Initial Query

Write a C++ class Const, Square, Print so that I can write, for example, Cost(5) >> Square() >> Inc() >> Inc() >> Print() and the resulting python program will print 27 to the screen.

LLM Generation

Query

Write a C++ class Const, Square, Print so that I can write, for example, Cost(5) >> Square() >> Inc() >> Inc() >> Print() and the resulting python program will print 27 to the screen.

Output

It seems like you're asking for a C++ implementation, but you mentioned a Python program in your question. I'll provide a C++ solution since that's what the context suggests. In C++, you can achieve this by using function chaining, which is a common technique in fluent interfaces. Here's a simple implementation: 

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#include <iostream>

class Const {
public:
    explicit Const(int value) : value_(value) {}

    Const& operator>> (const Square& sq) {
        value_ = sq.operate(value_);
        return *this;
    }

    Const& operator>> (const Inc& inc) {
        value_ = inc.operate(value_);
        return *this;
    }

    void print() const {
        std::cout << value_ << std::endl;
    }

private:
    int value_;
};

struct Square {
    int operate(int value) const {
        return value * value;
    }
};

struct Inc {
    int operate(int value) const {
        return value + 1;
    }
};

// Helper function to create a Const object
Const Cost(int value) {
    return Const(value);
}

int main() {
    Cost(5) >> Square() >> Inc() >> Inc() >> Print();
    return 0;
}
In this code, `Cost`, `Square`, `Inc`, and `Print` are not classes, but either a function returning a `Const` object or structures used in the function chaining. The `operator>>` is overloaded to call the `operate` function of `Square` and `Inc` structures, which performs the square and increment operations, respectively. The `Print` function is a member function of the `Const` class that prints the final result.

Extract Code

I extracted the following code from that output: 

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#include <iostream>

class Const {
public:
    explicit Const(int value) : value_(value) {}

    Const& operator>> (const Square& sq) {
        value_ = sq.operate(value_);
        return *this;
    }

    Const& operator>> (const Inc& inc) {
        value_ = inc.operate(value_);
        return *this;
    }

    void print() const {
        std::cout << value_ << std::endl;
    }

private:
    int value_;
};

struct Square {
    int operate(int value) const {
        return value * value;
    }
};

struct Inc {
    int operate(int value) const {
        return value + 1;
    }
};

// Helper function to create a Const object
Const Cost(int value) {
    return Const(value);
}

int main() {
    Cost(5) >> Square() >> Inc() >> Inc() >> Print();
    return 0;
}

Run Code Interpreter

Running the following program: 

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#include <iostream>

class Const {
public:
    explicit Const(int value) : value_(value) {}

    Const& operator>> (const Square& sq) {
        value_ = sq.operate(value_);
        return *this;
    }

    Const& operator>> (const Inc& inc) {
        value_ = inc.operate(value_);
        return *this;
    }

    void print() const {
        std::cout << value_ << std::endl;
    }

private:
    int value_;
};

struct Square {
    int operate(int value) const {
        return value * value;
    }
};

struct Inc {
    int operate(int value) const {
        return value + 1;
    }
};

// Helper function to create a Const object
Const Cost(int value) {
    return Const(value);
}

int __delete_this__main() {
    Cost(5) >> Square() >> Inc() >> Inc() >> Print();
    return 0;
}



int main() {
Const(2) >> Square() >> Inc() >> Square() >> Square() >> Print();
return 0;
}
And got the output: main.cpp:8:30: error: 'Square' does not name a type 8 | Const& operator>> (const Square& sq) { | ^~~~~~ main.cpp:13:30: error: 'Inc' does not name a type 13 | Const& operator>> (const Inc& inc) { | ^~~ main.cpp:13:12: error: 'Const& Const::operator>>(const int&)' cannot be overloaded with 'Const& Const::operator>>(const int&)' 13 | Const& operator>> (const Inc& inc) { | ^~~~~~~~ main.cpp:8:12: note: previous declaration 'Const& Const::operator>>(const int&)' 8 | Const& operator>> (const Square& sq) { | ^~~~~~~~ main.cpp: In member function 'Const& Const::operator>>(const int&)': main.cpp:9:21: error: request for member 'operate' in 'sq', which is of non-class type 'const int' 9 | value_ = sq.operate(value_); | ^~~~~~~ main.cpp: In member function 'Const& Const::operator>>(const int&)': main.cpp:14:22: error: request for member 'operate' in 'inc', which is of non-class type 'const int' 14 | value_ = inc.operate(value_); | ^~~~~~~ main.cpp: In function 'int __delete_this__main()': main.cpp:44:13: error: no match for 'operator>>' (operand types are 'Const' and 'Square') 44 | Cost(5) >> Square() >> Inc() >> Inc() >> Print(); | ~~~~~~~ ^~ ~~~~~~~~ | | | | Const Square main.cpp:8:12: note: candidate: 'Const& Const::operator>>(const int&)' 8 | Const& operator>> (const Square& sq) { | ^~~~~~~~ main.cpp:8:38: note: no known conversion for argument 1 from 'Square' to 'const int&' 8 | Const& operator>> (const Square& sq) { | ~~~~~~~~~~~~~~^~ main.cpp:44:46: error: 'Print' was not declared in this scope; did you mean 'printf'? 44 | Cost(5) >> Square() >> Inc() >> Inc() >> Print(); | ^~~~~ | printf main.cpp: In function 'int main()': main.cpp:51:10: error: no match for 'operator>>' (operand types are 'Const' and 'Square') 51 | Const(2) >> Square() >> Inc() >> Square() >> Square() >> Print(); | ~~~~~~~~ ^~ ~~~~~~~~ | | | | Const Square main.cpp:8:12: note: candidate: 'Const& Const::operator>>(const int&)' 8 | Const& operator>> (const Square& sq) { | ^~~~~~~~ main.cpp:8:38: note: no known conversion for argument 1 from 'Square' to 'const int&' 8 | Const& operator>> (const Square& sq) { | ~~~~~~~~~~~~~~^~ main.cpp:51:58: error: 'Print' was not declared in this scope; did you mean 'printf'? 51 | Const(2) >> Square() >> Inc() >> Square() >> Square() >> Print(); | ^~~~~ | printf main.sh: line 2: ./a.out: No such file or directory

Substring Evaluation

Testing if the previous output contains the string 625: False

Initial Query

Write a C++ class Const, Square, Print so that I can write, for example, Cost(5) >> Square() >> Inc() >> Inc() >> Print() and the resulting python program will print 27 to the screen.

LLM Generation

Query

Write a C++ class Const, Square, Print so that I can write, for example, Cost(5) >> Square() >> Inc() >> Inc() >> Print() and the resulting python program will print 27 to the screen.

Output

Sure, I can help you design classes in C++ that would behave similarly to your example. However, it's important to note that C++ doesn't support method chaining in the same way as Python. We can achieve this by returning a reference to the current object from each method (often called a fluent interface). Here's a simple implementation: 

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#include <iostream>

class Const {
public:
    explicit Const(int value) : value_(value) {}

    Const& operator>>(const Square&) {
        value_ *= value_;
        return *this;
    }

    Const& Inc() {
        ++value_;
        return *this;
    }

    void Print() const {
        std::cout << value_ << std::endl;
    }

private:
    int value_;
};

struct Square {};

int main() {
    Const(5) >> Square() >> Const::Inc() >> Const::Inc() >> Const::Print();
    return 0;
}
In this code: - `Const` is a class that holds an integer value. - `Square` is an empty struct that we use to trigger the squaring operation when used with the `>>` operator. - The `>>` operator is overloaded to square the value when a `Square` object is on the right-hand side. - The `Inc` method increments the value and returns a reference to the current object, allowing method chaining. - The `Print` method prints the value to the standard output.

Extract Code

I extracted the following code from that output: 

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#include <iostream>

class Const {
public:
    explicit Const(int value) : value_(value) {}

    Const& operator>>(const Square&) {
        value_ *= value_;
        return *this;
    }

    Const& Inc() {
        ++value_;
        return *this;
    }

    void Print() const {
        std::cout << value_ << std::endl;
    }

private:
    int value_;
};

struct Square {};

int main() {
    Const(5) >> Square() >> Const::Inc() >> Const::Inc() >> Const::Print();
    return 0;
}

Run Code Interpreter

Running the following program: 

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#include <iostream>

class Const {
public:
    explicit Const(int value) : value_(value) {}

    Const& operator>>(const Square&) {
        value_ *= value_;
        return *this;
    }

    Const& Inc() {
        ++value_;
        return *this;
    }

    void Print() const {
        std::cout << value_ << std::endl;
    }

private:
    int value_;
};

struct Square {};

int __delete_this__main() {
    Const(5) >> Square() >> Const::Inc() >> Const::Inc() >> Const::Print();
    return 0;
}



int main() {
Const(2) >> Square() >> Inc() >> Square() >> Square() >> Print();
return 0;
}
And got the output: main.cpp:8:29: error: 'Square' does not name a type 8 | Const& operator>>(const Square&) { | ^~~~~~ main.cpp: In function 'int __delete_this__main()': main.cpp:29:14: error: no match for 'operator>>' (operand types are 'Const' and 'Square') 29 | Const(5) >> Square() >> Const::Inc() >> Const::Inc() >> Const::Print(); | ~~~~~~~~ ^~ ~~~~~~~~ | | | | Const Square main.cpp:8:12: note: candidate: 'Const& Const::operator>>(const int&)' 8 | Const& operator>>(const Square&) { | ^~~~~~~~ main.cpp:8:23: note: no known conversion for argument 1 from 'Square' to 'const int&' 8 | Const& operator>>(const Square&) { | ^~~~~~~~~~~~~ main.cpp:29:39: error: cannot call member function 'Const& Const::Inc()' without object 29 | Const(5) >> Square() >> Const::Inc() >> Const::Inc() >> Const::Print(); | ~~~~~~~~~~^~ main.cpp:29:55: error: cannot call member function 'Const& Const::Inc()' without object 29 | Const(5) >> Square() >> Const::Inc() >> Const::Inc() >> Const::Print(); | ~~~~~~~~~~^~ main.cpp:29:73: error: cannot call member function 'void Const::Print() const' without object 29 | Const(5) >> Square() >> Const::Inc() >> Const::Inc() >> Const::Print(); | ~~~~~~~~~~~~^~ main.cpp: In function 'int main()': main.cpp:36:10: error: no match for 'operator>>' (operand types are 'Const' and 'Square') 36 | Const(2) >> Square() >> Inc() >> Square() >> Square() >> Print(); | ~~~~~~~~ ^~ ~~~~~~~~ | | | | Const Square main.cpp:8:12: note: candidate: 'Const& Const::operator>>(const int&)' 8 | Const& operator>>(const Square&) { | ^~~~~~~~ main.cpp:8:23: note: no known conversion for argument 1 from 'Square' to 'const int&' 8 | Const& operator>>(const Square&) { | ^~~~~~~~~~~~~ main.cpp:36:25: error: 'Inc' was not declared in this scope 36 | Const(2) >> Square() >> Inc() >> Square() >> Square() >> Print(); | ^~~ main.cpp:36:58: error: 'Print' was not declared in this scope; did you mean 'printf'? 36 | Const(2) >> Square() >> Inc() >> Square() >> Square() >> Print(); | ^~~~~ | printf main.sh: line 2: ./a.out: No such file or directory

Substring Evaluation

Testing if the previous output contains the string 625: False

Initial Query

Write a C++ class Const, Square, Print so that I can write, for example, Cost(5) >> Square() >> Inc() >> Inc() >> Print() and the resulting python program will print 27 to the screen.

LLM Generation

Query

Write a C++ class Const, Square, Print so that I can write, for example, Cost(5) >> Square() >> Inc() >> Inc() >> Print() and the resulting python program will print 27 to the screen.

Output

It seems like you're trying to create a chainable interface in C++, similar to how some libraries work in Python. Here's an example of how you might implement this in C++: 

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#include <iostream>

class Const {
public:
    explicit Const(int value) : value_(value) {}

    Const& operator>>(const Square&) {
        value_ *= value_;
        return *this;
    }

    Const& operator>>(const Inc&) {
        ++value_;
        return *this;
    }

    void Print() const {
        std::cout << value_ << std::endl;
    }

private:
    int value_;
};

struct Square {};
struct Inc {};

int main() {
    Const(5) >> Square() >> Inc() >> Inc() >> Print();
    return 0;
}
In this code: - `Const` is a class that holds an integer value. It has overloaded `operator>>` to allow chaining with `Square` and `Inc` structures. - `Square` and `Inc` are empty structures that are used to trigger the squaring and incrementing operations, respectively. - `Print` is a method of `Const` that prints the current value to the standard output. - In the `main` function, we create a `Const` object with the value 5, then square it, increment it twice, and print the result.

Extract Code

I extracted the following code from that output: 

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#include <iostream>

class Const {
public:
    explicit Const(int value) : value_(value) {}

    Const& operator>>(const Square&) {
        value_ *= value_;
        return *this;
    }

    Const& operator>>(const Inc&) {
        ++value_;
        return *this;
    }

    void Print() const {
        std::cout << value_ << std::endl;
    }

private:
    int value_;
};

struct Square {};
struct Inc {};

int main() {
    Const(5) >> Square() >> Inc() >> Inc() >> Print();
    return 0;
}

Run Code Interpreter

Running the following program: 

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#include <iostream>

class Const {
public:
    explicit Const(int value) : value_(value) {}

    Const& operator>>(const Square&) {
        value_ *= value_;
        return *this;
    }

    Const& operator>>(const Inc&) {
        ++value_;
        return *this;
    }

    void Print() const {
        std::cout << value_ << std::endl;
    }

private:
    int value_;
};

struct Square {};
struct Inc {};

int __delete_this__main() {
    Const(5) >> Square() >> Inc() >> Inc() >> Print();
    return 0;
}



int main() {
Const(2) >> Square() >> Inc() >> Square() >> Square() >> Print();
return 0;
}
And got the output: main.cpp:8:29: error: 'Square' does not name a type 8 | Const& operator>>(const Square&) { | ^~~~~~ main.cpp:13:29: error: 'Inc' does not name a type 13 | Const& operator>>(const Inc&) { | ^~~ main.cpp:13:12: error: 'Const& Const::operator>>(const int&)' cannot be overloaded with 'Const& Const::operator>>(const int&)' 13 | Const& operator>>(const Inc&) { | ^~~~~~~~ main.cpp:8:12: note: previous declaration 'Const& Const::operator>>(const int&)' 8 | Const& operator>>(const Square&) { | ^~~~~~~~ main.cpp: In function 'int __delete_this__main()': main.cpp:30:14: error: no match for 'operator>>' (operand types are 'Const' and 'Square') 30 | Const(5) >> Square() >> Inc() >> Inc() >> Print(); | ~~~~~~~~ ^~ ~~~~~~~~ | | | | Const Square main.cpp:8:12: note: candidate: 'Const& Const::operator>>(const int&)' 8 | Const& operator>>(const Square&) { | ^~~~~~~~ main.cpp:8:23: note: no known conversion for argument 1 from 'Square' to 'const int&' 8 | Const& operator>>(const Square&) { | ^~~~~~~~~~~~~ main.cpp:30:47: error: 'Print' was not declared in this scope; did you mean 'printf'? 30 | Const(5) >> Square() >> Inc() >> Inc() >> Print(); | ^~~~~ | printf main.cpp: In function 'int main()': main.cpp:37:10: error: no match for 'operator>>' (operand types are 'Const' and 'Square') 37 | Const(2) >> Square() >> Inc() >> Square() >> Square() >> Print(); | ~~~~~~~~ ^~ ~~~~~~~~ | | | | Const Square main.cpp:8:12: note: candidate: 'Const& Const::operator>>(const int&)' 8 | Const& operator>>(const Square&) { | ^~~~~~~~ main.cpp:8:23: note: no known conversion for argument 1 from 'Square' to 'const int&' 8 | Const& operator>>(const Square&) { | ^~~~~~~~~~~~~ main.cpp:37:58: error: 'Print' was not declared in this scope; did you mean 'printf'? 37 | Const(2) >> Square() >> Inc() >> Square() >> Square() >> Print(); | ^~~~~ | printf main.sh: line 2: ./a.out: No such file or directory

Substring Evaluation

Testing if the previous output contains the string 625: False

Initial Query

Write a C++ class Const, Square, Print so that I can write, for example, Cost(5) >> Square() >> Inc() >> Inc() >> Print() and the resulting python program will print 27 to the screen.

LLM Generation

Query

Write a C++ class Const, Square, Print so that I can write, for example, Cost(5) >> Square() >> Inc() >> Inc() >> Print() and the resulting python program will print 27 to the screen.

Output

Sure, I can help you design classes in C++ that would allow you to write code in a similar style to what you've described. However, please note that C++ is not as flexible as Python when it comes to chaining methods like this, especially when it involves different classes. Here's a possible implementation: 

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#include <iostream>

class Cost {
public:
    explicit Cost(int value) : value_(value) {}
    Square operator>(Square sq) {
        sq.value_ = value_;
        return sq;
    }
private:
    int value_;
};

class Square {
public:
    Square() : value_(0) {}
    Inc operator>(Inc inc) {
        inc.value_ = value_ * value_;
        return inc;
    }
    void value(int value) { value_ = value; }
private:
    int value_;
};
class Inc {
public:
    Inc() : value_(0) {}
    Print operator>(Print pr) {
        pr.value_ = ++value_;
        return pr;
    }
    void value(int value) { value_ = value; }
};

class Print {
public:
    Print() : value_(0) {}
    void operator()() {
        std::cout << value_ << std::endl;
    }
    void value(int value) { value_ = value; }
private:
    int value_;
};

int main() {
    Cost(5) > Square() > Inc() > Inc() > Print()();
    return 0;
}
This code defines four classes: `Cost`, `Square`, `Inc`, and `Print`. Each class has an overloaded `operator>` that returns an instance of the next class in the chain. The `Print` class has an overloaded `operator()` that prints the current value. The `main` function demonstrates how to use these classes to print the square of 5, incremented twice.

Extract Code

I extracted the following code from that output: 

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#include <iostream>

class Cost {
public:
    explicit Cost(int value) : value_(value) {}
    Square operator>(Square sq) {
        sq.value_ = value_;
        return sq;
    }
private:
    int value_;
};

class Square {
public:
    Square() : value_(0) {}
    Inc operator>(Inc inc) {
        inc.value_ = value_ * value_;
        return inc;
    }
    void value(int value) { value_ = value; }
private:
    int value_;
};
class Inc {
public:
    Inc() : value_(0) {}
    Print operator>(Print pr) {
        pr.value_ = ++value_;
        return pr;
    }
    void value(int value) { value_ = value; }
};

class Print {
public:
    Print() : value_(0) {}
    void operator()() {
        std::cout << value_ << std::endl;
    }
    void value(int value) { value_ = value; }
private:
    int value_;
};

int main() {
    Cost(5) > Square() > Inc() > Inc() > Print()();
    return 0;
}

Run Code Interpreter

Running the following program: 

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#include <iostream>

class Cost {
public:
    explicit Cost(int value) : value_(value) {}
    Square operator>(Square sq) {
        sq.value_ = value_;
        return sq;
    }
private:
    int value_;
};

class Square {
public:
    Square() : value_(0) {}
    Inc operator>(Inc inc) {
        inc.value_ = value_ * value_;
        return inc;
    }
    void value(int value) { value_ = value; }
private:
    int value_;
};
class Inc {
public:
    Inc() : value_(0) {}
    Print operator>(Print pr) {
        pr.value_ = ++value_;
        return pr;
    }
    void value(int value) { value_ = value; }
};

class Print {
public:
    Print() : value_(0) {}
    void operator()() {
        std::cout << value_ << std::endl;
    }
    void value(int value) { value_ = value; }
private:
    int value_;
};

int __delete_this__main() {
    Cost(5) > Square() > Inc() > Inc() > Print()();
    return 0;
}



int main() {
Const(2) >> Square() >> Inc() >> Square() >> Square() >> Print();
return 0;
}
And got the output: main.cpp:7:5: error: 'Square' does not name a type 7 | Square operator>(Square sq) { | ^~~~~~ main.cpp:18:5: error: 'Inc' does not name a type 18 | Inc operator>(Inc inc) { | ^~~ main.cpp:29:5: error: 'Print' does not name a type 29 | Print operator>(Print pr) { | ^~~~~ main.cpp: In constructor 'Inc::Inc()': main.cpp:28:13: error: class 'Inc' does not have any field named 'value_' 28 | Inc() : value_(0) {} | ^~~~~~ main.cpp: In member function 'void Inc::value(int)': main.cpp:33:29: error: 'value_' was not declared in this scope; did you mean 'value'? 33 | void value(int value) { value_ = value; } | ^~~~~~ | value main.cpp: In function 'int __delete_this__main()': main.cpp:48:13: error: no match for 'operator>' (operand types are 'Cost' and 'Square') 48 | Cost(5) > Square() > Inc() > Inc() > Print()(); | ~~~~~~~ ^ ~~~~~~~~ | | | | Cost Square main.cpp: In function 'int main()': main.cpp:55:1: error: 'Const' was not declared in this scope; did you mean 'Cost'? 55 | Const(2) >> Square() >> Inc() >> Square() >> Square() >> Print(); | ^~~~~ | Cost main.sh: line 2: ./a.out: No such file or directory

Substring Evaluation

Testing if the previous output contains the string 625: False

Initial Query

Write a C++ class Const, Square, Print so that I can write, for example, Cost(5) >> Square() >> Inc() >> Inc() >> Print() and the resulting python program will print 27 to the screen.

LLM Generation

Query

Write a C++ class Const, Square, Print so that I can write, for example, Cost(5) >> Square() >> Inc() >> Inc() >> Print() and the resulting python program will print 27 to the screen.

Output

In C++, you can't directly chain function calls like `Cost(5) >> Square() >> Inc() >> Inc() >> Print()` as in Python. However, you can achieve similar functionality using a combination of operator overloading and function chaining. Here's a possible implementation: 

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#include <iostream>

class Const {
public:
    explicit Const(int value) : value_(value) {}

    Const& operator>>=(const Square& square) {
        value_ = value_ * value_;
        return *this;
    }

    Const& operator>>=(const Inc& inc) {
        ++value_;
        return *this;
    }

    friend std::ostream& operator<<(std::ostream& os, const Const& constObj);

private:
    int value_;
};

std::ostream& operator<<(std::ostream& os, const Const& constObj) {
    os << constObj.value_;
    return os;
}

class Square {
public:
    friend const Const& operator>>(Const& constObj, const Square& square);
};

class Inc {
public:
    friend const Const& operator>>(Const& constObj, const Inc& inc);
};

const Const& operator>>(Const& constObj, const Square& square) {
    constObj >>= square;
    return constObj;
}

const Const& operator>>(Const& constObj, const Inc& inc) {
    constObj >>= inc;
    return constObj;
}

int main() {
    Const cost(5);
    cost >> Square() >> Inc() >> Inc() >> std::cout;
    return 0;
}
In this implementation, we define a `Const` class that holds an integer value. We also define `Square` and `Inc` classes, which are used as tags to perform square and increment operations, respectively. We overload the `>>=` operator for the `Const` class to perform square and increment operations based on the tag passed as the right operand. Additionally, we overload the global `operator>>` to enable function chaining and the `operator<<` to print the `Const` object. In the `main` function, we create a `Const` object with value 5 and chain the operations as requested. The result is printed to the standard output using `std::cout`.

Extract Code

I extracted the following code from that output: 

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#include <iostream>

class Const {
public:
    explicit Const(int value) : value_(value) {}

    Const& operator>>=(const Square& square) {
        value_ = value_ * value_;
        return *this;
    }

    Const& operator>>=(const Inc& inc) {
        ++value_;
        return *this;
    }

    friend std::ostream& operator<<(std::ostream& os, const Const& constObj);

private:
    int value_;
};

std::ostream& operator<<(std::ostream& os, const Const& constObj) {
    os << constObj.value_;
    return os;
}

class Square {
public:
    friend const Const& operator>>(Const& constObj, const Square& square);
};

class Inc {
public:
    friend const Const& operator>>(Const& constObj, const Inc& inc);
};

const Const& operator>>(Const& constObj, const Square& square) {
    constObj >>= square;
    return constObj;
}

const Const& operator>>(Const& constObj, const Inc& inc) {
    constObj >>= inc;
    return constObj;
}

int main() {
    Const cost(5);
    cost >> Square() >> Inc() >> Inc() >> std::cout;
    return 0;
}

Run Code Interpreter

Running the following program: 

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#include <iostream>

class Const {
public:
    explicit Const(int value) : value_(value) {}

    Const& operator>>=(const Square& square) {
        value_ = value_ * value_;
        return *this;
    }

    Const& operator>>=(const Inc& inc) {
        ++value_;
        return *this;
    }

    friend std::ostream& operator<<(std::ostream& os, const Const& constObj);

private:
    int value_;
};

std::ostream& operator<<(std::ostream& os, const Const& constObj) {
    os << constObj.value_;
    return os;
}

class Square {
public:
    friend const Const& operator>>(Const& constObj, const Square& square);
};

class Inc {
public:
    friend const Const& operator>>(Const& constObj, const Inc& inc);
};

const Const& operator>>(Const& constObj, const Square& square) {
    constObj >>= square;
    return constObj;
}

const Const& operator>>(Const& constObj, const Inc& inc) {
    constObj >>= inc;
    return constObj;
}

int __delete_this__main() {
    Const cost(5);
    cost >> Square() >> Inc() >> Inc() >> std::cout;
    return 0;
}



int main() {
Const(2) >> Square() >> Inc() >> Square() >> Square() >> Print();
return 0;
}
And got the output: main.cpp:8:30: error: 'Square' does not name a type 8 | Const& operator>>=(const Square& square) { | ^~~~~~ main.cpp:13:30: error: 'Inc' does not name a type 13 | Const& operator>>=(const Inc& inc) { | ^~~ main.cpp:13:12: error: 'Const& Const::operator>>=(const int&)' cannot be overloaded with 'Const& Const::operator>>=(const int&)' 13 | Const& operator>>=(const Inc& inc) { | ^~~~~~~~ main.cpp:8:12: note: previous declaration 'Const& Const::operator>>=(const int&)' 8 | Const& operator>>=(const Square& square) { | ^~~~~~~~ main.cpp: In function 'const Const& operator>>(Const&, const Square&)': main.cpp:40:14: error: no match for 'operator>>=' (operand types are 'Const' and 'const Square') 40 | constObj >>= square; | ~~~~~~~~~^~~~~~~~~~ main.cpp:8:12: note: candidate: 'Const& Const::operator>>=(const int&)' 8 | Const& operator>>=(const Square& square) { | ^~~~~~~~ main.cpp:8:38: note: no known conversion for argument 1 from 'const Square' to 'const int&' 8 | Const& operator>>=(const Square& square) { | ~~~~~~~~~~~~~~^~~~~~ main.cpp: In function 'const Const& operator>>(Const&, const Inc&)': main.cpp:45:14: error: no match for 'operator>>=' (operand types are 'Const' and 'const Inc') 45 | constObj >>= inc; | ~~~~~~~~~^~~~~~~ main.cpp:8:12: note: candidate: 'Const& Const::operator>>=(const int&)' 8 | Const& operator>>=(const Square& square) { | ^~~~~~~~ main.cpp:8:38: note: no known conversion for argument 1 from 'const Inc' to 'const int&' 8 | Const& operator>>=(const Square& square) { | ~~~~~~~~~~~~~~^~~~~~ main.cpp: In function 'int __delete_this__main()': main.cpp:51:10: error: binding reference of type 'Const&' to 'const Const' discards qualifiers 51 | cost >> Square() >> Inc() >> Inc() >> std::cout; | ~~~~~^~~~~~~~~~~ main.cpp:44:32: note: initializing argument 1 of 'const Const& operator>>(Const&, const Inc&)' 44 | const Const& operator>>(Const& constObj, const Inc& inc) { | ~~~~~~~^~~~~~~~ main.cpp: In function 'int main()': main.cpp:58:1: error: cannot bind non-const lvalue reference of type 'Const&' to an rvalue of type 'Const' 58 | Const(2) >> Square() >> Inc() >> Square() >> Square() >> Print(); | ^~~~~~~~ main.cpp:39:32: note: initializing argument 1 of 'const Const& operator>>(Const&, const Square&)' 39 | const Const& operator>>(Const& constObj, const Square& square) { | ~~~~~~~^~~~~~~~ main.cpp:58:58: error: 'Print' was not declared in this scope; did you mean 'printf'? 58 | Const(2) >> Square() >> Inc() >> Square() >> Square() >> Print(); | ^~~~~ | printf main.sh: line 2: ./a.out: No such file or directory

Substring Evaluation

Testing if the previous output contains the string 625: False