Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

Output

Here's a golfed version of your `stepper` function. Instead of using a switch statement, I've created an array of arrays to represent the pin states for each step and used a loop to write to the pins based on the current step index. This significantly reduces the code length: 

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void stepper(int xw) {
  int s[8][4]={{0,0,0,1},{0,0,1,1},{0,0,1,0},{0,1,1,0},{0,1,0,0},{1,1,0,0},{1,0,0,0},{1,0,0,1}};
  for(int i=0;i<xw;i++)for(int j=0;j<4;j++)digitalWrite(j+1,s[i%8][j]);
}
### Explanation: 1. **Array of States**: The states for each step are stored in a 2D array `s`, where each sub-array represents the output for pins 1 to 4 for each step. 2. **Loop**: The outer loop iterates through the number of steps (`xw`), while the inner loop writes the corresponding state to the pins using `digitalWrite`. 3. **Modulus Operator**: The current step is determined by `i % 8`, allowing it to loop through the 8 states continuously. This implementation is much shorter, and the total byte count (excluding whitespace) is well within the limit of 300 bytes.

Extract Code

I extracted the following code from that output: 

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void stepper(int xw) {
  int s[8][4]={{0,0,0,1},{0,0,1,1},{0,0,1,0},{0,1,1,0},{0,1,0,0},{1,1,0,0},{1,0,0,0},{1,0,0,1}};
  for(int i=0;i<xw;i++)for(int j=0;j<4;j++)digitalWrite(j+1,s[i%8][j]);
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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void stepper(int xw) {
  int s[8][4]={{0,0,0,1},{0,0,1,1},{0,0,1,0},{0,1,1,0},{0,1,0,0},{1,1,0,0},{1,0,0,0},{1,0,0,1}};
  for(int i=0;i<xw;i++)for(int j=0;j<4;j++)digitalWrite(j+1,s[i%8][j]);
}



#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed main.c: In function 'stepper': main.c:4:44: warning: implicit declaration of function 'digitalWrite' [-Wimplicit-function-declaration] 4 | for(int i=0;i<xw;i++)for(int j=0;j<4;j++)digitalWrite(j+1,s[i%8][j]); | ^~~~~~~~~~~~

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

PyFunc

Resulting in output: True

Final Answer: True

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

Output

Here’s a more concise version of the `stepper` function. We'll create a table of values for the digital outputs and use that table to simplify the function: 

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void stepper(int xw) {
  int s[8][4]={{0,0,0,1},{0,0,1,1},{0,0,1,0},{0,1,1,0},{0,1,0,0},{1,1,0,0},{1,0,0,0},{1,0,0,1}};
  for(int x=0;x<xw;x++,s[(x%8)])for(int i=0;i<4;i++)digitalWrite(i+1,s[x%8][i]);
}
### Explanation: 1. **Table Initialization**: We created a 2D array `s` to hold the output values for each step (0 to 7). 2. **Looping**: We loop through `x` from 0 to `xw`, and for each `x`, we find the appropriate index in `s` using `x % 8`. 3. **Digital Writes**: We then loop through the values in the current step and use `digitalWrite` to set the pins accordingly. This version is compact and achieves the same functionality as the original, while being under the byte limit.

Extract Code

I extracted the following code from that output: 

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void stepper(int xw) {
  int s[8][4]={{0,0,0,1},{0,0,1,1},{0,0,1,0},{0,1,1,0},{0,1,0,0},{1,1,0,0},{1,0,0,0},{1,0,0,1}};
  for(int x=0;x<xw;x++,s[(x%8)])for(int i=0;i<4;i++)digitalWrite(i+1,s[x%8][i]);
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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void stepper(int xw) {
  int s[8][4]={{0,0,0,1},{0,0,1,1},{0,0,1,0},{0,1,1,0},{0,1,0,0},{1,1,0,0},{1,0,0,0},{1,0,0,1}};
  for(int x=0;x<xw;x++,s[(x%8)])for(int i=0;i<4;i++)digitalWrite(i+1,s[x%8][i]);
}



#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed main.c: In function 'stepper': main.c:4:53: warning: implicit declaration of function 'digitalWrite' [-Wimplicit-function-declaration] 4 | for(int x=0;x<xw;x++,s[(x%8)])for(int i=0;i<4;i++)digitalWrite(i+1,s[x%8][i]); | ^~~~~~~~~~~~

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

PyFunc

Resulting in output: True

Final Answer: True

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

Output

Here's a shortened version of the `stepper` function. The optimization involves creating a lookup table for the output values and using that for each step rather than a series of `switch` cases. 

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void stepper(int xw) {
    const int pins[8][4] = {{0,0,0,1},{0,0,1,1},{0,0,1,0},{0,1,1,0},
                            {0,1,0,0},{1,1,0,0},{1,0,0,0},{1,0,0,1}};
    for (int i = 0; i < xw; i++) {
        digitalWrite(1, pins[i % 8][0]);
        digitalWrite(2, pins[i % 8][1]);
        digitalWrite(3, pins[i % 8][2]);
        digitalWrite(4, pins[i % 8][3]);
    }
}
### Explanation: 1. **Lookup Table**: The `pins` array serves as a lookup table for the digital values to be written to the pins. Each inner array corresponds to a step of the motor. 2. **Loop Optimization**: Instead of using a `switch` statement to determine which pins to set for each step, the function now directly accesses the `pins` array using the modulo operator to cycle through the steps. 3. **Code Compactness**: The number of lines and overall complexity is reduced significantly by using array indexing instead of repetitive code blocks, staying well under the 300-byte limit.

Extract Code

I extracted the following code from that output: 

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void stepper(int xw) {
    const int pins[8][4] = {{0,0,0,1},{0,0,1,1},{0,0,1,0},{0,1,1,0},
                            {0,1,0,0},{1,1,0,0},{1,0,0,0},{1,0,0,1}};
    for (int i = 0; i < xw; i++) {
        digitalWrite(1, pins[i % 8][0]);
        digitalWrite(2, pins[i % 8][1]);
        digitalWrite(3, pins[i % 8][2]);
        digitalWrite(4, pins[i % 8][3]);
    }
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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void stepper(int xw) {
    const int pins[8][4] = {{0,0,0,1},{0,0,1,1},{0,0,1,0},{0,1,1,0},
                            {0,1,0,0},{1,1,0,0},{1,0,0,0},{1,0,0,1}};
    for (int i = 0; i < xw; i++) {
        digitalWrite(1, pins[i % 8][0]);
        digitalWrite(2, pins[i % 8][1]);
        digitalWrite(3, pins[i % 8][2]);
        digitalWrite(4, pins[i % 8][3]);
    }
}



#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed main.c: In function 'stepper': main.c:6:9: warning: implicit declaration of function 'digitalWrite' [-Wimplicit-function-declaration] 6 | digitalWrite(1, pins[i % 8][0]); | ^~~~~~~~~~~~

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

PyFunc

Resulting in output: True

Final Answer: True

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

Output

To shorten the `stepper` function, we can create a lookup table for the digital values that correspond to each step, and then simply iterate through this table based on the current step. This will eliminate the need for repetitive `switch` statements. Here's the optimized code following your guidelines: 

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void stepper(int xw) {
  int s[8][4] = {{0,0,0,1},{0,0,1,1},{0,0,1,0},{0,1,1,0},{0,1,0,0},{1,1,0,0},{1,0,0,0},{1,0,0,1}};
  for (int i=0;i<xw;i++,Steps=(Steps+1)%8) 
    for(int j=0;j<4;j++) digitalWrite(j+1,s[Steps][j]);
}
### Explanation: 1. **Lookup Table**: We created a 2D array `s` that holds the digital values for each step. Each row corresponds to a step and each column corresponds to a pin. 2. **Looping**: We use a nested loop where the outer loop iterates `xw` times, and the inner loop updates the pins based on the values from the lookup table. 3. **Step Management**: The variable `Steps` is updated in the loop without needing to maintain a separate switch-case structure. This version is concise and maintains the same functionality as the original code while being significantly shorter.

Extract Code

I extracted the following code from that output: 

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void stepper(int xw) {
  int s[8][4] = {{0,0,0,1},{0,0,1,1},{0,0,1,0},{0,1,1,0},{0,1,0,0},{1,1,0,0},{1,0,0,0},{1,0,0,1}};
  for (int i=0;i<xw;i++,Steps=(Steps+1)%8) 
    for(int j=0;j<4;j++) digitalWrite(j+1,s[Steps][j]);
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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void stepper(int xw) {
  int s[8][4] = {{0,0,0,1},{0,0,1,1},{0,0,1,0},{0,1,1,0},{0,1,0,0},{1,1,0,0},{1,0,0,0},{1,0,0,1}};
  for (int i=0;i<xw;i++,Steps=(Steps+1)%8) 
    for(int j=0;j<4;j++) digitalWrite(j+1,s[Steps][j]);
}



#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: main.c: In function 'stepper': main.c:4:25: error: 'Steps' undeclared (first use in this function) 4 | for (int i=0;i<xw;i++,Steps=(Steps+1)%8) | ^~~~~ main.c:4:25: note: each undeclared identifier is reported only once for each function it appears in main.c:5:26: warning: implicit declaration of function 'digitalWrite' [-Wimplicit-function-declaration] 5 | for(int j=0;j<4;j++) digitalWrite(j+1,s[Steps][j]); | ^~~~~~~~~~~~ main.sh: line 2: ./a.out: No such file or directory

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

PyFunc

Resulting in output: True

Final Answer: False

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

Output

Here's a shorter version of the `stepper` function that uses a lookup table and bit manipulation to reduce the number of lines and make the code more concise. It maintains the same functionality while being under the 300-byte limit. 

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void stepper(int xw) {
  int s=0,d[8][4]={{0,0,0,1},{0,0,1,1},{0,0,1,0},{0,1,1,0},{0,1,0,0},{1,1,0,0},{1,0,0,0},{1,0,0,1}};
  for(int x=0;x<xw;x++,s=(s+1)%8)for(int i=0;i<4;i++)digitalWrite(i+1,d[s][i]);
}
### Explanation: 1. **Table Creation**: The `d` array holds the pin states for each step (0-7) in a compact form. 2. **Loop through Steps**: A single loop iterates through the number of steps (`xw`), updating the step counter `s` using modulo 8. 3. **Pin State Update**: A nested loop writes the corresponding pin states directly from the `d` array. This implementation maintains clarity while significantly reducing the number of lines and overall size of the function.

Extract Code

I extracted the following code from that output: 

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void stepper(int xw) {
  int s=0,d[8][4]={{0,0,0,1},{0,0,1,1},{0,0,1,0},{0,1,1,0},{0,1,0,0},{1,1,0,0},{1,0,0,0},{1,0,0,1}};
  for(int x=0;x<xw;x++,s=(s+1)%8)for(int i=0;i<4;i++)digitalWrite(i+1,d[s][i]);
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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void stepper(int xw) {
  int s=0,d[8][4]={{0,0,0,1},{0,0,1,1},{0,0,1,0},{0,1,1,0},{0,1,0,0},{1,1,0,0},{1,0,0,0},{1,0,0,1}};
  for(int x=0;x<xw;x++,s=(s+1)%8)for(int i=0;i<4;i++)digitalWrite(i+1,d[s][i]);
}



#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed main.c: In function 'stepper': main.c:4:54: warning: implicit declaration of function 'digitalWrite' [-Wimplicit-function-declaration] 4 | for(int x=0;x<xw;x++,s=(s+1)%8)for(int i=0;i<4;i++)digitalWrite(i+1,d[s][i]); | ^~~~~~~~~~~~

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

PyFunc

Resulting in output: True

Final Answer: True