Initial Query

Shorten this python code. Keep the name the same. 

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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

You can shorten the code by using a conditional expression directly in the list comprehension. Here's a more concise version: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
This version uses the `get` method of dictionaries, which allows you to specify a default value (`-5` in this case) if the key is not found, making the code cleaner and easier to read.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

You can shorten the code using a more concise syntax. Here's a revised version: 

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2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
This version uses the `get` method, which allows you to specify a default value if the key is not found, making the code cleaner.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

You can shorten the code by using the `get` method of dictionaries, which allows you to specify a default value if the key is not found. Here's a more concise version: 

1
2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

You can shorten the code by using the `get` method of dictionaries, which allows you to specify a default value if the key is not found. Here's a more concise version of the function: 

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2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

You can simplify the code using the `dict.get()` method, which allows you to provide a default value if the key is not found. Here’s the shortened version: 

1
2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True