Initial Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

LLM Generation

Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

Output

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import re

def match(text: str) -> str:
  """
  Uses a regex to find the first word repeated consecutively 5 or more times.

  Args:
    text: The input string to search within.

  Returns:
    The repeated word if found (repeated 5 or more times consecutively),
    otherwise an empty string.
  """
  # Regex breakdown:
  # (\b\w+\b) : Capture group 1: Match a whole word.
  #             \b ensures it's a whole word (word boundary).
  #             \w+ matches one or more alphanumeric characters (letters, numbers, _).
  # (?:\s+\1) : Non-capturing group:
  #             \s+ matches one or more whitespace characters (space, tab, newline etc.)
  #             \1 is a backreference to the exact text matched by capture group 1 (the word).
  # {4,}      : Quantifier: Match the preceding non-capturing group (whitespace + same word)
  #             4 or more times.
  #             This means the word appears 1 (from group 1) + 4 (from repetitions) = 5 or more times total.
  # \b        : Ensure the last repetition also ends at a word boundary. This prevents matching
  #             "go go go go gogo" as 5 repetitions of "go".
  pattern = r"(\b\w+\b)(?:\s+\1){4,}\b"

  search_result = re.search(pattern, text)

  if search_result:
    # Group 1 contains the word itself that was repeated
    return search_result.group(1)
  else:
    # No match found
    return ""

# Example Usage:
print(f"'hello hello hello hello hello world' -> '{match('hello hello hello hello hello world')}'")
print(f"'test test test test' -> '{match('test test test test')}'") # Only 4 times
print(f"'go go go go go go' -> '{match('go go go go go go')}'") # 6 times >= 5
print(f"'word word word word word.' -> '{match('word word word word word.')}'") # Punctuation acts as boundary
print(f"'abcabcabcabcabc' -> '{match('abcabcabcabcabc')}'") # Not separated by spaces
print(f"' one one one one one two' -> '{match(' one one one one one two')}'")
print(f"' five five five five fivefive' -> '{match(' five five five five fivefive')}'") # Last one isn't whole word
print(f"'no repeats here' -> '{match('no repeats here')}'")
print(f"'' -> '{match('')}'")
print(f"'repeat repeat repeat repeat repeat! yes' -> '{match('repeat repeat repeat repeat repeat! yes')}'")
print(f"'test test test test test test test test test test' -> '{match('test test test test test test test test test test')}'") # 10 times
**Explanation of the Regex:** `(\b\w+\b)(?:\s+\1){4,}\b` 1. `(\b\w+\b)`: This is the first capturing group (`group(1)`). * `\b`: Matches a word boundary. This ensures we match whole words (e.g., it won't match `cat` inside `catalog`). * `\w+`: Matches one or more "word" characters (letters, numbers, and underscore). * `\b`: Matches another word boundary at the end of the word. * The parentheses `()` capture the matched word so we can refer back to it. 2. `(?:\s+\1)`: This is a non-capturing group `(?:...)`. * `\s+`: Matches one or more whitespace characters (spaces, tabs, newlines). This requires the repeated words to be separated by whitespace. * `\1`: This is a backreference to whatever text was captured by the first capturing group (`group(1)`). It ensures we are matching the *exact same word* again. 3. `{4,}`: This is a quantifier applied to the preceding non-capturing group `(?:\s+\1)`. * It means "match the preceding group 4 or more times". * Since the first group `(\b\w+\b)` matches the *first* occurrence of the word, and this part matches *4 or more subsequent occurrences* (each preceded by whitespace), the total number of consecutive word occurrences will be 1 + 4 = 5 or more. 4. `\b`: This final word boundary ensures that the *last* matched repetition of the word also ends at a word boundary. This prevents partial matches like matching `go go go go gogo` as five repetitions of `go`. 5. `re.search()`: This function scans the string looking for the *first* location where the regex pattern produces a match, and returns a corresponding match object, or `None` if no position in the string matches the pattern. 6. `search_result.group(1)`: If a match is found, `group(1)` returns the substring that was captured by the first capturing group `(\b\w+\b)`, which is the word that was repeated.

Extract Code

I extracted the following code from that output: 

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import re

def match(text: str) -> str:
  """
  Uses a regex to find the first word repeated consecutively 5 or more times.

  Args:
    text: The input string to search within.

  Returns:
    The repeated word if found (repeated 5 or more times consecutively),
    otherwise an empty string.
  """
  # Regex breakdown:
  # (\b\w+\b) : Capture group 1: Match a whole word.
  #             \b ensures it's a whole word (word boundary).
  #             \w+ matches one or more alphanumeric characters (letters, numbers, _).
  # (?:\s+\1) : Non-capturing group:
  #             \s+ matches one or more whitespace characters (space, tab, newline etc.)
  #             \1 is a backreference to the exact text matched by capture group 1 (the word).
  # {4,}      : Quantifier: Match the preceding non-capturing group (whitespace + same word)
  #             4 or more times.
  #             This means the word appears 1 (from group 1) + 4 (from repetitions) = 5 or more times total.
  # \b        : Ensure the last repetition also ends at a word boundary. This prevents matching
  #             "go go go go gogo" as 5 repetitions of "go".
  pattern = r"(\b\w+\b)(?:\s+\1){4,}\b"

  search_result = re.search(pattern, text)

  if search_result:
    # Group 1 contains the word itself that was repeated
    return search_result.group(1)
  else:
    # No match found
    return ""

# Example Usage:
print(f"'hello hello hello hello hello world' -> '{match('hello hello hello hello hello world')}'")
print(f"'test test test test' -> '{match('test test test test')}'") # Only 4 times
print(f"'go go go go go go' -> '{match('go go go go go go')}'") # 6 times >= 5
print(f"'word word word word word.' -> '{match('word word word word word.')}'") # Punctuation acts as boundary
print(f"'abcabcabcabcabc' -> '{match('abcabcabcabcabc')}'") # Not separated by spaces
print(f"' one one one one one two' -> '{match(' one one one one one two')}'")
print(f"' five five five five fivefive' -> '{match(' five five five five fivefive')}'") # Last one isn't whole word
print(f"'no repeats here' -> '{match('no repeats here')}'")
print(f"'' -> '{match('')}'")
print(f"'repeat repeat repeat repeat repeat! yes' -> '{match('repeat repeat repeat repeat repeat! yes')}'")
print(f"'test test test test test test test test test test' -> '{match('test test test test test test test test test test')}'") # 10 times

Run Code Interpreter

Running the following program: 

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import re

def match(text: str) -> str:
  """
  Uses a regex to find the first word repeated consecutively 5 or more times.

  Args:
    text: The input string to search within.

  Returns:
    The repeated word if found (repeated 5 or more times consecutively),
    otherwise an empty string.
  """
  # Regex breakdown:
  # (\b\w+\b) : Capture group 1: Match a whole word.
  #             \b ensures it's a whole word (word boundary).
  #             \w+ matches one or more alphanumeric characters (letters, numbers, _).
  # (?:\s+\1) : Non-capturing group:
  #             \s+ matches one or more whitespace characters (space, tab, newline etc.)
  #             \1 is a backreference to the exact text matched by capture group 1 (the word).
  # {4,}      : Quantifier: Match the preceding non-capturing group (whitespace + same word)
  #             4 or more times.
  #             This means the word appears 1 (from group 1) + 4 (from repetitions) = 5 or more times total.
  # \b        : Ensure the last repetition also ends at a word boundary. This prevents matching
  #             "go go go go gogo" as 5 repetitions of "go".
  pattern = r"(\b\w+\b)(?:\s+\1){4,}\b"

  search_result = re.search(pattern, text)

  if search_result:
    # Group 1 contains the word itself that was repeated
    return search_result.group(1)
  else:
    # No match found
    return ""

# Example Usage:
print(f"'hello hello hello hello hello world' -> '{match('hello hello hello hello hello world')}'")
print(f"'test test test test' -> '{match('test test test test')}'") # Only 4 times
print(f"'go go go go go go' -> '{match('go go go go go go')}'") # 6 times >= 5
print(f"'word word word word word.' -> '{match('word word word word word.')}'") # Punctuation acts as boundary
print(f"'abcabcabcabcabc' -> '{match('abcabcabcabcabc')}'") # Not separated by spaces
print(f"' one one one one one two' -> '{match(' one one one one one two')}'")
print(f"' five five five five fivefive' -> '{match(' five five five five fivefive')}'") # Last one isn't whole word
print(f"'no repeats here' -> '{match('no repeats here')}'")
print(f"'' -> '{match('')}'")
print(f"'repeat repeat repeat repeat repeat! yes' -> '{match('repeat repeat repeat repeat repeat! yes')}'")
print(f"'test test test test test test test test test test' -> '{match('test test test test test test test test test test')}'") # 10 times





answer = match('hi hi hi hi hi')
expected = "hi"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hi hi hi hi')
expected = ""
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hello this is is is is is a test')
expected = "is"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: 'hello hello hello hello hello world' -> 'hello' 'test test test test' -> '' 'go go go go go go' -> 'go' 'word word word word word.' -> 'word' 'abcabcabcabcabc' -> '' ' one one one one one two' -> 'one' ' five five five five fivefive' -> '' 'no repeats here' -> '' '' -> '' 'repeat repeat repeat repeat repeat! yes' -> 'repeat' 'test test test test test test test test test test' -> 'test' All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True