Initial Query

Shorten this python code. Keep the name the same. 

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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's a shorter version of the code with the same functionality: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
In this version, we use the `dict.get()` method to retrieve the value associated with the key `y` from each dictionary `x` in the `arr` list. If the key `y` is not present in the dictionary `x`, the `get()` method returns the default value `-5` instead of raising a `KeyError`. The rest of the code remains the same, using a list comprehension to iterate over `arr` and another list comprehension to iterate over `keys` and construct the resulting list of lists.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's a shortened version of the Python code with the same functionality: 

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2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
In this version, we use the `get()` method of dictionaries to retrieve the value for each key `y` in `keys`. If the key is not found in the dictionary `x`, the `get()` method returns the default value `-5`. This achieves the same result as the original code but in a more concise manner by utilizing the `get()` method instead of the conditional expression `x[y] if y in x else -5`.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's the shortened version of the code with the same functionality: 

1
2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
In this version, we use the `get()` method of dictionaries to retrieve the value for each key `y` in `keys`. If the key doesn't exist in the dictionary `x`, it returns the default value of `-5` instead of using the `if-else` condition. This achieves the same result as the original code but in a more concise manner.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's the shortened version of the code, keeping the function name the same: 

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2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
In this version, we use the `get()` method of dictionaries to retrieve the value for each key `y` in `keys`. If the key is not present in the dictionary `x`, the `get()` method returns the default value `-5` instead of raising a `KeyError`. This achieves the same functionality as the original code but in a more concise manner.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's the shortened version of the code with the same functionality: 

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2
def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
Explanation: - Instead of using the conditional expression `x[y] if y in x else -5`, we can use the `dict.get()` method to retrieve the value for key `y` from dictionary `x`. If the key is not found, it returns the default value `-5`. - The rest of the code remains the same, using a list comprehension within a list comprehension to iterate over `arr` and `keys`. This shortens the code by replacing the conditional expression with the more concise `dict.get()` method.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True