Initial Query

Shorten this python code. Keep the name the same. 

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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

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def foo(arr,keys): return [[x.get(y,-5) for y in keys] for x in arr]
This shorter version uses dict.get() method, which returns a default value (-5) if the key doesn't exist, instead of using the if-else conditional.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr,keys): return [[x.get(y,-5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr,keys): return [[x.get(y,-5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's a shorter version using map and operator.itemgetter: 

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def foo(arr,keys):return[[d.get(k,-5)for k in keys]for d in arr]
This version does the same thing but uses dict.get() to handle missing keys, eliminating the if-else condition.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr,keys):return[[d.get(k,-5)for k in keys]for d in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr,keys):return[[d.get(k,-5)for k in keys]for d in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Since this code is already quite concise using list comprehension, there isn't much room for shortening while keeping the same functionality. However, here's the same code slightly shortened: 

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foo=lambda a,k:[[x.get(y,-5)for y in k]for x in a]
This version: - Uses lambda instead of def - Uses dict.get() with default value instead of if-else - Uses shorter parameter names - Removes spaces Both versions do exactly the same thing, but the original version is more readable and generally preferred in practice.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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foo=lambda a,k:[[x.get(y,-5)for y in k]for x in a]

Run Code Interpreter

Running the following program: 

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foo=lambda a,k:[[x.get(y,-5)for y in k]for x in a]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

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def foo(arr, keys): return [[x.get(y,-5) for y in keys] for x in arr]
This version uses dict.get() method which returns a default value (-5) if the key doesn't exist, making it more concise.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

1
def foo(arr, keys): return [[x.get(y,-5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys): return [[x.get(y,-5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

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def foo(arr,keys): return [[x.get(y,-5) for y in keys] for x in arr]
The dict.get() method achieves the same thing more concisely by checking if the key exists and returning the default value (-5) if it doesn't.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr,keys): return [[x.get(y,-5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr,keys): return [[x.get(y,-5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True