Initial Query

Shorten this python code. Keep the name the same. 

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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's a shorter version of the Python code while keeping the function name the same: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
This code uses the `get` method of dictionaries to retrieve the value for a given key, or return a default value (-5 in this case) if the key is not found. The `get` method is more concise than the original conditional expression.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's a shorter version of the provided Python code: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
Explanation: - The `get` method of dictionaries is used to retrieve the value of a key. If the key is not present, it returns a default value (here `-5`). - This eliminates the need for the `if-else` condition and makes the code more concise.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's a shorter version of the code: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
This version uses the `get` method of dictionaries, which allows you to specify a default value (in this case, `-5`) if the key is not found in the dictionary.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Sure, here's a shortened version of the code: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
This code achieves the same functionality as the original code, but it uses the `get()` method of dictionaries instead of checking if a key exists in the dictionary with the `if y in x` condition. The `get()` method takes two arguments: the key to look up and a default value to return if the key is not found. In this case, if the key `y` is not found in the dictionary `x`, it returns `-5`.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's a shorter version of the given Python code: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
Explanation: - Instead of using a nested list comprehension with an `if-else` condition, we can use the `dict.get()` method to retrieve the value for a given key from each dictionary in the list `arr`. - The `dict.get(key, default_value)` method returns the value associated with the `key` if it exists in the dictionary, otherwise it returns the `default_value` (which is `-5` in this case). - This code achieves the same functionality as the original code but in a more concise way.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True