Initial Query

Shorten this python code. Keep the name the same. 

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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

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def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's a shortened version of the code that maintains the same functionality: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
This version uses the `.get()` method to simplify the logic. If the key doesn't exist in the dictionary, it returns the default value `-5`.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's a shortened version of the code: 

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def foo(arr, keys): return [[x.get(y, -5) for y in keys] for x in arr]
This version uses the `.get()` method, which allows you to specify a default value (-5) if the key is not found. It achieves the same functionality as the original code but in a more concise manner.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys): return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys): return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's a shortened version of the code: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
The changes: - Used `.get()` method with a default value of -5, which eliminates the need for an explicit `if y in x` check - Keeps the same function name and overall list comprehension structure - Maintains the original functionality of returning a list of lists with values from the keys or -5 if the key is not present

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's a shortened version of the code: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
The changes: - Used `.get()` method instead of checking `if y in x` - Removed explicit `if` condition - Kept the same function name and logic - More concise and Pythonic The function works the same way: - Takes an array of dictionaries `arr` and a list of `keys` - Returns a list of lists where each inner list contains values for the given keys - If a key is not in a dictionary, it returns -5 as the default value

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True

Initial Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

LLM Generation

Query

Shorten this python code. Keep the name the same. 

1
2
def foo(arr, keys):
    return [[x[y] if y in x else -5 for y in keys] for x in arr]

Output

Here's a shortened version of the code: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]
The changes: 1. Replaced the conditional list comprehension `x[y] if y in x else -5` with the dictionary `.get()` method, which does the same thing more concisely. 2. The functionality remains identical: it returns a list of lists where each inner list contains values from the corresponding dictionary in `arr`, using the keys specified in `keys`. If a key is not present, it uses -5 as the default value.

Check if all of the following conditions are true:

Extract Code

I extracted the following code from that output: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]

Run Code Interpreter

Running the following program: 

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def foo(arr, keys):
    return [[x.get(y, -5) for y in keys] for x in arr]





answer = foo([{1: 2, 3: 4, 5: 6}], [1, 2, 3, 4])
expected = [[2, -5, 4, -5]]
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Substring Evaluation

Testing if the previous output contains the string .get: True

Final Answer: True