Initial Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the function named `count`. 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the function named `count`. 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

Output

1
int count(){int R=8,C=8,c=0;for(int i=0;i<1<<16;i++){long long unsigned int a=((i&0xf)<<9)|((i&0xf0)<<(9+8-4))|((i&0xf00)<<(9+8-4+8-4))|((i&0xf000)<<(9+8-4+8-4+8-4)),n=a;for(int i=1;i<R-1;i++)for(int j=1;j<C-1;j++){int p=i*C+j,tp=(i-1)*C+j,lp=i*C+(j-1),bp=(i+1)*C+j,rp=i*C+(j+1),ce=(n>>p)&1,tt=(n>>tp)&1,lt=(n>>lp)&1,bt=(n>>bp)&1,rt=(n>>rp)&1,s=tt+lt+bt+rt;if(s==0&&ce==1)a&=~(1ULL<<p);}c+=(a==n);}return c;}

Extract Code

I extracted the following code from that output: 

1
int count(){int R=8,C=8,c=0;for(int i=0;i<1<<16;i++){long long unsigned int a=((i&0xf)<<9)|((i&0xf0)<<(9+8-4))|((i&0xf00)<<(9+8-4+8-4))|((i&0xf000)<<(9+8-4+8-4+8-4)),n=a;for(int i=1;i<R-1;i++)for(int j=1;j<C-1;j++){int p=i*C+j,tp=(i-1)*C+j,lp=i*C+(j-1),bp=(i+1)*C+j,rp=i*C+(j+1),ce=(n>>p)&1,tt=(n>>tp)&1,lt=(n>>lp)&1,bt=(n>>bp)&1,rt=(n>>rp)&1,s=tt+lt+bt+rt;if(s==0&&ce==1)a&=~(1ULL<<p);}c+=(a==n);}return c;}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
int count(){int R=8,C=8,c=0;for(int i=0;i<1<<16;i++){long long unsigned int a=((i&0xf)<<9)|((i&0xf0)<<(9+8-4))|((i&0xf00)<<(9+8-4+8-4))|((i&0xf000)<<(9+8-4+8-4+8-4)),n=a;for(int i=1;i<R-1;i++)for(int j=1;j<C-1;j++){int p=i*C+j,tp=(i-1)*C+j,lp=i*C+(j-1),bp=(i+1)*C+j,rp=i*C+(j+1),ce=(n>>p)&1,tt=(n>>tp)&1,lt=(n>>lp)&1,bt=(n>>bp)&1,rt=(n>>rp)&1,s=tt+lt+bt+rt;if(s==0&&ce==1)a&=~(1ULL<<p);}c+=(a==n);}return c;}



#include<stdio.h>
#include<stdlib.h>

int main() {


int answer = count();
int expected = 27488;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

PyFunc

Resulting in output: False

Final Answer: False

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the function named `count`. 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the function named `count`. 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

Output

1
int count(){int r=8,c=8,n=0;for(int i=0;i<1<<16;i++){long long unsigned int a=((i&0xf)<<9)|((i&0xf0)<<(9+8-4))|((i&0xf00)<<(9+8-4+8-4))|((i&0xf000)<<(9+8-4+8-4+8-4)),b=a;for(int i=1;i<r-1;i++){for(int j=1;j<c-1;j++){int p=i*c+j,t=(i-1)*c+j,l=i*c+j-1,b=(i+1)*c+j,r=i*c+j+1,ce=(b>>p)&1,to=(b>>t)&1,le=(b>>l)&1,bo=(b>>b)&1,ri=(b>>r)&1,s=to+le+bo+ri;if(s==0&&ce==1){a&=~(1ULL<<p);}}}n+=(b==a);}return n;}

Extract Code

I extracted the following code from that output: 

1
int count(){int r=8,c=8,n=0;for(int i=0;i<1<<16;i++){long long unsigned int a=((i&0xf)<<9)|((i&0xf0)<<(9+8-4))|((i&0xf00)<<(9+8-4+8-4))|((i&0xf000)<<(9+8-4+8-4+8-4)),b=a;for(int i=1;i<r-1;i++){for(int j=1;j<c-1;j++){int p=i*c+j,t=(i-1)*c+j,l=i*c+j-1,b=(i+1)*c+j,r=i*c+j+1,ce=(b>>p)&1,to=(b>>t)&1,le=(b>>l)&1,bo=(b>>b)&1,ri=(b>>r)&1,s=to+le+bo+ri;if(s==0&&ce==1){a&=~(1ULL<<p);}}}n+=(b==a);}return n;}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
int count(){int r=8,c=8,n=0;for(int i=0;i<1<<16;i++){long long unsigned int a=((i&0xf)<<9)|((i&0xf0)<<(9+8-4))|((i&0xf00)<<(9+8-4+8-4))|((i&0xf000)<<(9+8-4+8-4+8-4)),b=a;for(int i=1;i<r-1;i++){for(int j=1;j<c-1;j++){int p=i*c+j,t=(i-1)*c+j,l=i*c+j-1,b=(i+1)*c+j,r=i*c+j+1,ce=(b>>p)&1,to=(b>>t)&1,le=(b>>l)&1,bo=(b>>b)&1,ri=(b>>r)&1,s=to+le+bo+ri;if(s==0&&ce==1){a&=~(1ULL<<p);}}}n+=(b==a);}return n;}



#include<stdio.h>
#include<stdlib.h>

int main() {


int answer = count();
int expected = 27488;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: Wrong answer; got 65536 instead of 27488.

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

PyFunc

Resulting in output: False

Final Answer: False

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the function named `count`. 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the function named `count`. 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

Output

1
int count(){int R=8,C=8,c=0;for(int i=0;i<1<<16;i++){long long unsigned a=((i&0xf)<<9)|((i&0xf0)<<(9+8-4))|((i&0xf00)<<(9+8-4+8-4))|((i&0xf000)<<(9+8-4+8-4+8-4)),I=a,t=a;for(int i=1;i<R-1;i++){for(int j=1;j<C-1;j++){int p=i*C+j,t=(t>>p)&1,T=(t>>(p-C))&1,L=(t>>(p-1))&1,B=(t>>(p+C))&1,R=(t>>(p+1))&1,S=T+L+B+R;if(S==0&&t==1)a&=~(1ULL<<p);}}c+=(I==a);}return c;}

Extract Code

I extracted the following code from that output: 

1
int count(){int R=8,C=8,c=0;for(int i=0;i<1<<16;i++){long long unsigned a=((i&0xf)<<9)|((i&0xf0)<<(9+8-4))|((i&0xf00)<<(9+8-4+8-4))|((i&0xf000)<<(9+8-4+8-4+8-4)),I=a,t=a;for(int i=1;i<R-1;i++){for(int j=1;j<C-1;j++){int p=i*C+j,t=(t>>p)&1,T=(t>>(p-C))&1,L=(t>>(p-1))&1,B=(t>>(p+C))&1,R=(t>>(p+1))&1,S=T+L+B+R;if(S==0&&t==1)a&=~(1ULL<<p);}}c+=(I==a);}return c;}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
int count(){int R=8,C=8,c=0;for(int i=0;i<1<<16;i++){long long unsigned a=((i&0xf)<<9)|((i&0xf0)<<(9+8-4))|((i&0xf00)<<(9+8-4+8-4))|((i&0xf000)<<(9+8-4+8-4+8-4)),I=a,t=a;for(int i=1;i<R-1;i++){for(int j=1;j<C-1;j++){int p=i*C+j,t=(t>>p)&1,T=(t>>(p-C))&1,L=(t>>(p-1))&1,B=(t>>(p+C))&1,R=(t>>(p+1))&1,S=T+L+B+R;if(S==0&&t==1)a&=~(1ULL<<p);}}c+=(I==a);}return c;}



#include<stdio.h>
#include<stdlib.h>

int main() {


int answer = count();
int expected = 27488;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: Wrong answer; got 65536 instead of 27488.

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

PyFunc

Resulting in output: False

Final Answer: False

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the function named `count`. 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the function named `count`. 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

Output

1
int count(){int r=8,c=8,C=0;for(int i=0;i<1<<16;i++){long long unsigned int a=((i&0xf)<<9)|((i&0xf0)<<(9+8-4))|((i&0xf00)<<(9+8-4+8-4))|((i&0xf000)<<(9+8-4+8-4+8-4));long long unsigned int b=a;long long unsigned int t=a;for(int i=1;i<r-1;i++){for(int j=1;j<c-1;j++){int p=i*c+j,intop=(i-1)*c+j,le=(t>>p)&1,ta=(t>>intop)&1,lf=(t>>((i*c)+(j-1)))&1,bo=(t>>((i+1)*c+j))&1,ri=(t>>((i*c)+(j+1)))&1,s=ta+lf+bo+ri;if(s==0&&le==1){a&=~(1ULL<<p);}}}C+=(b==a);}return C;}

Extract Code

I extracted the following code from that output: 

1
int count(){int r=8,c=8,C=0;for(int i=0;i<1<<16;i++){long long unsigned int a=((i&0xf)<<9)|((i&0xf0)<<(9+8-4))|((i&0xf00)<<(9+8-4+8-4))|((i&0xf000)<<(9+8-4+8-4+8-4));long long unsigned int b=a;long long unsigned int t=a;for(int i=1;i<r-1;i++){for(int j=1;j<c-1;j++){int p=i*c+j,intop=(i-1)*c+j,le=(t>>p)&1,ta=(t>>intop)&1,lf=(t>>((i*c)+(j-1)))&1,bo=(t>>((i+1)*c+j))&1,ri=(t>>((i*c)+(j+1)))&1,s=ta+lf+bo+ri;if(s==0&&le==1){a&=~(1ULL<<p);}}}C+=(b==a);}return C;}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
int count(){int r=8,c=8,C=0;for(int i=0;i<1<<16;i++){long long unsigned int a=((i&0xf)<<9)|((i&0xf0)<<(9+8-4))|((i&0xf00)<<(9+8-4+8-4))|((i&0xf000)<<(9+8-4+8-4+8-4));long long unsigned int b=a;long long unsigned int t=a;for(int i=1;i<r-1;i++){for(int j=1;j<c-1;j++){int p=i*c+j,intop=(i-1)*c+j,le=(t>>p)&1,ta=(t>>intop)&1,lf=(t>>((i*c)+(j-1)))&1,bo=(t>>((i+1)*c+j))&1,ri=(t>>((i*c)+(j+1)))&1,s=ta+lf+bo+ri;if(s==0&&le==1){a&=~(1ULL<<p);}}}C+=(b==a);}return C;}



#include<stdio.h>
#include<stdlib.h>

int main() {


int answer = count();
int expected = 27488;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

PyFunc

Resulting in output: False

Final Answer: False

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the function named `count`. 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the function named `count`. 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
int count() {
    int ROWS = 8;
    int COLS = 8;
    int count = 0;
    for (int i = 0; i < 1<<16; i++) {
        long long unsigned int array = ((i & 0xf) << 9) | ((i & 0xf0) << (9 + 8 - 4)) | ((i & 0xf00) << (9 + 8 - 4 + 8 - 4)) | ((i & 0xf000) << (9 + 8 - 4 + 8 - 4 + 8 - 4));
        long long unsigned int init = array;

    long long unsigned int temp = array;

    for (int i = 1; i < ROWS - 1; i++) {
        for (int j = 1; j < COLS - 1; j++) {
            // Calculate bit positions
            int pos = i * COLS + j;
            int topPos = (i - 1) * COLS + j;
            int leftPos = i * COLS + (j - 1);
            int bottomPos = (i + 1) * COLS + j;
            int rightPos = i * COLS + (j + 1);

            // Get the values of the neighbors
            int cell = (temp >> pos) & 1;
            int top = (temp >> topPos) & 1;
            int left = (temp >> leftPos) & 1;
            int bottom = (temp >> bottomPos) & 1;
            int right = (temp >> rightPos) & 1;

            // Sum the values of the neighbors
            int sum = top + left + bottom + right;

            // Update the cell if all neighbors are 0 and the cell itself is 1
            if (sum == 0 && cell == 1) {
                array &= ~(1ULL << pos);
            }
        }
    }

        count += (init == array);
    }
    return count;
}

Output

1
int count(){int R=8,C=8,c=0;for(int i=0;i<1<<16;i++){long long unsigned int a=((i&0xf)<<9)|((i&0xf0)<<13)|((i&0xf00)<<17)|((i&0xf000)<<21),t=a;for(int i=1;i<R-1;i++){for(int j=1;j<C-1;j++){int p=i*C+j,tp=(i-1)*C+j,lp=i*C+(j-1),bp=(i+1)*C+j,rp=i*C+(j+1),ce=(t>>p)&1,to=(t>>tp)&1,le=(t>>lp)&1,bo=(t>>bp)&1,ri=(t>>rp)&1,s=to+le+bo+ri;if(s==0&&ce==1){a&=~(1ULL<<p);}}}c+=(a==t);}return c;}

Extract Code

I extracted the following code from that output: 

1
int count(){int R=8,C=8,c=0;for(int i=0;i<1<<16;i++){long long unsigned int a=((i&0xf)<<9)|((i&0xf0)<<13)|((i&0xf00)<<17)|((i&0xf000)<<21),t=a;for(int i=1;i<R-1;i++){for(int j=1;j<C-1;j++){int p=i*C+j,tp=(i-1)*C+j,lp=i*C+(j-1),bp=(i+1)*C+j,rp=i*C+(j+1),ce=(t>>p)&1,to=(t>>tp)&1,le=(t>>lp)&1,bo=(t>>bp)&1,ri=(t>>rp)&1,s=to+le+bo+ri;if(s==0&&ce==1){a&=~(1ULL<<p);}}}c+=(a==t);}return c;}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
int count(){int R=8,C=8,c=0;for(int i=0;i<1<<16;i++){long long unsigned int a=((i&0xf)<<9)|((i&0xf0)<<13)|((i&0xf00)<<17)|((i&0xf000)<<21),t=a;for(int i=1;i<R-1;i++){for(int j=1;j<C-1;j++){int p=i*C+j,tp=(i-1)*C+j,lp=i*C+(j-1),bp=(i+1)*C+j,rp=i*C+(j+1),ce=(t>>p)&1,to=(t>>tp)&1,le=(t>>lp)&1,bo=(t>>bp)&1,ri=(t>>rp)&1,s=to+le+bo+ri;if(s==0&&ce==1){a&=~(1ULL<<p);}}}c+=(a==t);}return c;}



#include<stdio.h>
#include<stdlib.h>

int main() {


int answer = count();
int expected = 27488;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

PyFunc

Resulting in output: False

Final Answer: False