Initial Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

LLM Generation

Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

Output

**Function to Find Repeated Words** ### Description This function uses a regular expression to find any word repeated 5 times or more in a given string. It returns the first word that meets this condition, or an empty string if no such word exists. ### Code

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import re
from collections import Counter

def match(s):
    """
    Find any word repeated 5 times or more in a string.

    Args:
        s (str): The input string.

    Returns:
        str: The first word repeated 5 times or more, or an empty string.
    """
    # Split the string into words
    words = re.findall(r'\b\w+\b', s.lower())

    # Count the occurrences of each word
    word_counts = Counter(words)

    # Find the first word with 5 or more occurrences
    for word, count in word_counts.items():
        if count >= 5:
            return word

    # If no word is repeated 5 times or more, return an empty string
    return ""

# Example usage:
print(match("test test test test test hello world"))  # Output: test
print(match("hello world hello world hello world hello world hello"))  # Output: hello
print(match("hello world"))  # Output: (empty string)
### Explanation 1. The function first splits the input string into words using a regular expression. The `\b\w+\b` pattern matches any word character (equivalent to `[a-zA-Z0-9_]`) surrounded by word boundaries. 2. It then counts the occurrences of each word using the `Counter` class from the `collections` module. 3. The function iterates over the word counts and returns the first word with 5 or more occurrences. 4. If no word is repeated 5 times or more, the function returns an empty string. Note: This function is case-insensitive, as it converts the input string to lowercase before splitting it into words.

Extract Code

I extracted the following code from that output:

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import re
from collections import Counter

def match(s):
    """
    Find any word repeated 5 times or more in a string.

    Args:
        s (str): The input string.

    Returns:
        str: The first word repeated 5 times or more, or an empty string.
    """
    # Split the string into words
    words = re.findall(r'\b\w+\b', s.lower())

    # Count the occurrences of each word
    word_counts = Counter(words)

    # Find the first word with 5 or more occurrences
    for word, count in word_counts.items():
        if count >= 5:
            return word

    # If no word is repeated 5 times or more, return an empty string
    return ""

# Example usage:
print(match("test test test test test hello world"))  # Output: test
print(match("hello world hello world hello world hello world hello"))  # Output: hello
print(match("hello world"))  # Output: (empty string)

Run Code Interpreter

Running the following program:

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import re
from collections import Counter

def match(s):
    """
    Find any word repeated 5 times or more in a string.

    Args:
        s (str): The input string.

    Returns:
        str: The first word repeated 5 times or more, or an empty string.
    """
    # Split the string into words
    words = re.findall(r'\b\w+\b', s.lower())

    # Count the occurrences of each word
    word_counts = Counter(words)

    # Find the first word with 5 or more occurrences
    for word, count in word_counts.items():
        if count >= 5:
            return word

    # If no word is repeated 5 times or more, return an empty string
    return ""

# Example usage:
print(match("test test test test test hello world"))  # Output: test
print(match("hello world hello world hello world hello world hello"))  # Output: hello
print(match("hello world"))  # Output: (empty string)





answer = match('hi hi hi hi hi')
expected = "hi"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hi hi hi hi')
expected = ""
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hello this is is is is is a test')
expected = "is"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: test hello All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True