What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
The program will print the shape of the slice of the `array` obtained by indexing it with `array[0, :, idxs]`. Here's how the indexing works: - `0` selects the first element along the first dimension (index 0). - `:` selects all elements along the second dimension. - `idxs` selects the elements at indices 1, 2, and 3 along the third dimension. Given the shape of `array` as `(10, 20, 30)`, the resulting shape of `array[0, :, idxs]` will be `(20, 3)`. Therefore, the output of the program will be:
1 | The array shape is (20, 3) |
Testing if the previous output contains the string The array shape is (3, 20)
: False
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
The program will print the shape of a specific slice of the `array` using the indexing `array[0, :, idxs]`. Here's the breakdown: - `array` is a 3-dimensional numpy array with shape (10, 20, 30). - `idxs` is a list containing the values [1, 2, 3]. When indexing the array with `array[0, :, idxs]`: - The first index, `0`, selects the first element along the first dimension (axis 0) of the array. - The second index, `:`, selects all elements along the second dimension (axis 1) of the array. - The third index, `idxs`, selects the elements at indices 1, 2, and 3 along the third dimension (axis 2) of the array. Therefore, `array[0, :, idxs]` will result in a 2-dimensional slice of the original array with shape (20, 3). The first dimension corresponds to all elements along axis 1, and the second dimension corresponds to the selected indices [1, 2, 3] along axis 2. So, the output of the program will be:
1 | The array shape is (20, 3) |
Testing if the previous output contains the string The array shape is (3, 20)
: False
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
The program will print the following:
1 | The array shape is (20, 3) |
1 | The array shape is (20, 3) |
Testing if the previous output contains the string The array shape is (3, 20)
: False
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
The program will print the shape of the array slice obtained by indexing the original array using `array[0, :, idxs]`. Let's break it down: 1. The original array `array` is created using `np.zeros((10, 20, 30))`, which creates a 3-dimensional array filled with zeros. The shape of `array` is `(10, 20, 30)`. 2. The variable `idxs` is a list containing the values `[1, 2, 3]`. 3. The indexing operation `array[0, :, idxs]` selects a specific slice of the original array: - `0` selects the first element along the first dimension (index 0). - `:` selects all elements along the second dimension. - `idxs` selects the elements at indices 1, 2, and 3 along the third dimension. 4. The resulting slice will have a shape of `(20, 3)` because: - The first dimension is reduced to a single element (index 0). - The second dimension remains unchanged, so it has a size of 20. - The third dimension is reduced to the selected indices `[1, 2, 3]`, resulting in a size of 3. Therefore, when you run this program, it will print:
1 | The array shape is (20, 3) |
Testing if the previous output contains the string The array shape is (3, 20)
: False
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
What will this program print:
1 2 3 4 5 6 | import numpy as np array = np.zeros((10, 20, 30)) idxs = [1, 2, 3] print("The array shape is", array[0, :, idxs].shape) |
The program will print:
1 | The array shape is (20, 3) |
Testing if the previous output contains the string The array shape is (3, 20)
: False