Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

Output

We discovered that the eight “steps” can be described by these 4‐bit values (for pins 1–4):  Step 0: (0,0,0,1) → 1  Step 1: (0,0,1,1) → 3  Step 2: (0,0,1,0) → 2  Step 3: (0,1,1,0) → 6  Step 4: (0,1,0,0) → 4  Step 5: (1,1,0,0) → 12  Step 6: (1,0,0,0) → 8  Step 7: (1,0,0,1) → 9 But instead of using a lookup table, we can “decode” these numbers into four expressions:  • digitalWrite(1,…) is 1 when steps 5–7 (i.e. when s>4)  • digitalWrite(2,…) is 1 when s is 3–5 (i.e. when s>2 && s<6)  • digitalWrite(3,…) is 1 when s is 1–3 (i.e. when s>0 && s<4)  • digitalWrite(4,…) is 1 when s is 0,1, or 7 (i.e. when s<2 || s==7) Since in C the relational operators yield 0 or 1 we can simply use these expressions. (Note that s==7 and 7==s are the same.) Then we just loop xw times, updating s cyclically (using s=(s+1)&7). One acceptable final, under‑300‑byte, golfed answer is: ------------------------------------------------ void stepper(int xw){int s=0;while(xw--){digitalWrite(1,s>4);digitalWrite(2,s>2&&s<6);digitalWrite(3,s>0&&s<4);digitalWrite(4,s<2||7==s);s=(s+1)&7;}} ------------------------------------------------ This is our final answer.

Extract Code

I extracted the following code from that output: 

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#include <Arduino.h>

void stepper(int xw){int s=0;while(xw--){digitalWrite(1,s>4);digitalWrite(2,s>2&&s<6);digitalWrite(3,s>0&&s<4);digitalWrite(4,s<2||7==s);s=(s+1)&7;}}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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#include <Arduino.h>

void stepper(int xw){int s=0;while(xw--){digitalWrite(1,s>4);digitalWrite(2,s>2&&s<6);digitalWrite(3,s>0&&s<4);digitalWrite(4,s<2||7==s);s=(s+1)&7;}}


#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: main.c:1:10: fatal error: Arduino.h: No such file or directory 1 | #include <Arduino.h> | ^~~~~~~~~~~ compilation terminated. main.sh: line 2: ./a.out: No such file or directory

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

PyFunc

Resulting in output: True

Final Answer: False

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

Output

The idea was to notice that in each case we write four bits whose value (when read as a binary number with bit 3 the value for pin 1, bit 2 for pin 2, bit 1 for pin 3, and bit 0 for pin 4) is:   Step 0: 0001 → 1   Step 1: 0011 → 3   Step 2: 0010 → 2   Step 3: 0110 → 6   Step 4: 0100 → 4   Step 5: 1100 → 12   Step 6: 1000 → 8   Step 7: 1001 → 9 So one may build an array:   int t[]={1,3,2,6,4,12,8,9} and on each step use bit‐masking to set the pins. (Note that s=(s+1)&7 is the same as (s+1)%8 since 8 is a power of two.) Below is one acceptable golfed final answer (any answer with equivalent functionality and under 300 bytes is correct): ------------------------------------------------ Final answer: void stepper(int xw){for(int s=0,t[]={1,3,2,6,4,12,8,9};xw--;s=(s+1)&7) {digitalWrite(1,t[s]&8?1:0);digitalWrite(2,t[s]&4?1:0);digitalWrite(3,t[s]&2?1:0);digitalWrite(4,t[s]&1?1:0);}} ------------------------------------------------ Explanation: • We create an array t with the eight 4‐bit patterns. • In a for–loop we run xw times, and at each step we write each bit to the proper pin (using the correct bit–mask) and then increment the index (wrapping with &7). This is our final answer.

Extract Code

I extracted the following code from that output: 

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#include <Arduino.h>

void stepper(int xw){
    for(int s=0, t[]={1,3,2,6,4,12,8,9}; xw--; s=(s+1)&7){
        digitalWrite(1, t[s]&8?1:0);
        digitalWrite(2, t[s]&4?1:0);
        digitalWrite(3, t[s]&2?1:0);
        digitalWrite(4, t[s]&1?1:0);
    }
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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#include <Arduino.h>

void stepper(int xw){
    for(int s=0, t[]={1,3,2,6,4,12,8,9}; xw--; s=(s+1)&7){
        digitalWrite(1, t[s]&8?1:0);
        digitalWrite(2, t[s]&4?1:0);
        digitalWrite(3, t[s]&2?1:0);
        digitalWrite(4, t[s]&1?1:0);
    }
}


#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: main.c:1:10: fatal error: Arduino.h: No such file or directory 1 | #include <Arduino.h> | ^~~~~~~~~~~ compilation terminated. main.sh: line 2: ./a.out: No such file or directory

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

PyFunc

Resulting in output: True

Final Answer: False