Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

Output

Here's a compact version of the `stepper` function using a lookup table to minimize the number of `digitalWrite` calls. This approach reduces the overall byte count by encoding the pin states in an array and using bitwise operations to set each pin. 

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void stepper(int xw){
    const unsigned char s[]={1,3,2,6,4,12,8,9};
    unsigned char S=0;
    while(xw--){
        digitalWrite(1,s[S]&1);
        digitalWrite(2,(s[S]>>1)&1);
        digitalWrite(3,(s[S]>>2)&1);
        digitalWrite(4,(s[S]>>3)&1);
        S=(S+1)&7;
    }
}
**Explanation:** 1. **Lookup Table (`s`):** - Encodes the state of all four pins for each step in an 8-step cycle. - Each element in the array represents the states of pins 1 to 4 as bits. 2. **Loop (`while(xw--)`):** - Iterates `xw` times to perform the stepping action. 3. **Digital Writes:** - Sets each pin based on the corresponding bit in the current step. - `s[S]&1` sets pin 1, `(s[S]>>1)&1` sets pin 2, and so on. 4. **Step Increment:** - `S=(S+1)&7;` increments the step and wraps around using a bitmask. This version should be well under 300 bytes, making it suitable for code golf purposes.

Extract Code

I extracted the following code from that output: 

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void stepper(int xw){
    const unsigned char s[]={1,3,2,6,4,12,8,9};
    unsigned char S=0;
    while(xw--){
        digitalWrite(1,s[S]&1);
        digitalWrite(2,(s[S]>>1)&1);
        digitalWrite(3,(s[S]>>2)&1);
        digitalWrite(4,(s[S]>>3)&1);
        S=(S+1)&7;
    }
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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void stepper(int xw){
    const unsigned char s[]={1,3,2,6,4,12,8,9};
    unsigned char S=0;
    while(xw--){
        digitalWrite(1,s[S]&1);
        digitalWrite(2,(s[S]>>1)&1);
        digitalWrite(3,(s[S]>>2)&1);
        digitalWrite(4,(s[S]>>3)&1);
        S=(S+1)&7;
    }
}



#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: Wrong answer; got 370724802 instead of -1475775710. main.c: In function 'stepper': main.c:6:9: warning: implicit declaration of function 'digitalWrite' [-Wimplicit-function-declaration] 6 | digitalWrite(1,s[S]&1); | ^~~~~~~~~~~~

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

PyFunc

Resulting in output: True

Final Answer: False

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

Output

Here's a compact version of the `stepper` function using an array to store the step patterns. This approach significantly reduces the code size by eliminating the `switch` statement and using bitwise operations to set the pin states. 

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void stepper(int xw){
  static const char S[]={1,3,2,6,4,12,8,9};
  int s=0;
  while(xw--){
    digitalWrite(1,S[s]&1);
    digitalWrite(2,(S[s]>>1)&1);
    digitalWrite(3,(S[s]>>2)&1);
    digitalWrite(4,(S[s]>>3)&1);
    s=(s+1)&7;
  }
}
**Explanation:** 1. **Step Patterns Array (`S`):** - The array `S` holds the binary patterns for each step. Each element represents the state of the four pins (1 to 4) using bits. - For example, `1` is `0001` (only pin 4 is high), `3` is `0011` (pins 3 and 4 are high), and so on. 2. **Looping Through Steps:** - The `while(xw--)` loop runs `xw` times, decrementing `xw` each iteration. - For each iteration, it sets the pin states based on the current step pattern `S[s]`. 3. **Setting Pin States:** - `digitalWrite(1, S[s]&1);` sets pin 1 based on the least significant bit. - `digitalWrite(2, (S[s]>>1)&1);` sets pin 2 based on the next bit. - `digitalWrite(3, (S[s]>>2)&1);` sets pin 3. - `digitalWrite(4, (S[s]>>3)&1);` sets pin 4. 4. **Updating Step Counter:** - `s=(s+1)&7;` increments the step counter and wraps it around using bitwise AND to ensure it stays within 0-7. This optimized version should be well below the 300-byte limit and maintains the original functionality of the `stepper` function.

Extract Code

I extracted the following code from that output: 

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void stepper(int xw){
  static const char S[]={1,3,2,6,4,12,8,9};
  int s=0;
  while(xw--){
    digitalWrite(1,S[s]&1);
    digitalWrite(2,(S[s]>>1)&1);
    digitalWrite(3,(S[s]>>2)&1);
    digitalWrite(4,(S[s]>>3)&1);
    s=(s+1)&7;
  }
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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void stepper(int xw){
  static const char S[]={1,3,2,6,4,12,8,9};
  int s=0;
  while(xw--){
    digitalWrite(1,S[s]&1);
    digitalWrite(2,(S[s]>>1)&1);
    digitalWrite(3,(S[s]>>2)&1);
    digitalWrite(4,(S[s]>>3)&1);
    s=(s+1)&7;
  }
}



#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: Wrong answer; got 370724802 instead of -1475775710. main.c: In function 'stepper': main.c:6:5: warning: implicit declaration of function 'digitalWrite' [-Wimplicit-function-declaration] 6 | digitalWrite(1,S[s]&1); | ^~~~~~~~~~~~

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

PyFunc

Resulting in output: True

Final Answer: False