Initial Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

LLM Generation

Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

Output

Here's one way to write the function using a regular expression: ------------------------------------------------------------ def match(text): import re # This regex uses a capture group for a word (\w+) # followed by a non-capturing group matching any non-word chars and the same word again. # The {4,} means that this repetition must occur at least four times after the first occurrence, # making a total of at least 5 consecutive occurrences. pattern = r'\b(\w+)(?:\W+\1){4,}\b' m = re.search(pattern, text) return m.group(1) if m else '' # Example usage: example1 = "hello hello hello hello hello" example2 = "test test test" # less than 5 repetitions print(match(example1)) # Output: hello print(match(example2)) # Output: (an empty string) ------------------------------------------------------------ Explanation: • The pattern \b(\w+)\b matches a word (letters, digits, or underscores) and ensures word boundaries. • (?:\W+\1){4,} is a non-capturing group which requires the same word (via \1) preceded by one or more non-word characters, repeated at least 4 times. • Thus, the full expression looks for 1 initial word followed by at least 4 occurrences of that same word (i.e. 5 times overall). • If a match is found, we return the word, otherwise we return an empty string.

Extract Code

I extracted the following code from that output: 

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import re

def match(text):
    # This regex uses a capture group for a word (\w+)
    # followed by a non-capturing group matching any non-word chars and the same word again.
    # The {4,} means that this repetition must occur at least four times after the first occurrence,
    # making a total of at least 5 consecutive occurrences.
    pattern = r'\b(\w+)(?:\W+\1){4,}\b'
    m = re.search(pattern, text)
    return m.group(1) if m else ''

Run Code Interpreter

Running the following program: 

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import re

def match(text):
    # This regex uses a capture group for a word (\w+)
    # followed by a non-capturing group matching any non-word chars and the same word again.
    # The {4,} means that this repetition must occur at least four times after the first occurrence,
    # making a total of at least 5 consecutive occurrences.
    pattern = r'\b(\w+)(?:\W+\1){4,}\b'
    m = re.search(pattern, text)
    return m.group(1) if m else ''




answer = match('hi hi hi hi hi')
expected = "hi"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hi hi hi hi')
expected = ""
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hello this is is is is is a test')
expected = "is"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

LLM Generation

Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

Output

Below is one acceptable solution. The function uses a regex that captures a word and then looks for that same word repeated at least 4 more times (for a total of 5 or more occurrences). If such a pattern is found, the function returns the word; otherwise, it returns an empty string. Here is the code: ------------------------------------------------ def match(text): import re # This regex does the following: # \b : word boundary # (?P<word>\w+): capture one or more word characters into a group named "word" # (?:\s+(?P=word)){4,} : non-capturing group that matches one or more whitespace characters, # followed by the same word, repeated at least 4 times. # \b : end with a word boundary. pattern = r'\b(?P<word>\w+)(?:\s+(?P=word)){4,}\b' match_obj = re.search(pattern, text) if match_obj: return match_obj.group("word") else: return "" # Example usage: if __name__ == "__main__": test_string = "hello hello hello hello hello world" print(match(test_string)) # Expected output: hello ------------------------------------------------ Explanation: 1. The regex uses a named group (?P<word>\w+) to capture a word. 2. The non-capturing group (?:\s+(?P=word)){4,} requires that same word (preceded by whitespace) appears at least 4 more times consecutively. 3. re.search finds the first occurrence that fits this pattern. 4. If the pattern is present, the word is returned; otherwise, an empty string is returned. This meets the requirements.

Extract Code

I extracted the following code from that output: 

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import re

def match(text):
    # This regex does the following:
    # \b           : word boundary
    # (?P<word>\w+): capture one or more word characters into a group named "word"
    # (?:\s+(?P=word)){4,} : non-capturing group that matches one or more whitespace characters, 
    #                        followed by the same word, repeated at least 4 times.
    # \b           : end with a word boundary.
    pattern = r'\b(?P<word>\w+)(?:\s+(?P=word)){4,}\b'
    match_obj = re.search(pattern, text)
    if match_obj:
        return match_obj.group("word")
    else:
        return ""

Run Code Interpreter

Running the following program: 

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import re

def match(text):
    # This regex does the following:
    # \b           : word boundary
    # (?P<word>\w+): capture one or more word characters into a group named "word"
    # (?:\s+(?P=word)){4,} : non-capturing group that matches one or more whitespace characters, 
    #                        followed by the same word, repeated at least 4 times.
    # \b           : end with a word boundary.
    pattern = r'\b(?P<word>\w+)(?:\s+(?P=word)){4,}\b'
    match_obj = re.search(pattern, text)
    if match_obj:
        return match_obj.group("word")
    else:
        return ""




answer = match('hi hi hi hi hi')
expected = "hi"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hi hi hi hi')
expected = ""
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hello this is is is is is a test')
expected = "is"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True