Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Certainly! Below is a simple assembly language program that calculates the first 20 prime numbers and stores them in memory addresses from 0 to 19.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 | ; Program to store the first 20 prime numbers in memory addresses 0 to 19 SET R1 0 ; Counter for prime numbers found SET R2 2 ; Current number to check for primality SET R3 0 ; Index for memory address primes_loop: ; Check if R2 is prime SET R4 2 ; Start divisibility check from 2 SET R5 0 ; Flag to indicate if R2 is prime (0 = true, not prime) check_divisor: ; If R4 * R4 > R2, then R2 is prime MUL R6 R4 R4 ; R6 = R4 * R4 GTE R6 R2 ; Set flag if R6 >= R2 JT is_prime ; Jump if R2 is not prime ; Check if R2 is divisible by R4 MOD R7 R2 R4 ; R7 = R2 % R4 EQ R7 0 ; If R7 == 0, R2 is not prime JF not_prime ; Jump if R2 is not divisible by R4 INC R4 ; Increment divisor JMP check_divisor ; Continue checking not_prime: SET R5 1 ; Set flag to indicate R2 is not prime JMP primes_loop_continue is_prime: ; If prime, store it in memory EQ R5 0 ; Check if flag is still 0 (prime) JF primes_loop_continue ; If not prime, continue loop ; Store the prime number in memory STORE R2 R3 ; Store R2 at memory address R3 INC R1 ; Increment the count of primes found INC R3 ; Move to the next memory address primes_loop_continue: INC R2 ; Move to the next number EQ R1 20 ; Check if we've found 20 primes JTE HCF ; If yes, halt the program JMP primes_loop ; Repeat the loop HCF: ; End of program |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 | ; Program to store the first 20 prime numbers in memory addresses 0 to 19 SET R1 0 ; Counter for prime numbers found SET R2 2 ; Current number to check for primality SET R3 0 ; Index for memory address primes_loop: ; Check if R2 is prime SET R4 2 ; Start divisibility check from 2 SET R5 0 ; Flag to indicate if R2 is prime (0 = true, not prime) check_divisor: ; If R4 * R4 > R2, then R2 is prime MUL R6 R4 R4 ; R6 = R4 * R4 GTE R6 R2 ; Set flag if R6 >= R2 JT is_prime ; Jump if R2 is not prime ; Check if R2 is divisible by R4 MOD R7 R2 R4 ; R7 = R2 % R4 EQ R7 0 ; If R7 == 0, R2 is not prime JF not_prime ; Jump if R2 is not divisible by R4 INC R4 ; Increment divisor JMP check_divisor ; Continue checking not_prime: SET R5 1 ; Set flag to indicate R2 is not prime JMP primes_loop_continue is_prime: ; If prime, store it in memory EQ R5 0 ; Check if flag is still 0 (prime) JF primes_loop_continue ; If not prime, continue loop ; Store the prime number in memory STORE R2 R3 ; Store R2 at memory address R3 INC R1 ; Increment the count of primes found INC R3 ; Move to the next memory address primes_loop_continue: INC R2 ; Move to the next number EQ R1 20 ; Check if we've found 20 primes JTE HCF ; If yes, halt the program JMP primes_loop ; Repeat the loop HCF: ; End of program |
Infinite loop detected Resulting in output: False
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Here's a simple assembly language program that calculates the first 20 prime numbers and stores them in memory addresses 0 to 19. The program uses basic arithmetic and control flow instructions to achieve this.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 | start: SET R1 2 ; Start checking for primes from 2 SET R2 0 ; Counter for found primes (R2) SET R3 20 ; We want 20 primes next_prime: INC R1 ; Move to the next number SET R4 2 ; Start checking for factors from 2 SET R5 0 ; Flag to indicate if prime (0 = true, 1 = false) check_factor: SET R6 0 ; Reset factor found flag DIV R1 R4 R7 ; R7 = R1 / R4 MUL R7 R4 R7 ; R7 = R4 * (R1 / R4) EQ R1 R7 ; Check if R1 is divisible by R4 JT factor_found ; If true, it's not a prime INC R4 ; Check next factor LT R4 R1 ; Check if R4 < R1 JT check_factor ; If true, go back to check next factor ; If no factors were found, it's prime SET R5 1 ; Set flag to indicate prime factor_found: INC R4 ; Increment factor LT R4 R1 ; Check if R4 < R1 JT check_factor ; If true, continue checking ; If R5 is set, store the prime EQ R5 1 ; Check if prime flag is set JT store_prime ; If true, store the prime ; Check if we have found enough primes INC R2 ; Increment found prime counter LT R2 R3 ; Check if we found less than 20 primes JT next_prime ; If true, find the next prime HCF ; Stop execution store_prime: STORE R1 R2 ; Store the found prime in memory at index R2 JT next_prime ; Continue searching for primes |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 | start: SET R1 2 ; Start checking for primes from 2 SET R2 0 ; Counter for found primes (R2) SET R3 20 ; We want 20 primes next_prime: INC R1 ; Move to the next number SET R4 2 ; Start checking for factors from 2 SET R5 0 ; Flag to indicate if prime (0 = true, 1 = false) check_factor: SET R6 0 ; Reset factor found flag DIV R1 R4 R7 ; R7 = R1 / R4 MUL R7 R4 R7 ; R7 = R4 * (R1 / R4) EQ R1 R7 ; Check if R1 is divisible by R4 JT factor_found ; If true, it's not a prime INC R4 ; Check next factor LT R4 R1 ; Check if R4 < R1 JT check_factor ; If true, go back to check next factor ; If no factors were found, it's prime SET R5 1 ; Set flag to indicate prime factor_found: INC R4 ; Increment factor LT R4 R1 ; Check if R4 < R1 JT check_factor ; If true, continue checking ; If R5 is set, store the prime EQ R5 1 ; Check if prime flag is set JT store_prime ; If true, store the prime ; Check if we have found enough primes INC R2 ; Increment found prime counter LT R2 R3 ; Check if we found less than 20 primes JT next_prime ; If true, find the next prime HCF ; Stop execution store_prime: STORE R1 R2 ; Store the found prime in memory at index R2 JT next_prime ; Continue searching for primes |
integer division or modulo by zero Resulting in output: False
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
To write a program that stores the first 20 prime numbers in memory addresses 0 to 19 using the provided assembly language, we need to implement a method to check for prime numbers and store them accordingly. Below is a sample program that accomplishes this task:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 | start: SET R1 0 ; Initialize count of primes found SET R2 2 ; Start checking for primes from 2 next_prime: SET R3 0 ; Reset the divisor counter SET R4 0 ; Reset the is_prime flag (0 = false) is_prime: INC R3 ; Increment divisor SET R5 2 ; Initialize divisor to 2 check_divisor: EQ R3 R2 ; Check if divisor has reached the number to be checked JT prime_found ; If yes, jump to prime_found MOD R6 R2 R3 ; R6 = R2 % R3 EQ R6 0 ; Check if there's no remainder JT not_prime ; If no remainder, R2 is not prime JMP check_divisor ; Continue checking next divisor not_prime: INC R2 ; Increment number to check JMP next_prime ; Go back to check for the next prime prime_found: INC R1 ; Increment the prime count STORE R2 R1 ; Store the prime number in memory at address R1 INC R2 ; Check the next number SET R7 20 ; Set the limit to 20 primes found EQ R1 R7 ; Check if we have found 20 primes JT HCF ; If yes, halt the program JMP next_prime ; Otherwise, continue searching for primes HCF: HCF ; Stop the program |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 | start: SET R1 0 ; Initialize count of primes found SET R2 2 ; Start checking for primes from 2 next_prime: SET R3 0 ; Reset the divisor counter SET R4 0 ; Reset the is_prime flag (0 = false) is_prime: INC R3 ; Increment divisor SET R5 2 ; Initialize divisor to 2 check_divisor: EQ R3 R2 ; Check if divisor has reached the number to be checked JT prime_found ; If yes, jump to prime_found MOD R6 R2 R3 ; R6 = R2 % R3 EQ R6 0 ; Check if there's no remainder JT not_prime ; If no remainder, R2 is not prime JMP check_divisor ; Continue checking next divisor not_prime: INC R2 ; Increment number to check JMP next_prime ; Go back to check for the next prime prime_found: INC R1 ; Increment the prime count STORE R2 R1 ; Store the prime number in memory at address R1 INC R2 ; Check the next number SET R7 20 ; Set the limit to 20 primes found EQ R1 R7 ; Check if we have found 20 primes JT HCF ; If yes, halt the program JMP next_prime ; Otherwise, continue searching for primes HCF: HCF ; Stop the program |
integer division or modulo by zero Resulting in output: False
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Certainly! Below is an assembly language program that calculates and stores the first 20 prime numbers in memory addresses 0 to 19.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 | START: SET R1 0 ; Counter for the number of primes found SET R2 2 ; The current number to check for primality JMP CHECK_PRIME ; Jump to the check prime section CHECK_PRIME: SET R3 0 ; Reset the divisor (R3) SET R4 1 ; Set a flag to indicate if we found a prime (1 = true) DIVIDE_LOOP: INC R3 ; Increment the divisor SET R5 R2 ; Set R5 to the current number (R2) DIV R5 R3 ; Divide R5 by R3, result in R5, remainder in R6 MOD R6 R3 ; Get the remainder of R5 divided by R3 EQ R6 0 ; Check if the remainder is 0 (not prime) JF NOT_PRIME ; If remainder is not 0, continue checking SET R4 0 ; R4 = 0, meaning we found a divisor, so not prime JMP STORE_PRIME ; Jump to store the prime (if it is one) NOT_PRIME: INC R3 ; Increment divisor LTE R3 R5 ; Check if R3 <= R5 JT DIVIDE_LOOP ; If true, continue dividing STORE_PRIME: EQ R4 1 ; Check the flag to see if it is still set (prime) JT ADD_PRIME ; If it's prime, go to store it SKIP_PRIME: INC R2 ; Move to the next number LTE R1 20 ; Check if we have found 20 primes JT CHECK_PRIME ; If not, continue checking HCF: HCF ; Stop program ADD_PRIME: STORE R2 R1 ; Store the prime number (R2) in memory at index R1 INC R1 ; Increment the prime counter INC R2 ; Move to the next number JMP CHECK_PRIME ; Jump back to check for more primes |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 | START: SET R1 0 ; Counter for the number of primes found SET R2 2 ; The current number to check for primality JMP CHECK_PRIME ; Jump to the check prime section CHECK_PRIME: SET R3 0 ; Reset the divisor (R3) SET R4 1 ; Set a flag to indicate if we found a prime (1 = true) DIVIDE_LOOP: INC R3 ; Increment the divisor SET R5 R2 ; Set R5 to the current number (R2) DIV R5 R3 ; Divide R5 by R3, result in R5, remainder in R6 MOD R6 R3 ; Get the remainder of R5 divided by R3 EQ R6 0 ; Check if the remainder is 0 (not prime) JF NOT_PRIME ; If remainder is not 0, continue checking SET R4 0 ; R4 = 0, meaning we found a divisor, so not prime JMP STORE_PRIME ; Jump to store the prime (if it is one) NOT_PRIME: INC R3 ; Increment divisor LTE R3 R5 ; Check if R3 <= R5 JT DIVIDE_LOOP ; If true, continue dividing STORE_PRIME: EQ R4 1 ; Check the flag to see if it is still set (prime) JT ADD_PRIME ; If it's prime, go to store it SKIP_PRIME: INC R2 ; Move to the next number LTE R1 20 ; Check if we have found 20 primes JT CHECK_PRIME ; If not, continue checking HCF: HCF ; Stop program ADD_PRIME: STORE R2 R1 ; Store the prime number (R2) in memory at index R1 INC R1 ; Increment the prime counter INC R2 ; Move to the next number JMP CHECK_PRIME ; Jump back to check for more primes |
invalid literal for int() with base 10: ';' Resulting in output: False
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
To store the first 20 prime numbers in memory addresses 0 to 19 using the provided assembly language, we can write a program that iterates through numbers, checks if they are prime, and stores them in memory. Below is an example of such a program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 | start: SET R1 0 ; R1 will serve as the count of found primes SET R2 2 ; R2 will be the candidate prime number (starting from 2) next_candidate: EQ R1 20 ; Check if we found 20 primes JT done ; If true, jump to done SET R3 0 ; R3 will serve as the divisor count SET R4 1 ; R4 will be the flag for primality (1 = prime, 0 = not prime) check_prime: SET R5 2 ; Start checking divisibility from 2 LT R5 R2 ; Check if R5 < R2 JF store_prime ; If R5 is not less than R2, jump to store_prime MOD R6 R2 R5 ; R6 = R2 % R5 EQ R6 0 ; Check if R2 is divisible by R5 JT not_prime ; If true, it's not prime INC R5 ; Increment the divisor JMP check_prime ; Check the next divisor not_prime: SET R4 0 ; Set R4 to 0, indicating not prime store_prime: EQ R4 1 ; Check if R4 is still 1 (indicating prime) JF next_number ; If not, go to the next number STORE R2 R1 ; Store the prime number in memory at address R1 INC R1 ; Increment the prime count next_number: INC R2 ; Move to the next candidate number JMP next_candidate ; Go back to check for more primes done: HCF ; Stop the program |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 | start: SET R1 0 ; R1 will serve as the count of found primes SET R2 2 ; R2 will be the candidate prime number (starting from 2) next_candidate: EQ R1 20 ; Check if we found 20 primes JT done ; If true, jump to done SET R3 0 ; R3 will serve as the divisor count SET R4 1 ; R4 will be the flag for primality (1 = prime, 0 = not prime) check_prime: SET R5 2 ; Start checking divisibility from 2 LT R5 R2 ; Check if R5 < R2 JF store_prime ; If R5 is not less than R2, jump to store_prime MOD R6 R2 R5 ; R6 = R2 % R5 EQ R6 0 ; Check if R2 is divisible by R5 JT not_prime ; If true, it's not prime INC R5 ; Increment the divisor JMP check_prime ; Check the next divisor not_prime: SET R4 0 ; Set R4 to 0, indicating not prime store_prime: EQ R4 1 ; Check if R4 is still 1 (indicating prime) JF next_number ; If not, go to the next number STORE R2 R1 ; Store the prime number in memory at address R1 INC R1 ; Increment the prime count next_number: INC R2 ; Move to the next candidate number JMP next_candidate ; Go back to check for more primes done: HCF ; Stop the program |
Infinite loop detected Resulting in output: False