Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the function named `count`. 

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int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the function named `count`. 

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int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

Output

int count(){int c=0,i,r,j,p;unsigned long long a,b;for(i=0;i<1<<16;i++){a=((i&15)<<9)|((i&240)<<13)|((i&0xf00)<<17)|((i&0xf000)<<21);b=a;for(r=1;r<7;r++)for(j=1;j<7;j++){p=r*8+j;if((a>>p&1)&&!(a>>(p-8)&1)&&!(a>>(p-1)&1)&&!(a>>(p+8)&1)&&!(a>>(p+1)&1))a&=~(1ULL<<p);}c+=a==b;}return c;} --- Explanation: • We compress the original function by dropping extra whitespace and using single‐letter names. • The board is built by “laying out” four nibbles (using bit–masks 15, 240, 0xf00, 0xf000) into a 64–bit integer at offsets 9,13,17,21. • For each inner cell (rows 1 to 6, columns 1 to 6 in an 8×8 board) we check if the cell is 1 while all its four neighbors (top, left, bottom, right) are 0. If so, we “remove” it by zeroing the bit. • If no change occurred (a equals its initial copy b) we increment the count. This version is well under 300 bytes (spaces aren’t counted) and meets the criteria.

Extract Code

I extracted the following code from that output: 

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#include <stdio.h>
#include <stdlib.h>

int count(){int c=0,i,r,j,p;unsigned long long a,b;for(i=0;i<1<<16;i++){a=((i&15)<<9)|((i&240)<<13)|((i&0xf00)<<17)|((i&0xf000)<<21);b=a;for(r=1;r<7;r++)for(j=1;j<7;j++){p=r*8+j;if((a>>p&1)&&!(a>>(p-8)&1)&&!(a>>(p-1)&1)&&!(a>>(p+8)&1)&&!(a>>(p+1)&1))a&=~(1ULL<<p);}c+=a==b;}return c;}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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#include <stdio.h>
#include <stdlib.h>

int count(){int c=0,i,r,j,p;unsigned long long a,b;for(i=0;i<1<<16;i++){a=((i&15)<<9)|((i&240)<<13)|((i&0xf00)<<17)|((i&0xf000)<<21);b=a;for(r=1;r<7;r++)for(j=1;j<7;j++){p=r*8+j;if((a>>p&1)&&!(a>>(p-8)&1)&&!(a>>(p-1)&1)&&!(a>>(p+8)&1)&&!(a>>(p+1)&1))a&=~(1ULL<<p);}c+=a==b;}return c;}


#include<stdio.h>
#include<stdlib.h>

int main() {


int answer = count();
int expected = 27488;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

PyFunc

Resulting in output: False

Final Answer: False

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the function named `count`. 

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int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the function named `count`. 

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int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

Output

#include <stdint.h> int count(){int c=0,n,i,j;for(n=0;n<65536;n++){unsigned long long a=((n&15)<<9)|((n&240)<<13)|((n&3840)<<17)|((n&61440)<<21),b=a;for(i=1;i<7;i++)for(j=1;j<7;j++){int p=i*8+j;if((a>>p)&1&&!(((a>>(p-8))|(a>>(p-1))|(a>>(p+1))|(a>>(p+8)))&1))a&=~(1ULL<<p);}c+=a==b;}return c;} // Explanation: // For each 16-bit number n (0..65535), we construct a 64-bit board 'a' by mapping its four 4‐bit nibbles // into specific offsets on an 8×8 grid. We then copy 'a' into b and iterate over the inner 6×6 cells (i=1..6, j=1..6). // For each cell p=i*8+j that is 1, if all its four immediate neighbors (above, below, left, right) // are 0 then we clear that bit in a. Finally we increment c if the transformed board a is equal to the original b.

Extract Code

I extracted the following code from that output: 

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#include <stdint.h>
int count(){int c=0,n,i,j;for(n=0;n<65536;n++){unsigned long long a=((n&15)<<9)|((n&240)<<13)|((n&3840)<<17)|((n&61440)<<21),b=a;for(i=1;i<7;i++)for(j=1;j<7;j++){int p=i*8+j;if((a>>p)&1&&!(((a>>(p-8))|(a>>(p-1))|(a>>(p+1))|(a>>(p+8)))&1))a&=~(1ULL<<p);}c+=a==b;}return c;}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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#include <stdint.h>
int count(){int c=0,n,i,j;for(n=0;n<65536;n++){unsigned long long a=((n&15)<<9)|((n&240)<<13)|((n&3840)<<17)|((n&61440)<<21),b=a;for(i=1;i<7;i++)for(j=1;j<7;j++){int p=i*8+j;if((a>>p)&1&&!(((a>>(p-8))|(a>>(p-1))|(a>>(p+1))|(a>>(p+8)))&1))a&=~(1ULL<<p);}c+=a==b;}return c;}


#include<stdio.h>
#include<stdlib.h>

int main() {


int answer = count();
int expected = 27488;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

PyFunc

Resulting in output: True

Final Answer: True