Initial Query

Shorten this python code. Keep the name the same. 

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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

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def foo(arr, keys):
  """
  Extracts values from a list of dictionaries based on specified keys,
  using a default value if a key is missing.

  Args:
    arr: A list of dictionaries.
    keys: A list of keys to look up in each dictionary.

  Returns:
    A list of lists, where each inner list contains the values
    corresponding to the keys for one dictionary in arr, or -5 if
    a key was not found.
  """
  return [[x.get(y, -5) for y in keys] for x in arr]
**Explanation of change:** The original code used a conditional expression `x[y] if y in x else -5` to handle missing keys. This was replaced with the dictionary `get()` method: `x.get(y, -5)`. * `x.get(y)` attempts to retrieve the value associated with key `y` from dictionary `x`. * If `y` is found, its value is returned. * If `y` is *not* found, the second argument provided to `get()` (`-5` in this case) is returned as the default value. This achieves the same result with slightly more concise syntax.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
  """
  Extracts values from a list of dictionaries based on specified keys,
  using a default value if a key is missing.

  Args:
    arr: A list of dictionaries.
    keys: A list of keys to look up in each dictionary.

  Returns:
    A list of lists, where each inner list contains the values
    corresponding to the keys for one dictionary in arr, or -5 if
    a key was not found.
  """
  return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
  """
  Extracts values from a list of dictionaries based on specified keys,
  using a default value if a key is missing.

  Args:
    arr: A list of dictionaries.
    keys: A list of keys to look up in each dictionary.

  Returns:
    A list of lists, where each inner list contains the values
    corresponding to the keys for one dictionary in arr, or -5 if
    a key was not found.
  """
  return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True