Initial Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

Output

Here's the code golfed version of the `stepper` function, which is under 200 bytes (excluding whitespace): 

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void stepper(int x){int s=0;for(;x--;s=(s+1)%8)for(int i=0;i<4;i++)digitalWrite(i+1,s>>i&1^s>>i+1&1);}
Explanation: - The outer loop iterates `x` times, decrementing `x` in each iteration. - `s` is the step counter, which is incremented and modulo 8 in each iteration. - The inner loop iterates from 0 to 3 (inclusive) to set the states of the four pins. - `s>>i&1^s>>i+1&1` determines the state of each pin based on the current step. - `s>>i&1` checks if the i-th bit of `s` is set (1) or not (0). - `s>>i+1&1` checks if the (i+1)-th bit of `s` is set (1) or not (0). - The XOR (`^`) operation between these two bits determines the final state of the pin. - `digitalWrite(i+1, ...)` sets the state of the pin (`i+1`) based on the calculated value. The code golf version reduces the size of the function by: - Using shorter variable names. - Removing the `switch` statement and using a bitwise operation to determine the pin states. - Using a single loop to iterate over the pins instead of explicitly writing each `digitalWrite` statement. Note: This code golf version prioritizes brevity over readability and maintainability. It is not recommended for production code but serves as an exercise in reducing code size.

Extract Code

I extracted the following code from that output: 

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void stepper(int x){int s=0;for(;x--;s=(s+1)%8)for(int i=0;i<4;i++)digitalWrite(i+1,s>>i&1^s>>i+1&1);}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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void stepper(int x){int s=0;for(;x--;s=(s+1)%8)for(int i=0;i<4;i++)digitalWrite(i+1,s>>i&1^s>>i+1&1);}



#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: Wrong answer; got -453235900 instead of -1475775710. main.c: In function 'stepper': main.c:2:68: warning: implicit declaration of function 'digitalWrite' [-Wimplicit-function-declaration] 2 | void stepper(int x){int s=0;for(;x--;s=(s+1)%8)for(int i=0;i<4;i++)digitalWrite(i+1,s>>i&1^s>>i+1&1);} | ^~~~~~~~~~~~

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

PyFunc

Resulting in output: True

Final Answer: False

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

Output

Here's the code golfed version of the `stepper` function, which is under 200 bytes (excluding whitespace): 

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void stepper(int x){for(int S=0;x--;S=(S+1)%8){int a[]={0,0,0,1,1,0,0,1,0,0,1,1,0,1,1,0,1,1,0,0,1,0,0,0,0,0,0,1,0,0,0,0};for(int i=0;i<4;)digitalWrite(++i,a[S*4+i-1]);}}
Explanation: - The outer loop iterates `x` times, decrementing `x` in each iteration. - `S` represents the current step and is incremented modulo 8 in each iteration. - The array `a` contains the binary states for each step and each pin. Each step occupies 4 elements in the array. - The inner loop iterates over the 4 pins and sets their states using `digitalWrite` based on the corresponding values in the `a` array. The code takes advantage of the fact that the pin states follow a specific pattern, allowing us to store them in a compact array and access them using the step number and pin index. Note: The code assumes that the `digitalWrite` function is available and that the pins are numbered from 1 to 4.

Extract Code

I extracted the following code from that output: 

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void stepper(int x){for(int S=0;x--;S=(S+1)%8){int a[]={0,0,0,1,1,0,0,1,0,0,1,1,0,1,1,0,1,1,0,0,1,0,0,0,0,0,0,1,0,0,0,0};for(int i=0;i<4;)digitalWrite(++i,a[S*4+i-1]);}}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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void stepper(int x){for(int S=0;x--;S=(S+1)%8){int a[]={0,0,0,1,1,0,0,1,0,0,1,1,0,1,1,0,1,1,0,0,1,0,0,0,0,0,0,1,0,0,0,0};for(int i=0;i<4;)digitalWrite(++i,a[S*4+i-1]);}}



#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: Wrong answer; got -216546045 instead of -1475775710. main.c: In function 'stepper': main.c:2:139: warning: implicit declaration of function 'digitalWrite' [-Wimplicit-function-declaration] 2 | void stepper(int x){for(int S=0;x--;S=(S+1)%8){int a[]={0,0,0,1,1,0,0,1,0,0,1,1,0,1,1,0,1,1,0,0,1,0,0,0,0,0,0,1,0,0,0,0};for(int i=0;i<4;)digitalWrite(++i,a[S*4+i-1]);}} | ^~~~~~~~~~~~

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

PyFunc

Resulting in output: True

Final Answer: False

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

Output

Here's a code golf version of the `stepper` function that is under 200 bytes: 

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void stepper(int xw){
  for(int x=0,s=0;x<xw;x++,s=(s+1)%8)
    for(int i=0;i<4;i++)
      digitalWrite(i+1,s>>i&1|(s>>i&2&&i>1));
}
Explanation: - The outer loop iterates `xw` times and increments the `s` variable (steps) modulo 8. - The inner loop iterates over the 4 pins. - The `digitalWrite` function is called with the pin number (`i+1`) and a bitwise expression that determines the state of the pin based on the current step (`s`). - `s>>i&1` checks if the i-th bit of `s` is set (1) or not (0). - `s>>i&2&&i>1` checks if the (i+1)-th bit of `s` is set (1) and `i` is greater than 1. This is used to set the state of pins 3 and 4 in certain steps. The code golf version reduces the size of the function by using bitwise operations to determine the state of each pin based on the current step, eliminating the need for a switch statement. Note: The code assumes that the `digitalWrite` function is defined and the pins are properly set up.

Extract Code

I extracted the following code from that output: 

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void stepper(int xw){
  for(int x=0,s=0;x<xw;x++,s=(s+1)%8)
    for(int i=0;i<4;i++)
      digitalWrite(i+1,s>>i&1|(s>>i&2&&i>1));
}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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void stepper(int xw){
  for(int x=0,s=0;x<xw;x++,s=(s+1)%8)
    for(int i=0;i<4;i++)
      digitalWrite(i+1,s>>i&1|(s>>i&2&&i>1));
}



#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: Wrong answer; got -7200748 instead of -1475775710. main.c: In function 'stepper': main.c:5:7: warning: implicit declaration of function 'digitalWrite' [-Wimplicit-function-declaration] 5 | digitalWrite(i+1,s>>i&1|(s>>i&2&&i>1)); | ^~~~~~~~~~~~

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

PyFunc

Resulting in output: True

Final Answer: False

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

Output

Here's the code golfed version of the `stepper` function in under 200 bytes (not counting whitespace): 

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void stepper(int x){int s=0;for(;x--;s=(s+1)%8){int a[]={0,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,0,1,0,0,1};for(int i=0;i<4;i++)digitalWrite(i+1,a[s*4+i]);}}
This version reduces the code size by: 1. Renaming variables to single-letter names. 2. Using an array `a` to store the binary patterns for each step, avoiding the need for a `switch` statement. 3. Using a single `for` loop to iterate through the steps and setting the pin states using the array values. 4. Removing unnecessary whitespace and braces. The function still performs the same stepping sequence as the original code, but in a much more compact form.

Extract Code

I extracted the following code from that output: 

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void stepper(int x){int s=0;for(;x--;s=(s+1)%8){int a[]={0,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,0,1,0,0,1};for(int i=0;i<4;i++)digitalWrite(i+1,a[s*4+i]);}}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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void stepper(int x){int s=0;for(;x--;s=(s+1)%8){int a[]={0,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,0,1,0,0,1};for(int i=0;i<4;i++)digitalWrite(i+1,a[s*4+i]);}}



#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed main.c: In function 'stepper': main.c:2:143: warning: implicit declaration of function 'digitalWrite' [-Wimplicit-function-declaration] 2 | void stepper(int x){int s=0;for(;x--;s=(s+1)%8){int a[]={0,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,0,1,0,0,1};for(int i=0;i<4;i++)digitalWrite(i+1,a[s*4+i]);}} | ^~~~~~~~~~~~

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

PyFunc

Resulting in output: True

Final Answer: True

Initial Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

LLM Generation

Query

Code golf this function to be a lot shorter. You only get points if it's <200 bytes (not counting whitespace). Keep the name `stepper`. 

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void stepper(int xw) {
  int Steps = 0;
  for (int x = 0; x < xw; x++) {
    switch (Steps) {
      case 0:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      case 1:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 1);
        break;
      case 2:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 3:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 1);
        digitalWrite(4, 0);
        break;
      case 4:
        digitalWrite(1, 0);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 5:
        digitalWrite(1, 1);
        digitalWrite(2, 1);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 6:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
      case 7:
        digitalWrite(1, 1);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 1);
        break;
      default:
        digitalWrite(1, 0);
        digitalWrite(2, 0);
        digitalWrite(3, 0);
        digitalWrite(4, 0);
        break;
    }
    Steps = (Steps + 1) % 8;
  }
}

Output

Here's the code golfed version of the `stepper` function that is under 200 bytes (excluding whitespace): 

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void stepper(int xw){int S=0;for(int x=0;x<xw;x++){int a[]={0,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,0,1,0,0,1};for(int i=0;i<4;i++)digitalWrite(i+1,a[S*4+i]);S=(S+1)%8;}}
This version reduces the code size by: 1. Using a single array `a` to store the binary patterns for each step, instead of using a `switch` statement. 2. Using a loop to set the `digitalWrite` values based on the current step, instead of manually setting each value. 3. Renaming the `Steps` variable to `S` to save bytes. 4. Removing unnecessary whitespace and braces. The function still performs the same functionality as the original version, but in a more compact form. Note: The code assumes that the `digitalWrite` function is defined elsewhere and that the pins 1, 2, 3, and 4 are used for the stepper motor control.

Extract Code

I extracted the following code from that output: 

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void stepper(int xw){int S=0;for(int x=0;x<xw;x++){int a[]={0,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,0,1,0,0,1};for(int i=0;i<4;i++)digitalWrite(i+1,a[S*4+i]);S=(S+1)%8;}}

Check if all of the following conditions are true:

Run Code Interpreter

Running the following program: 

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void stepper(int xw){int S=0;for(int x=0;x<xw;x++){int a[]={0,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,0,1,0,0,1};for(int i=0;i<4;i++)digitalWrite(i+1,a[S*4+i]);S=(S+1)%8;}}



#include<stdio.h>
#include<stdlib.h>

#include <stdio.h>

int out = 0;
int digitalWrite(int pin, int value) {
  out *= 101;
  out += pin;
  out *= 97;
  out += value;
  return out;
}

int main() {


int answer = (stepper(100),out);
int expected = -1475775710;
if (answer != expected) {
    printf("Wrong answer; got %d instead of %d.\n", answer, expected);
    exit(1);
}
printf("All tests passed\n");
}
And got the output: All tests passed main.c: In function 'stepper': main.c:2:146: warning: implicit declaration of function 'digitalWrite' [-Wimplicit-function-declaration] 2 | void stepper(int xw){int S=0;for(int x=0;x<xw;x++){int a[]={0,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,0,1,0,0,1};for(int i=0;i<4;i++)digitalWrite(i+1,a[S*4+i]);S=(S+1)%8;}} | ^~~~~~~~~~~~

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

PyFunc

Resulting in output: True

Final Answer: True