Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the function named `count`. 

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int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the function named `count`. 

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int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

Output

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int count(){
  int c=0;
  for(int i=0;i<65536;i++){
    long long a=((i&15)<<9)|((i&240)<<13)|((i&3840)<<17)|((i&61440)<<21);
    long long t=a;
    for(int j=1;j<7;j++)
      for(int k=1;k<7;k++){
        int p=j*8+k,s=0;
        s+=!!(t>>(p-8)&1)+!!(t>>(p-1)&1)+!!(t>>(p+8)&1)+!!(t>>(p+1)&1);
        if(!s&&t>>p&1)a&=~(1LL<<p);
      }
    c+=(t==a);
  }
  return c;
}

Extract Code

I extracted the following code from that output: 

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int count(){
  int c=0;
  for(int i=0;i<65536;i++){
    long long a=((i&15)<<9)|((i&240)<<13)|((i&3840)<<17)|((i&61440)<<21);
    long long t=a;
    for(int j=1;j<7;j++)
      for(int k=1;k<7;k++){
        int p=j*8+k,s=0;
        s+=!!(t>>(p-8)&1)+!!(t>>(p-1)&1)+!!(t>>(p+8)&1)+!!(t>>(p+1)&1);
        if(!s&&t>>p&1)a&=~(1LL<<p);
      }
    c+=(t==a);
  }
  return c;
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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int count(){
  int c=0;
  for(int i=0;i<65536;i++){
    long long a=((i&15)<<9)|((i&240)<<13)|((i&3840)<<17)|((i&61440)<<21);
    long long t=a;
    for(int j=1;j<7;j++)
      for(int k=1;k<7;k++){
        int p=j*8+k,s=0;
        s+=!!(t>>(p-8)&1)+!!(t>>(p-1)&1)+!!(t>>(p+8)&1)+!!(t>>(p+1)&1);
        if(!s&&t>>p&1)a&=~(1LL<<p);
      }
    c+=(t==a);
  }
  return c;
}



#include<stdio.h>
#include<stdlib.h>

int main() {


int answer = count();
int expected = 27488;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

PyFunc

Resulting in output: True

Final Answer: True

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the function named `count`. 

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int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the function named `count`. 

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int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

Output

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int count(){
  int c=0;
  for(int i=0;i<65536;i++){
    long long a=((i&15)<<9)|((i&240)<<13)|((i&3840)<<17)|((i&61440)<<21);
    long long t=a;
    for(int j=1;j<7;j++)
      for(int k=1;k<7;k++){
        int p=j*8+k,s=!!(t>>(p-8)&1)+!!(t>>(p-1)&1)+!!(t>>(p+8)&1)+!!(t>>(p+1)&1);
        if(s==0&&!!(t>>p&1))a&=~(1LL<<p);
      }
    c+=(t==a);
  }
  return c;
}

Extract Code

I extracted the following code from that output: 

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int count(){
  int c=0;
  for(int i=0;i<65536;i++){
    long long a=((i&15)<<9)|((i&240)<<13)|((i&3840)<<17)|((i&61440)<<21);
    long long t=a;
    for(int j=1;j<7;j++)
      for(int k=1;k<7;k++){
        int p=j*8+k,s=!!(t>>(p-8)&1)+!!(t>>(p-1)&1)+!!(t>>(p+8)&1)+!!(t>>(p+1)&1);
        if(s==0&&!!(t>>p&1))a&=~(1LL<<p);
      }
    c+=(t==a);
  }
  return c;
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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int count(){
  int c=0;
  for(int i=0;i<65536;i++){
    long long a=((i&15)<<9)|((i&240)<<13)|((i&3840)<<17)|((i&61440)<<21);
    long long t=a;
    for(int j=1;j<7;j++)
      for(int k=1;k<7;k++){
        int p=j*8+k,s=!!(t>>(p-8)&1)+!!(t>>(p-1)&1)+!!(t>>(p+8)&1)+!!(t>>(p+1)&1);
        if(s==0&&!!(t>>p&1))a&=~(1LL<<p);
      }
    c+=(t==a);
  }
  return c;
}



#include<stdio.h>
#include<stdlib.h>

int main() {


int answer = count();
int expected = 27488;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

PyFunc

Resulting in output: True

Final Answer: True

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the function named `count`. 

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int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the function named `count`. 

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int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

Output

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int count(){
  int c=0;
  for(int i=0;i<65536;i++){
    long long a=((i&15)<<9)|((i&240)<<13)|((i&3840)<<17)|((i&61440)<<21);
    long long t=a;
    for(int j=1;j<7;j++)
      for(int k=1;k<7;k++){
        int p=j*8+k,s=!!(t>>(p-8)&1)+!!(t>>(p-1)&1)+!!(t>>(p+8)&1)+!!(t>>(p+1)&1);
        if(s==0&&!!(t>>p&1))a&=~(1LL<<p);
      }
    c+=(t==a);
  }
  return c;
}

Extract Code

I extracted the following code from that output: 

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int count(){
  int c=0;
  for(int i=0;i<65536;i++){
    long long a=((i&15)<<9)|((i&240)<<13)|((i&3840)<<17)|((i&61440)<<21);
    long long t=a;
    for(int j=1;j<7;j++)
      for(int k=1;k<7;k++){
        int p=j*8+k,s=!!(t>>(p-8)&1)+!!(t>>(p-1)&1)+!!(t>>(p+8)&1)+!!(t>>(p+1)&1);
        if(s==0&&!!(t>>p&1))a&=~(1LL<<p);
      }
    c+=(t==a);
  }
  return c;
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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int count(){
  int c=0;
  for(int i=0;i<65536;i++){
    long long a=((i&15)<<9)|((i&240)<<13)|((i&3840)<<17)|((i&61440)<<21);
    long long t=a;
    for(int j=1;j<7;j++)
      for(int k=1;k<7;k++){
        int p=j*8+k,s=!!(t>>(p-8)&1)+!!(t>>(p-1)&1)+!!(t>>(p+8)&1)+!!(t>>(p+1)&1);
        if(s==0&&!!(t>>p&1))a&=~(1LL<<p);
      }
    c+=(t==a);
  }
  return c;
}



#include<stdio.h>
#include<stdlib.h>

int main() {


int answer = count();
int expected = 27488;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

PyFunc

Resulting in output: True

Final Answer: True

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the function named `count`. 

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int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the function named `count`. 

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int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

Output

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int count(){
  int c=0;
  for(int i=0;i<65536;i++){
    long long a=((i&15)<<9)|((i&240)<<13)|((i&3840)<<17)|((i&61440)<<21);
    long long t=a;
    for(int j=1;j<7;j++)
      for(int k=1;k<7;k++){
        int p=j*8+k,s=!!(t>>(p-8)&1)+!!(t>>(p-1)&1)+!!(t>>(p+8)&1)+!!(t>>(p+1)&1);
        if(s==0&&t>>p&1)a&=~(1LL<<p);
      }
    c+=(t==a);
  }
  return c;
}

Extract Code

I extracted the following code from that output: 

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int count(){
  int c=0;
  for(int i=0;i<65536;i++){
    long long a=((i&15)<<9)|((i&240)<<13)|((i&3840)<<17)|((i&61440)<<21);
    long long t=a;
    for(int j=1;j<7;j++)
      for(int k=1;k<7;k++){
        int p=j*8+k,s=!!(t>>(p-8)&1)+!!(t>>(p-1)&1)+!!(t>>(p+8)&1)+!!(t>>(p+1)&1);
        if(s==0&&t>>p&1)a&=~(1LL<<p);
      }
    c+=(t==a);
  }
  return c;
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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int count(){
  int c=0;
  for(int i=0;i<65536;i++){
    long long a=((i&15)<<9)|((i&240)<<13)|((i&3840)<<17)|((i&61440)<<21);
    long long t=a;
    for(int j=1;j<7;j++)
      for(int k=1;k<7;k++){
        int p=j*8+k,s=!!(t>>(p-8)&1)+!!(t>>(p-1)&1)+!!(t>>(p+8)&1)+!!(t>>(p+1)&1);
        if(s==0&&t>>p&1)a&=~(1LL<<p);
      }
    c+=(t==a);
  }
  return c;
}



#include<stdio.h>
#include<stdlib.h>

int main() {


int answer = count();
int expected = 27488;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

PyFunc

Resulting in output: True

Final Answer: True

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the function named `count`. 

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int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the function named `count`. 

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int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

Output

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int count(){
  int c=0;
  for(int i=0;i<65536;i++){
    long long a=((i&15)<<9)|((i&240)<<13)|((i&3840)<<17)|((i&61440)<<21);
    long long t=a;
    for(int j=1;j<7;j++)
      for(int k=1;k<7;k++){
        int p=j*8+k,s=!!(t>>(p-8)&1)+!!(t>>(p-1)&1)+!!(t>>(p+8)&1)+!!(t>>(p+1)&1);
        if(s==0&&!!(t>>p&1))a&=~(1LL<<p);
      }
    c+=(t==a);
  }
  return c;
}

Extract Code

I extracted the following code from that output: 

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int count(){
  int c=0;
  for(int i=0;i<65536;i++){
    long long a=((i&15)<<9)|((i&240)<<13)|((i&3840)<<17)|((i&61440)<<21);
    long long t=a;
    for(int j=1;j<7;j++)
      for(int k=1;k<7;k++){
        int p=j*8+k,s=!!(t>>(p-8)&1)+!!(t>>(p-1)&1)+!!(t>>(p+8)&1)+!!(t>>(p+1)&1);
        if(s==0&&!!(t>>p&1))a&=~(1LL<<p);
      }
    c+=(t==a);
  }
  return c;
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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int count(){
  int c=0;
  for(int i=0;i<65536;i++){
    long long a=((i&15)<<9)|((i&240)<<13)|((i&3840)<<17)|((i&61440)<<21);
    long long t=a;
    for(int j=1;j<7;j++)
      for(int k=1;k<7;k++){
        int p=j*8+k,s=!!(t>>(p-8)&1)+!!(t>>(p-1)&1)+!!(t>>(p+8)&1)+!!(t>>(p+1)&1);
        if(s==0&&!!(t>>p&1))a&=~(1LL<<p);
      }
    c+=(t==a);
  }
  return c;
}



#include<stdio.h>
#include<stdlib.h>

int main() {


int answer = count();
int expected = 27488;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

PyFunc

Resulting in output: True

Final Answer: True