Convert this to c def foo(x): sum = 0 for i in range(x): x += i sum += x return sum
Convert this to c def foo(x): sum = 0 for i in range(x): x += i sum += x return sum
To convert the given Python function to C, we need to account for the fact that the loop in the original code runs a fixed number of times based on the initial value of `x`, even though `x` is modified within the loop. Here's the equivalent C code:
1 2 3 4 5 6 7 8 9 | int foo(int x) { int sum = 0; int original_x = x; // Store the initial value of x for (int i = 0; i < original_x; i++) { x += i; sum += x; } return sum; } |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 | int foo(int x) { int sum = 0; int original_x = x; // Store the initial value of x for (int i = 0; i < original_x; i++) { x += i; sum += x; } return sum; } |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 | int foo(int x) { int sum = 0; int original_x = x; // Store the initial value of x for (int i = 0; i < original_x; i++) { x += i; sum += x; } return sum; } #include<stdio.h> #include<stdlib.h> int main() { int answer = foo(10); int expected = 265; if (answer != expected) { printf("Wrong answer; got %d instead of %d.\n", answer, expected); exit(1); } printf("All tests passed\n"); } |
All tests passed
Testing if the previous output contains the string All tests passed
: True