Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Here's a program that finds the first 20 prime numbers and stores them in memory addresses 0 to 19: SET R1 2 SET R2 0 SET R3 20 SET R4 0 SET R5 0 SET R6 0 SET R7 0 loop: EQ R4 R3 JT done SET R5 2 SET R6 0 checkprime: MOD R7 R1 R5 EQ R7 0 JT notprime ADD R5 R5 1 LT R5 R1 JT checkprime isprime: STORE R1 R2 INC R2 INC R4 JMP next notprime: next: INC R1 JMP loop done: HCF Explanation: 1. Initialize R1 to 2 (the first prime number), R2 to 0 (the memory address to store primes), R3 to 20 (the count of primes to find), and R4 to 0 (the count of primes found so far). 2. Start the main loop. If R4 equals R3, jump to 'done' as we have found all 20 primes. 3. For each number, initialize R5 to 2 (the first potential divisor) and R6 to 0 (flag for whether the number is prime). 4. Start the 'checkprime' loop. Calculate the remainder of dividing the current number (R1) by the potential divisor (R5), storing it in R7. 5. If the remainder (R7) is 0, jump to 'notprime' as the number is not prime. 6. Increment the potential divisor (R5). If R5 is still less than the current number (R1), jump back to 'checkprime' to test the next divisor. 7. If we've checked all potential divisors without jumping to 'notprime', the number is prime. Jump to 'isprime'. 8. In 'isprime', store the prime number (R1) in the current memory address (R2), increment the memory address (R2) and the count of primes found (R4). 9. In 'notprime' or after storing a prime, jump to 'next'. 10. In 'next', increment the current number (R1) and jump back to the main loop. 11. If we've found all 20 primes, the program reaches 'done' and halts (with pizzazz). This program will store the first 20 prime numbers (2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71) in memory addresses 0 to 19.
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 | SET R1 2 SET R2 0 SET R3 20 SET R4 0 SET R5 0 SET R6 0 SET R7 0 loop: EQ R4 R3 JT done SET R5 2 SET R6 0 checkprime: MOD R7 R1 R5 EQ R7 0 JT notprime ADD R5 R5 1 LT R5 R1 JT checkprime isprime: STORE R1 R2 INC R2 INC R4 JMP next notprime: next: INC R1 JMP loop done: HCF |
Resulting in output: False
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Here's a program that puts the first 20 prime numbers in memory cells 0 to 19 using the given assembly language: SET R1 2 // start at 2 SET R2 0 // memory address counter SET R3 20 // stop after 20 primes SET R4 1 // constant 1 SET R5 0 // current number being checked start: SET R6 2 // potential factor starts at 2 check: MOD R7 R5 R6 // R7 = R5 % R6 EQ R7 0 JT not_prime // if R7 == 0, not a prime INC R6 LT R6 R5 JT check // keep checking factors is_prime: STORE R5 R2 // store prime in memory INC R2 // increment memory address DEC R3 EQ R3 0 JT done // if R3 == 0, we have 20 primes JMP next not_prime: next: INC R5 // check the next number JMP start done: HCF // halt with pizzazz This program does the following: 1. Initializes registers with starting values. 2. Starts a loop at the 'start' label, setting R5 to the current number being checked for primality. 3. Starts a nested loop at the 'check' label, using R6 as a potential factor. 4. If R5 is divisible by R6 (i.e., R5 % R6 == 0), jumps to 'not_prime'. 5. If R6 becomes greater than or equal to R5, the number is prime, so it jumps to 'is_prime'. 6. At 'is_prime', stores the prime number in memory, increments the memory address, and decrements the count of primes needed. 7. If 20 primes have been found, jumps to 'done'. Otherwise, jumps to 'next'. 8. At 'not_prime' or after storing a prime, jumps to 'next' to increment R5 and start checking the next number. 9. Halts with pizzazz once 20 primes are found and stored in memory. After running this program, memory addresses 0 to 19 will contain the first 20 prime numbers (2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71).
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 | SET R1 2 // start at 2 SET R2 0 // memory address counter SET R3 20 // stop after 20 primes SET R4 1 // constant 1 SET R5 0 // current number being checked start: SET R6 2 // potential factor starts at 2 check: MOD R7 R5 R6 // R7 = R5 % R6 EQ R7 0 JT not_prime // if R7 == 0, not a prime INC R6 LT R6 R5 JT check // keep checking factors is_prime: STORE R5 R2 // store prime in memory INC R2 // increment memory address DEC R3 EQ R3 0 JT done // if R3 == 0, we have 20 primes JMP next not_prime: next: INC R5 // check the next number JMP start done: HCF // halt with pizzazz |
Resulting in output: False
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Here's a program in the given assembly language that puts the first 20 prime numbers in memory cells 0 to 19: SET R1 2 SET R2 0 SET R3 20 SET R4 1 SET R5 0 loop: SET R6 2 checkprime: MOD R7 R1 R6 EQ R7 0 JT notprime INC R6 LT R6 R1 JT checkprime isprime: STORE R1 R2 INC R2 INC R5 EQ R5 R3 JT done JMP aftercheck notprime: INC R1 aftercheck: JMP loop done: HCF Explanation: 1. Initialize R1 to 2 (the first prime number), R2 to 0 (the starting memory address), R3 to 20 (the count of prime numbers to find), R4 to 1 (used as a constant), and R5 to 0 (a counter for the number of primes found). 2. Start the main loop. Set R6 to 2 (the first potential divisor). 3. Check if the current number (R1) is prime by checking for divisibility by numbers from 2 to R1-1. 4. If the number is divisible by any of these numbers (remainder is 0), jump to the 'notprime' label. 5. If the number is not divisible by any of these numbers, it is prime. Store the prime number in the memory address pointed to by R2, increment R2 and R5, and check if we have found all 20 primes (R5 equals R3). If so, jump to 'done'. 6. If the number is not prime, increment R1 and jump back to the main loop. 7. If we have found all 20 primes, stop the program with the 'HCF' instruction. This program will store the first 20 prime numbers (2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71) in memory addresses 0 to 19.
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 | SET R1 2 SET R2 0 SET R3 20 SET R4 1 SET R5 0 loop: SET R6 2 checkprime: MOD R7 R1 R6 EQ R7 0 JT notprime INC R6 LT R6 R1 JT checkprime isprime: STORE R1 R2 INC R2 INC R5 EQ R5 R3 JT done JMP aftercheck notprime: INC R1 aftercheck: JMP loop done: HCF |
Resulting in output: False
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Here's a program in the given assembly language that puts the first 20 prime numbers in memory cells 0..19:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 | SET R1 2 // start with the first prime number, 2 SET R2 0 // memory address to store prime numbers SET R3 20 // counter for the number of primes to find main: SET R4 2 // divisor to check for primality check_prime: MOD R5 R1 R4 // calculate R1 % R4 EQ R5 0 // check if the remainder is 0 JT not_prime // if the remainder is 0, the number is not prime INC R4 // increment the divisor LT R6 R4 R1 // check if the divisor is less than the number JT check_prime // if the divisor is less than the number, continue checking // if we reach here, the number is prime STORE R1 R2 // store the prime number in the memory address INC R2 // increment the memory address DEC R3 // decrement the prime counter EQ R3 0 // check if we have found all 20 primes JT done // if we have found all 20 primes, exit the program not_prime: INC R1 // increment the number to check JMP main // go back to the main loop done: HCF // stop the program with pizzazz |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 | SET R1 2 // start with the first prime number, 2 SET R2 0 // memory address to store prime numbers SET R3 20 // counter for the number of primes to find main: SET R4 2 // divisor to check for primality check_prime: MOD R5 R1 R4 // calculate R1 % R4 EQ R5 0 // check if the remainder is 0 JT not_prime // if the remainder is 0, the number is not prime INC R4 // increment the divisor LT R6 R4 R1 // check if the divisor is less than the number JT check_prime // if the divisor is less than the number, continue checking // if we reach here, the number is prime STORE R1 R2 // store the prime number in the memory address INC R2 // increment the memory address DEC R3 // decrement the prime counter EQ R3 0 // check if we have found all 20 primes JT done // if we have found all 20 primes, exit the program not_prime: INC R1 // increment the number to check JMP main // go back to the main loop done: HCF // stop the program with pizzazz |
Infinite loop detected Resulting in output: False
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Here is the description of a new assembly language: * 8 registers (R1, R2, R3, R4, R5, R6, R7, R8) that can hold integers. * 1 flag that can hold a boolean value (True or False). * 100 memory addresses (0-99) that can hold integers. * 1 instruction pointer that points to the current instruction being executed. Each instruction is of the form OP ARG1 ARG2 ... where ARGn can be either a register (e.g., R1) or a constant (e.g., 10). Labels are written with a lowercase word followed by colon. The assembly language supports the following instructions: * SET Rx C: Assigns the value C to register Rx. * ADD Rx Ry Rz: Adds the values of Ry and Rz and stores the result in Rx. * (similarly for SUB, MUL, DIV, MOD) * EQ Rx Ry: Sets the flag to True if Rx and Ry are equal, False otherwise. * (similarly for NEQ, LT (Rx < Ry), LTE, GT, GTE) * INC/DEC Rx: Increments/Decrements the value of Rx by one. * JMP L: Jumps to label L unconditionally. * JT/JF (jump if true / jump if false) L: Jumps to label L if the is set or not set. * LOAD Rx M: Loads the value at memory address M into register Rx. * STORE Rx M: Stores the value of register Rx into memory address M. * HCF: Stops the program (with pizzazz) Given this assembly language, write a program that puts the first 20 prime numbers in memory cells 0..19
Here's a program that puts the first 20 prime numbers in memory cells 0..19 using the given assembly language:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 | SET R1 2 ; Initialize R1 to 2 (first prime number) SET R2 0 ; Initialize R2 to 0 (memory address counter) SET R3 20 ; Set R3 to 20 (number of primes to find) SET R4 1 ; Initialize R4 to 1 (constant) SET R5 0 ; Initialize R5 to 0 (counter for division) SET R6 0 ; Initialize R6 to 0 (flag for prime) loop: SET R7 2 ; Initialize R7 to 2 (divisor) SET R6 0 ; Set R6 to 0 (assume prime) divisor_loop: MOD R8 R1 R7 ; R8 = R1 % R7 EQ R8 0 ; Check if R8 is equal to 0 JT not_prime ; If R8 is 0, jump to not_prime INC R7 ; Increment divisor (R7) LT R7 R1 ; Check if R7 < R1 JT divisor_loop ; If R7 < R1, jump to divisor_loop SET R6 1 ; Set R6 to 1 (prime number found) not_prime: EQ R6 1 ; Check if R6 is equal to 1 JF increment ; If R6 is 0 (not prime), jump to increment STORE R1 R2 ; Store prime number (R1) in memory address (R2) INC R2 ; Increment memory address counter (R2) DEC R3 ; Decrement number of primes to find (R3) EQ R3 0 ; Check if R3 is equal to 0 JT done ; If R3 is 0, jump to done increment: INC R1 ; Increment number (R1) JMP loop ; Jump back to loop done: HCF ; Stop the program |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 | SET R1 2 ; Initialize R1 to 2 (first prime number) SET R2 0 ; Initialize R2 to 0 (memory address counter) SET R3 20 ; Set R3 to 20 (number of primes to find) SET R4 1 ; Initialize R4 to 1 (constant) SET R5 0 ; Initialize R5 to 0 (counter for division) SET R6 0 ; Initialize R6 to 0 (flag for prime) loop: SET R7 2 ; Initialize R7 to 2 (divisor) SET R6 0 ; Set R6 to 0 (assume prime) divisor_loop: MOD R8 R1 R7 ; R8 = R1 % R7 EQ R8 0 ; Check if R8 is equal to 0 JT not_prime ; If R8 is 0, jump to not_prime INC R7 ; Increment divisor (R7) LT R7 R1 ; Check if R7 < R1 JT divisor_loop ; If R7 < R1, jump to divisor_loop SET R6 1 ; Set R6 to 1 (prime number found) not_prime: EQ R6 1 ; Check if R6 is equal to 1 JF increment ; If R6 is 0 (not prime), jump to increment STORE R1 R2 ; Store prime number (R1) in memory address (R2) INC R2 ; Increment memory address counter (R2) DEC R3 ; Decrement number of primes to find (R3) EQ R3 0 ; Check if R3 is equal to 0 JT done ; If R3 is 0, jump to done increment: INC R1 ; Increment number (R1) JMP loop ; Jump back to loop done: HCF ; Stop the program |
Resulting in output: False