Initial Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the name `stepper`.

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the name `stepper`.

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

Output

Sure! Here's a compact version of the `stepper` function using a lookup table to minimize the code size. This version is well under 200 bytes (excluding whitespace):

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void stepper(int xw){
  char a[]={1,3,2,6,4,12,8,9},S=0;
  while(xw--){
    digitalWrite(1,a[S]&1);
    digitalWrite(2,(a[S]>>1)&1);
    digitalWrite(3,(a[S]>>2)&1);
    digitalWrite(4,(a[S]>>3)&1);
    S=(S+1)&7;
  }
}
**Explanation:** 1. **Lookup Table (`a`):** - The array `a` holds the binary patterns corresponding to each step. Each element represents the states of pins 1 to 4 using bit masking. - For example, `1` represents `0001` (only pin 4 is high), `3` represents `0011` (pins 3 and 4 are high), etc. 2. **Loop and State Management:** - The `while(xw--)` loop runs `xw` times, decrementing `xw` with each iteration. - Inside the loop: - `digitalWrite` is called for each pin (1 to 4), setting them based on the current state `S` using bitwise operations. - `S` is incremented and wrapped around using `S=(S+1)&7` to cycle through 0 to 7. This approach replaces the `switch` statement with a simple array lookup and bitwise operations, significantly reducing the code size while maintaining functionality.

Extract Code

I extracted the following code from that output:

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void stepper(int xw){
  char a[]={1,3,2,6,4,12,8,9},S=0;
  while(xw--){
    digitalWrite(1,a[S]&1);
    digitalWrite(2,(a[S]>>1)&1);
    digitalWrite(3,(a[S]>>2)&1);
    digitalWrite(4,(a[S]>>3)&1);
    S=(S+1)&7;
  }
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program:

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void stepper(int xw){
  char a[]={1,3,2,6,4,12,8,9},S=0;
  while(xw--){
    digitalWrite(1,a[S]&1);
    digitalWrite(2,(a[S]>>1)&1);
    digitalWrite(3,(a[S]>>2)&1);
    digitalWrite(4,(a[S]>>3)&1);
    S=(S+1)&7;
  }
}



#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: Wrong answer; got 370724802 instead of -1475775710. main.c: In function 'stepper': main.c:5:5: warning: implicit declaration of function 'digitalWrite' [-Wimplicit-function-declaration] 5 | digitalWrite(1,a[S]&1); | ^~~~~~~~~~~~

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

PyFunc

Resulting in output: True

Final Answer: False

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the name `stepper`.

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the name `stepper`.

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

Output

Here's a golfed version of the `stepper` function in C that is well under 200 bytes (excluding whitespace):

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void stepper(intxw){
  static char s[]={8,12,10,6,4,3,1,9};
  int S=0,x;
  for(x=0;x<xw;x++){
    digitalWrite(1,s[S]&1);
    digitalWrite(2,s[S]>>1&1);
    digitalWrite(3,s[S]>>2&1);
    digitalWrite(4,s[S]>>3&1);
    S=(S+1)&7;
  }
}
**Explanation of Optimizations:** 1. **Lookup Table:** - **Purpose:** Instead of using a `switch` statement with multiple `digitalWrite` calls, a lookup table (`s`) is used to store the state of the pins for each step. Each value in the array represents the state of pins 1 to 4 using bit manipulation. - **Benefit:** Reduces the number of conditional statements and repeated function calls, significantly shortening the code. 2. **Compact Variable Naming:** - **Variables:** Shortened variable names like `xw` to `xw`, `Steps` to `S`, and `x` remain concise. - **Benefit:** Minimizes the number of characters used for variable declarations and references. 3. **Bit Manipulation:** - **Approach:** Uses bitwise operations to extract the state of each pin from the lookup table: - `s[S]&1` extracts the state for pin 1. - `s[S]>>1&1` extracts the state for pin 2. - `s[S]>>2&1` extracts the state for pin 3. - `s[S]>>3&1` extracts the state for pin 4. - **Benefit:** Eliminates the need for multiple `if` or `switch` cases, reducing the overall code length. 4. **Loop Optimization:** - The `for` loop is kept as simple and concise as possible, avoiding unnecessary braces or spaces. This optimized version maintains the original functionality while significantly reducing the code size, making it suitable for code golf challenges.

Extract Code

I extracted the following code from that output:

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void stepper(intxw){
  static char s[]={8,12,10,6,4,3,1,9};
  int S=0,x;
  for(x=0;x<xw;x++){
    digitalWrite(1,s[S]&1);
    digitalWrite(2,s[S]>>1&1);
    digitalWrite(3,s[S]>>2&1);
    digitalWrite(4,s[S]>>3&1);
    S=(S+1)&7;
  }
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program:

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void stepper(intxw){
  static char s[]={8,12,10,6,4,3,1,9};
  int S=0,x;
  for(x=0;x<xw;x++){
    digitalWrite(1,s[S]&1);
    digitalWrite(2,s[S]>>1&1);
    digitalWrite(3,s[S]>>2&1);
    digitalWrite(4,s[S]>>3&1);
    S=(S+1)&7;
  }
}



#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: main.c: In function 'stepper': main.c:2:6: warning: type of 'intxw' defaults to 'int' [-Wimplicit-int] 2 | void stepper(intxw){ | ^~~~~~~ main.c:5:13: error: 'xw' undeclared (first use in this function); did you mean 'x'? 5 | for(x=0;x<xw;x++){ | ^~ | x main.c:5:13: note: each undeclared identifier is reported only once for each function it appears in main.c:6:5: warning: implicit declaration of function 'digitalWrite' [-Wimplicit-function-declaration] 6 | digitalWrite(1,s[S]&1); | ^~~~~~~~~~~~ main.sh: line 2: ./a.out: No such file or directory

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

PyFunc

Resulting in output: True

Final Answer: False