Initial Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

LLM Generation

Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

Output

# Word Repetition Finder I'll write a Python function that uses regex to find any word repeated 5 times or more in a row and returns that word. 

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import re

def match(text):
    """
    Finds a word that is repeated 5 or more times consecutively in the text.
    
    Args:
        text (str): The input text to search
        
    Returns:
        str: The word that's repeated 5+ times, or empty string if none found
    """
    # Pattern explanation:
    # \b(\w+)\b - Captures a word between word boundaries
    # (?:\s+\1\b){4,} - Looks for the same word (referenced by \1) repeated 4 or more times
    # This gives us a total of 5+ occurrences of the word
    pattern = r'\b(\w+)\b(?:\s+\1\b){4,}'
    
    # Search for the pattern in the text
    match = re.search(pattern, text, re.IGNORECASE)
    
    # Return the found word or empty string
    if match:
        return match.group(1)
    else:
        return ""
## Examples: 
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# Should return "hello"
match("hello hello hello hello hello world") 

# Should return "test"
match("this is a test test test test test of regex") 

# Should return empty string - only 4 repetitions
match("word word word word is not enough") 

# Should return empty string - not consecutive
match("word another word another word another word another word")
The function uses a regex pattern that captures a word and then checks if it's followed by at least 4 more occurrences of the same word, making for a total of 5+ occurrences.

Extract Code

I extracted the following code from that output: 

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import re

def match(text):
    """
    Finds a word that is repeated 5 or more times consecutively in the text.
    
    Args:
        text (str): The input text to search
        
    Returns:
        str: The word that's repeated 5+ times, or empty string if none found
    """
    # Pattern explanation:
    # \b(\w+)\b - Captures a word between word boundaries
    # (?:\s+\1\b){4,} - Looks for the same word (referenced by \1) repeated 4 or more times
    # This gives us a total of 5+ occurrences of the word
    pattern = r'\b(\w+)\b(?:\s+\1\b){4,}'
    
    # Search for the pattern in the text
    match = re.search(pattern, text, re.IGNORECASE)
    
    # Return the found word or empty string
    if match:
        return match.group(1)
    else:
        return ""

Run Code Interpreter

Running the following program: 

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import re

def match(text):
    """
    Finds a word that is repeated 5 or more times consecutively in the text.
    
    Args:
        text (str): The input text to search
        
    Returns:
        str: The word that's repeated 5+ times, or empty string if none found
    """
    # Pattern explanation:
    # \b(\w+)\b - Captures a word between word boundaries
    # (?:\s+\1\b){4,} - Looks for the same word (referenced by \1) repeated 4 or more times
    # This gives us a total of 5+ occurrences of the word
    pattern = r'\b(\w+)\b(?:\s+\1\b){4,}'
    
    # Search for the pattern in the text
    match = re.search(pattern, text, re.IGNORECASE)
    
    # Return the found word or empty string
    if match:
        return match.group(1)
    else:
        return ""





answer = match('hi hi hi hi hi')
expected = "hi"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hi hi hi hi')
expected = ""
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hello this is is is is is a test')
expected = "is"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

LLM Generation

Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

Output

# Function to Find Words Repeated 5+ Times Here's a solution that uses regular expressions to find words repeated 5 or more times: 

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import re
from collections import Counter

def match(text):
    # Use regex to find all words in the text
    words = re.findall(r'\b\w+\b', text.lower())
    
    # Count occurrences of each word
    word_counts = Counter(words)
    
    # Find any word that appears 5 times or more
    for word, count in word_counts.items():
        if count >= 5:
            return word
    
    # If no word appears 5 times or more, return an empty string
    return ""
## How It Works 1. The function extracts all words using the regex pattern `\b\w+\b`, which matches word boundaries and word characters 2. Words are converted to lowercase to ensure case-insensitive matching 3. The Counter class efficiently tallies word occurrences 4. The function returns the first word that appears 5+ times, or an empty string if none do ## Example Usage: 
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# Examples
print(match("one two three four five"))  # Returns ""
print(match("cat dog cat dog cat dog cat dog cat"))  # Returns "cat"
print(match("the the the the the quick brown fox"))  # Returns "the"

Extract Code

I extracted the following code from that output: 

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import re
from collections import Counter

def match(text):
    # Use regex to find all words in the text
    words = re.findall(r'\b\w+\b', text.lower())
    
    # Count occurrences of each word
    word_counts = Counter(words)
    
    # Find any word that appears 5 times or more
    for word, count in word_counts.items():
        if count >= 5:
            return word
    
    # If no word appears 5 times or more, return an empty string
    return ""

Run Code Interpreter

Running the following program: 

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import re
from collections import Counter

def match(text):
    # Use regex to find all words in the text
    words = re.findall(r'\b\w+\b', text.lower())
    
    # Count occurrences of each word
    word_counts = Counter(words)
    
    # Find any word that appears 5 times or more
    for word, count in word_counts.items():
        if count >= 5:
            return word
    
    # If no word appears 5 times or more, return an empty string
    return ""





answer = match('hi hi hi hi hi')
expected = "hi"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hi hi hi hi')
expected = ""
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hello this is is is is is a test')
expected = "is"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True