Initial Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

LLM Generation

Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

Output

Here's a Python function that uses a regular expression to find words repeated 5 times or more: 

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import re

def match(text):
    # Find words repeated 5 or more times
    # Use word boundary \b to ensure we match whole words
    # (\b\w+\b) captures the word
    # (?:\s+\1){4,} matches the same word repeated at least 4 more times
    pattern = r'\b(\w+)\b(?:\s+\1){4,}'
    
    # Search for the pattern in the text
    match = re.search(pattern, text)
    
    # Return the matched word or empty string
    return match.group(1) if match else ''
Here's how the function works: - `\b(\w+)\b` captures a whole word - `\b` ensures word boundaries - `(\w+)` captures one or more word characters - The parentheses create a capture group - `(?:\s+\1){4,}` matches the same word repeated at least 4 more times - `\s+` matches one or more whitespace characters - `\1` refers to the first capture group (the word) - `{4,}` means "4 or more times" Examples: 
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# Test cases
print(match("a a a a a b b"))  # Returns "a"
print(match("a a a a b b b b b"))  # Returns ""
print(match("dog dog dog dog dog cat cat"))  # Returns "dog"
print(match("the the the the the the"))  # Returns "the"
print(match("a b c"))  # Returns ""
Key points: - Uses `re.search()` to find the first match - Returns the repeated word if found - Returns an empty string if no word is repeated 5 times - Works with words separated by whitespace - Case-sensitive matching The function efficiently handles different scenarios: - Multiple repeated words - Words at the beginning or middle of the text - Words with different surrounding text Time complexity is O(n), where n is the length of the input text, as it does a single pass through the text using regex.

Extract Code

I extracted the following code from that output: 

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import re

def match(text):
    # Find words repeated 5 or more times
    # Use word boundary \b to ensure we match whole words
    # (\b\w+\b) captures the word
    # (?:\s+\1){4,} matches the same word repeated at least 4 more times
    pattern = r'\b(\w+)\b(?:\s+\1){4,}'
    
    # Search for the pattern in the text
    match = re.search(pattern, text)
    
    # Return the matched word or empty string
    return match.group(1) if match else ''

Run Code Interpreter

Running the following program: 

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import re

def match(text):
    # Find words repeated 5 or more times
    # Use word boundary \b to ensure we match whole words
    # (\b\w+\b) captures the word
    # (?:\s+\1){4,} matches the same word repeated at least 4 more times
    pattern = r'\b(\w+)\b(?:\s+\1){4,}'
    
    # Search for the pattern in the text
    match = re.search(pattern, text)
    
    # Return the matched word or empty string
    return match.group(1) if match else ''





answer = match('hi hi hi hi hi')
expected = "hi"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hi hi hi hi')
expected = ""
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hello this is is is is is a test')
expected = "is"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

LLM Generation

Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

Output

Here's a Python function that uses a regular expression to find words repeated 5 times or more in a given text: 

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import re

def match(text):
    # Find words that are repeated 5 or more times
    pattern = r'\b(\w+)\b(?:\s+\1\b){4,}'
    
    # Search for the pattern in the text
    match = re.search(pattern, text)
    
    # Return the matched word or an empty string
    return match.group(1) if match else ''
Let's break down the solution: 1. We import the `re` module for regular expression operations. 2. The regex pattern `r'\b(\w+)\b(?:\s+\1\b){4,}'` does the following: - `\b(\w+)\b` captures a whole word - `(?:\s+\1\b){4,}` looks for that same word repeated at least 4 more times (with spaces between), which means 5 total repetitions 3. `re.search()` finds the first match in the text. 4. If a match is found, `match.group(1)` returns the repeated word. If no match, it returns an empty string. Here are some example uses: 
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# Examples
print(match("dog dog dog dog dog"))  # Returns "dog"
print(match("a b c"))  # Returns ""
print(match("hello hello hello hello hello world"))  # Returns "hello"
print(match("one two one two one two one two one two"))  # Returns "one"
Key points: - `\b` ensures we match whole words - `\w+` matches one or more word characters - `\1` is a backreference to the first captured group - `{4,}` means "4 or more times" in addition to the first occurrence The function efficiently finds the first word that's repeated exactly 5 or more times, returning that word or an empty string if no such word exists. Some additional test cases: 
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assert match("dog dog dog dog dog") == "dog"
assert match("a b c") == ""
assert match("hello hello hello hello hello world") == "hello"
assert match("one two one two one two one two one two") == "one"

Extract Code

I extracted the following code from that output: 

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import re

def match(text):
    # Find words that are repeated 5 or more times
    pattern = r'\b(\w+)\b(?:\s+\1\b){4,}'
    
    # Search for the pattern in the text
    match = re.search(pattern, text)
    
    # Return the matched word or an empty string
    return match.group(1) if match else ''

Run Code Interpreter

Running the following program: 

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import re

def match(text):
    # Find words that are repeated 5 or more times
    pattern = r'\b(\w+)\b(?:\s+\1\b){4,}'
    
    # Search for the pattern in the text
    match = re.search(pattern, text)
    
    # Return the matched word or an empty string
    return match.group(1) if match else ''





answer = match('hi hi hi hi hi')
expected = "hi"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hi hi hi hi')
expected = ""
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hello this is is is is is a test')
expected = "is"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

LLM Generation

Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

Output

Here's a Python function that uses a regular expression to find words repeated 5 times or more: 

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import re

def match(text):
    # Use regex to find words repeated 5 or more times
    # \b defines a word boundary
    # (\w+) captures the word
    # (?:\s+\1){4,} looks for the same word repeated at least 4 more times
    pattern = r'\b(\w+)(?:\s+\1){4,}\b'
    
    # Search for the pattern in the text
    match = re.search(pattern, text)
    
    # Return the matched word or an empty string
    return match.group(1) if match else ''
Let's break down the regex pattern: - `\b` ensures we're matching whole words - `(\w+)` captures a word - `(?:\s+\1){4,}` looks for the same word repeated at least 4 more times - `\s+` allows for one or more spaces between repetitions - `\1` refers to the first captured group (the word) - `{4,}` means at least 4 more repetitions Here are some example uses: 
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# Examples
print(match("a a a a a"))  # Returns "a"
print(match("a a a a b"))  # Returns ""
print(match("dog dog dog dog dog"))  # Returns "dog"
print(match("cat cat cat cat dog dog dog dog dog"))  # Returns "dog"
print(match("the the the the the cat"))  # Returns "the"
print(match("word word word word"))  # Returns ""
Key points: - The function returns the first word found that's repeated 5 times - If no word is repeated 5 times, it returns an empty string - It uses word boundaries to ensure whole word matches - The regex is case-sensitive Alternative implementation with a bit more explicit counting: 
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import re

def match(text):
    # Split the text into words
    words = text.split()
    
    # Count word frequencies
    word_counts = {}
    for word in words:
        word_counts[word] = word_counts.get(word, 0) + 1
    
    # Find first word repeated 5 or more times
    for word, count in word_counts.items():
        if count >= 5:
            return word
    
    # Return empty string if no word repeated 5 times
    return ''
This alternative approach might be more readable and potentially more performant for very large texts, as it only does a single pass through the words. The first regex solution is more concise and typically faster for most use cases, especially with shorter texts.

Extract Code

I extracted the following code from that output: 

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import re

def match(text):
    # Use regex to find words repeated 5 or more times
    # \b defines a word boundary
    # (\w+) captures the word
    # (?:\s+\1){4,} looks for the same word repeated at least 4 more times
    pattern = r'\b(\w+)(?:\s+\1){4,}\b'
    
    # Search for the pattern in the text
    match = re.search(pattern, text)
    
    # Return the matched word or an empty string
    return match.group(1) if match else ''

Run Code Interpreter

Running the following program: 

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import re

def match(text):
    # Use regex to find words repeated 5 or more times
    # \b defines a word boundary
    # (\w+) captures the word
    # (?:\s+\1){4,} looks for the same word repeated at least 4 more times
    pattern = r'\b(\w+)(?:\s+\1){4,}\b'
    
    # Search for the pattern in the text
    match = re.search(pattern, text)
    
    # Return the matched word or an empty string
    return match.group(1) if match else ''





answer = match('hi hi hi hi hi')
expected = "hi"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hi hi hi hi')
expected = ""
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hello this is is is is is a test')
expected = "is"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

LLM Generation

Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

Output

Here's a Python function that uses a regex to find any word repeated 5 times or more: 

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import re

def match(text):
    # Find words that are repeated at least 5 times
    pattern = r'\b(\w+)\b(?:\s+\1){4,}'
    
    # Search for the pattern in the text
    match = re.search(pattern, text)
    
    # Return the matched word or an empty string
    return match.group(1) if match else ''
Let's break down the regex pattern and the function: 1. `\b(\w+)\b`: - `\b` ensures we match whole words - `(\w+)` captures one or more word characters - The parentheses create a capture group 2. `(?:\s+\1){4,}`: - `(?:\s+\1)` matches the same word with whitespace in between - `{4,}` means this pattern repeats at least 4 more times (so 5 total occurrences) - `(?:...)` is a non-capturing group Examples: 
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# Examples of usage
print(match("a a a a a b b"))          # Returns "a"
print(match("a a a a b b b b b"))      # Returns "b"
print(match("a b c"))                  # Returns ""
print(match("word word word word word")) # Returns "word"
print(match("the the the the the quick brown fox"))  # Returns "the"
The function works as follows: 1. It uses `re.search()` to find the first occurrence of a word repeated at least 5 times 2. If found, it returns the repeated word 3. If no such word is found, it returns an empty string A few key points: - The regex allows for words separated by any amount of whitespace - It only matches whole words - It returns the first word found that meets the criteria - It's case-sensitive (so "Word" and "word" would be considered different) You can modify the regex or add flags if you want different behavior, such as case-insensitive matching or stricter word boundaries.

Extract Code

I extracted the following code from that output: 

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import re

def match(text):
    # Find words that are repeated at least 5 times
    pattern = r'\b(\w+)\b(?:\s+\1){4,}'
    
    # Search for the pattern in the text
    match = re.search(pattern, text)
    
    # Return the matched word or an empty string
    return match.group(1) if match else ''

Run Code Interpreter

Running the following program: 

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import re

def match(text):
    # Find words that are repeated at least 5 times
    pattern = r'\b(\w+)\b(?:\s+\1){4,}'
    
    # Search for the pattern in the text
    match = re.search(pattern, text)
    
    # Return the matched word or an empty string
    return match.group(1) if match else ''





answer = match('hi hi hi hi hi')
expected = "hi"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hi hi hi hi')
expected = ""
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hello this is is is is is a test')
expected = "is"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

LLM Generation

Query

Write a function called `match` in Python that uses a regex to find any word repeated 5 times or more. Return that word. If no word is repeated 5 times or more, return an empty string.

Output

Here's a Python function that uses regex to find words repeated 5 times or more: 

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import re

def match(text):
    # Find words that are repeated 5 or more times
    pattern = r'\b(\w+)\b(?:\s+\1){4,}'
    
    # Search for the pattern in the text
    match = re.search(pattern, text)
    
    # Return the matched word or an empty string
    return match.group(1) if match else ''
Let's break down the solution: 1. We import the `re` module for regular expression operations. 2. The regex pattern `r'\b(\w+)\b(?:\s+\1){4,}'` does the following: - `\b(\w+)\b`: Captures a whole word (word boundary before and after) - `(?:\s+\1){4,}`: Matches the same word repeated at least 4 more times - `(?:...)` is a non-capturing group - `\s+` matches one or more whitespace characters - `\1` refers back to the first captured group (the word) - `{4,}` means "4 or more times" 3. `re.search()` finds the first match in the text 4. If a match is found, we return the captured word using `match.group(1)` - If no match is found, we return an empty string Here are some example use cases: 
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# Examples
print(match("the cat cat cat cat cat is cute"))  # Returns "cat"
print(match("a b c d"))  # Returns ""
print(match("word word word word word extra"))  # Returns "word"
print(match("hello hello hello hello world"))  # Returns ""
Key points: - The function finds words repeated exactly 5 times or more - It works with any word characters - It's case-sensitive - It checks for whole word matches (not parts of words) The regex ensures that: - The word is captured as a whole - The word is repeated at least 4 additional times (total of 5) - It works with different types of text and words Time complexity is O(n), where n is the length of the input text, as it uses a single pass regex search.

Extract Code

I extracted the following code from that output: 

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import re

def match(text):
    # Find words that are repeated 5 or more times
    pattern = r'\b(\w+)\b(?:\s+\1){4,}'
    
    # Search for the pattern in the text
    match = re.search(pattern, text)
    
    # Return the matched word or an empty string
    return match.group(1) if match else ''

Run Code Interpreter

Running the following program: 

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import re

def match(text):
    # Find words that are repeated 5 or more times
    pattern = r'\b(\w+)\b(?:\s+\1){4,}'
    
    # Search for the pattern in the text
    match = re.search(pattern, text)
    
    # Return the matched word or an empty string
    return match.group(1) if match else ''





answer = match('hi hi hi hi hi')
expected = "hi"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hi hi hi hi')
expected = ""
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'

answer = match('hello this is is is is is a test')
expected = "is"
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True