What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
This program will print: `The array shape is (20, 3)` Explanation: The numpy array `array` is of shape `(10, 20, 30)`, which means it has 10 elements in the first dimension, each of which is a 2D array of shape `(20, 30)`. The expression `array[0, :, idxs]` selects the first 2D array from `array` (i.e., `array[0]`), and then selects all elements along the second dimension (i.e., `:`), and finally selects only the elements at indices `1`, `2`, and `3` in the third dimension (i.e., `idxs`). Therefore, `array[0, :, idxs]` is a 2D array with shape `(20, 3)`, where each row corresponds to a row in the first 2D array of `array`, and contains only the elements at indices `1`, `2`, and `3` in the corresponding third dimension.
Testing if the previous output contains the string The array shape is (3, 20)
: False
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
The program will print the shape of a numpy array slice. The slice is taken from the first element of the first dimension (axis 0), all elements of the second dimension (axis 1), and the elements at indices 1, 2, and 3 of the third dimension (axis 2). The output of the program will be: `The array shape is (20, 3)` This means that the resulting array has 20 rows and 3 columns. The 20 rows come from selecting all elements in the second dimension, and the 3 columns come from selecting the elements at indices 1, 2, and 3 of the third dimension.
Testing if the previous output contains the string The array shape is (3, 20)
: False
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
The program will print: `The array shape is (20, 3)` Explanation: The `numpy.zeros()` function creates an array of zeros with the specified shape, which in this case is (10, 20, 30). The line `array[0, :, idxs]` selects a subset of the array. Specifically, it selects the first element along the first dimension (i.e., `array[0]`), all elements along the second dimension (i.e., `:`), and the elements at indices 1, 2, and 3 along the third dimension (i.e., `idxs`). Therefore, the resulting array has shape (20, 3), where 20 corresponds to the number of elements in the second dimension and 3 corresponds to the number of elements selected from the third dimension.
Testing if the previous output contains the string The array shape is (3, 20)
: False
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
The program will print: `The array shape is (20, 3)` Explanation: The given NumPy code creates a 3-dimensional array of shape `(10, 20, 30)` filled with zeros. Then it selects elements from the second dimension (axis=1) using the index `[1, 2, 3]` for the third dimension (axis=2). This results in a 2-dimensional array with shape `(20, 3)`, where the first dimension corresponds to the 20 elements selected from the second axis and the second dimension corresponds to the 3 elements selected from the third axis.
Testing if the previous output contains the string The array shape is (3, 20)
: False
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
The given Python program uses NumPy, a popular library for numerical computations. It creates a 3-dimensional array of shape (10, 20, 30) filled with zeros, and then selects a subset of data from the array using an index list `idxs`. When you run this program, it will print the shape of the subset array, which can be calculated as follows: 1. `array[0, :, idxs]` means selecting the first element along the first dimension (axis 0), all elements along the second dimension (axis 1), and only the elements at indices 1, 2, and 3 along the third dimension (axis 2). 2. Since the second dimension has 20 elements and we're selecting all of them, the size along this dimension remains unchanged (20). 3. For the third dimension, we're selecting only the elements at indices 1, 2, and 3. Therefore, the size along this dimension will be 3. 4. The shape of the resulting subset array will be (1, 20, 3), where the first dimension has a size of 1 because we're only selecting one element from it. So, the output of the program will be:
1 | The array shape is (1, 20, 3) |
Testing if the previous output contains the string The array shape is (3, 20)
: False