Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`.

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`.

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

Output

Looking at the original code, I notice it's controlling 4 pins in 8 different sequence steps. Let me first create a table of what's being written to each pin: | Step | Pin 1 | Pin 2 | Pin 3 | Pin 4 | Decimal | |------|-------|-------|-------|-------|---------| | 0 | 0 | 0 | 0 | 1 | 1 | | 1 | 0 | 0 | 1 | 1 | 3 | | 2 | 0 | 0 | 1 | 0 | 2 | | 3 | 0 | 1 | 1 | 0 | 6 | | 4 | 0 | 1 | 0 | 0 | 4 | | 5 | 1 | 1 | 0 | 0 | 12 | | 6 | 1 | 0 | 0 | 0 | 8 | | 7 | 1 | 0 | 0 | 1 | 9 | I can represent each step with a single number where each bit represents a pin state. Then I can set all pins by bit-shifting this number! First attempt:

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void stepper(int xw) {
  static const int p[] = {1, 3, 2, 6, 4, 12, 8, 9};
  for (int x = 0; x < xw; x++) {
    int s = p[x % 8];
    digitalWrite(1, (s >> 3) & 1);
    digitalWrite(2, (s >> 2) & 1);
    digitalWrite(3, (s >> 1) & 1);
    digitalWrite(4, s & 1);
  }
}
Let's make it even shorter by eliminating the temporary variable:
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void stepper(int xw) {
  static const int p[] = {1, 3, 2, 6, 4, 12, 8, 9};
  for (int x = 0; x < xw; x++) {
    digitalWrite(1, (p[x % 8] >> 3) & 1);
    digitalWrite(2, (p[x % 8] >> 2) & 1);
    digitalWrite(3, (p[x % 8] >> 1) & 1);
    digitalWrite(4, p[x % 8] & 1);
  }
}
Final answer:
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void stepper(int xw){
  static const int p[]={1,3,2,6,4,12,8,9};
  for(int x=0;x<xw;x++){
    int v=p[x%8];
    digitalWrite(1,v>>3&1);
    digitalWrite(2,v>>2&1);
    digitalWrite(3,v>>1&1);
    digitalWrite(4,v&1);
  }
}
This solution uses a fixed array containing each pin state encoded as a 4-bit pattern, then extracts each bit to set the corresponding pin. At around 150-170 bytes, it's well under our 300-byte limit.

Extract Code

I extracted the following code from that output:

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#include <Arduino.h>

void stepper(int xw){
  static const int p[]={1,3,2,6,4,12,8,9};
  for(int x=0;x<xw;x++){
    int v=p[x%8];
    digitalWrite(1,v>>3&1);
    digitalWrite(2,v>>2&1);
    digitalWrite(3,v>>1&1);
    digitalWrite(4,v&1);
  }
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program:

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#include <Arduino.h>

void stepper(int xw){
  static const int p[]={1,3,2,6,4,12,8,9};
  for(int x=0;x<xw;x++){
    int v=p[x%8];
    digitalWrite(1,v>>3&1);
    digitalWrite(2,v>>2&1);
    digitalWrite(3,v>>1&1);
    digitalWrite(4,v&1);
  }
}



#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: main.c:2:10: fatal error: Arduino.h: No such file or directory 2 | #include <Arduino.h> | ^~~~~~~~~~~ compilation terminated. main.sh: line 2: ./a.out: No such file or directory

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

PyFunc

Resulting in output: True

Final Answer: False

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`.

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <300 bytes (not counting whitespace). Keep the name `stepper`.

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}
To do this follow these steps: 1. start out by creating a table of the values that are being written to the pins. 2. Then find an expression for this. 3. Write the function as short as possible. 4. See if you can make it any shorter. Return this as the final answer and call it your final answer. Make sure to name it stepper still.

Output

# Code Golf Solution First, I'll map the digital writes to a pattern:

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Step | Pin 1 | Pin 2 | Pin 3 | Pin 4 | Binary | Decimal
-----|-------|-------|-------|-------|--------|--------
  0  |   0   |   0   |   0   |   1   |  0001  |    1
  1  |   0   |   0   |   1   |   1   |  0011  |    3
  2  |   0   |   0   |   1   |   0   |  0010  |    2
  3  |   0   |   1   |   1   |   0   |  0110  |    6
  4  |   0   |   1   |   0   |   0   |  0100  |    4
  5  |   1   |   1   |   0   |   0   |  1100  |   12
  6  |   1   |   0   |   0   |   0   |  1000  |    8
  7  |   1   |   0   |   0   |   1   |  1001  |    9
The values follow a pattern where each step has a specific 4-bit code. Instead of a large switch statement, I can lookup the pattern and extract each bit. Here's my golfed solution:
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void stepper(int xw){
  static const byte p[]={1,3,2,6,4,12,8,9};
  for(int x=0;x<xw;x++){
    byte v=p[x&7];
    digitalWrite(1,v>>3&1);
    digitalWrite(2,v>>2&1);
    digitalWrite(3,v>>1&1);
    digitalWrite(4,v&1);
  }
}
## Final answer
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void stepper(int xw){static const byte p[]={1,3,2,6,4,12,8,9};for(int x=0;x<xw;x++){byte v=p[x&7];digitalWrite(1,v>>3&1);digitalWrite(2,v>>2&1);digitalWrite(3,v>>1&1);digitalWrite(4,v&1);}}
This solution: 1. Uses a byte array to store the bit patterns 2. Uses bitwise operations to extract individual bits 3. Uses `x&7` instead of `x%8` to get values 0-7 4. Uses a temporary variable to avoid multiple array lookups The total byte count (excluding whitespace) is approximately 153 bytes, well under the 300 byte limit.

Extract Code

I extracted the following code from that output:

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#include <Arduino.h>

void stepper(int xw){
  static const byte p[]={1,3,2,6,4,12,8,9};
  for(int x=0;x<xw;x++){
    byte v=p[x&7];
    digitalWrite(1,v>>3&1);
    digitalWrite(2,v>>2&1);
    digitalWrite(3,v>>1&1);
    digitalWrite(4,v&1);
  }
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program:

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#include <Arduino.h>

void stepper(int xw){
  static const byte p[]={1,3,2,6,4,12,8,9};
  for(int x=0;x<xw;x++){
    byte v=p[x&7];
    digitalWrite(1,v>>3&1);
    digitalWrite(2,v>>2&1);
    digitalWrite(3,v>>1&1);
    digitalWrite(4,v&1);
  }
}



#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: main.c:2:10: fatal error: Arduino.h: No such file or directory 2 | #include <Arduino.h> | ^~~~~~~~~~~ compilation terminated. main.sh: line 2: ./a.out: No such file or directory

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

PyFunc

Resulting in output: True

Final Answer: False