) for y in keys] for x in arr]
This code uses the `get()` method of dictionaries, which allows you to specify a default value to return if the key is not found in the dictionary. This allows you to simplify the list comprehension by removing the `if` statement. Note: This code assumes that the elements of the `arr` list are dictionaries. If they are not, you may need to modify the code to handle that case. Here is another way to shorten the code using a lambda function: 
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def foo(arr, keys):
  return [list(map(lambda x, y: x.get(y, -5), x, keys)) for x in arr]
This code uses the `map()` function to apply the lambda function to each element of `arr` and `keys`. The lambda function takes two arguments: `x` and `y`. It returns the value of `x[y]` if `y` is a key in `x`, otherwise it returns `-5`. The `list()` function is used to convert the map object to a list. This code has the same assumptions as the previous code about the elements of `arr`. I hope this helps! Let me know if you have any questions.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
  return [[x.get(y, -5) for y in keys] for x in arr]

def foo(arr, keys):
  return [list(map(lambda x, y: x.get(y, -5), x, keys)) for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
  return [[x.get(y, -5) for y in keys] for x in arr]

def foo(arr, keys):
  return [list(map(lambda x, y: x.get(y, -5), x, keys)) for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 12, in <module> answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4]) ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 6, in foo return [list(map(lambda x, y: x.get(y, -5), x, keys)) for x in arr] ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 6, in <listcomp> return [list(map(lambda x, y: x.get(y, -5), x, keys)) for x in arr] ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 6, in <lambda> return [list(map(lambda x, y: x.get(y, -5), x, keys)) for x in arr] ^^^^^ AttributeError: 'int' object has no attribute 'get'

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: False

Initial Query

Shorten this python code. Keep the name the same. 

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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

You can shorten the code by using a dictionary comprehension and the `get()` method to return `-5` when the key is not found in the dictionary. Here's the shortened version: 

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def foo(arr, keys):
    return [ [x.get(y, -5) for y in keys] for x in arr ]
This version uses a dictionary comprehension to create a new dictionary for each item in `arr`, and the `get()` method to retrieve the value for each key in `keys`, or `-5` if the key is not found in the dictionary. The resulting list of dictionaries is then converted to a list of lists using a list comprehension.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [ [x.get(y, -5) for y in keys] for x in arr ]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [ [x.get(y, -5) for y in keys] for x in arr ]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's the shortened version of the code: 

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def foo(arr, keys):
    return [list(map(lambda x,y: x.get(y,-5), x, keys)) for x in arr]
The code uses the built-in `map()` function to apply a lambda function to each element in `arr` and `keys`. The lambda function takes two arguments, `x` and `y`, where `x` is a dictionary and `y` is a key. The `get()` method is used to retrieve the value associated with the key `y` in the dictionary `x`. If the key is not found, the default value of `-5` is returned. The `list()` function is used to convert the map object to a list. Note that while this code is shorter, it may not be as readable as the original code, especially for those who are not familiar with the `map()` function and lambda functions.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [list(map(lambda x,y: x.get(y,-5), x, keys)) for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [list(map(lambda x,y: x.get(y,-5), x, keys)) for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 9, in <module> answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4]) ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 3, in foo return [list(map(lambda x,y: x.get(y,-5), x, keys)) for x in arr] ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 3, in <listcomp> return [list(map(lambda x,y: x.get(y,-5), x, keys)) for x in arr] ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 3, in <lambda> return [list(map(lambda x,y: x.get(y,-5), x, keys)) for x in arr] ^^^^^ AttributeError: 'int' object has no attribute 'get'

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: False