Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

The Python code you've provided is already quite concise, as it uses list comprehension to achieve its goal. However, if you want to make it slightly shorter, you can remove the space between the function name and the parameters, and the spaces between the brackets. Here's the shortened version: 

1
2
def foo(arr,keys):
    return[[x[y] if y in x else -5 for y in keys]for x in arr]

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

1
2
def foo(arr,keys):
    return[[x[y] if y in x else -5 for y in keys]for x in arr]

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
def foo(arr,keys):
    return[[x[y] if y in x else -5 for y in keys]for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: False

Final Answer: False

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

The given Python code is already quite concise, but you can make it slightly shorter by using the `get()` method with a default value of `-5`. Here's the shortened version: 

1
2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

1
2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

The given Python code is already quite short and concise. However, you can make it slightly shorter by using the `get()` method of the dictionary, which allows you to specify a default value if the key is not found. Here's the shortened code: 

1
2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
This code assumes that the elements of `arr` are dictionaries. If they are not dictionaries but some other iterable type, you would need to keep the original code or implement a different approach.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

1
2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

The given Python code is already quite short and concise. However, if you want to shorten it further, you can use the `get()` method of the dictionary, which allows you to specify a default value. Here's how you can do it: 

1
2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
This code assumes that the elements of `arr` are dictionaries. If they are not, the original code is as short as it can be while maintaining readability.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

1
2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

The given Python code is already quite short and concise. However, you can make it slightly shorter by using the `get()` method of the dictionary, which allows you to specify a default value when a key is not found. Here's the shortened code: 

1
2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
This code assumes that the elements of `arr` are dictionaries. If they are not, you should keep the original code to avoid any errors.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

1
2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True