Initial Query

class Node: def __init__(self, name, parent=None): self.name = name self.parent = parent self.children = [] if parent: self.parent.children.append(self) def __repr__(self): if self.children == []: return self.name return '('+self.name + ' ' + ' '.join(repr(c) for c in self.children)+')' Write a complete python file that will print the tree (1 (2 (3 4 5 6) (7 8)) (9 10 (11 12))) Call the root of the tree 'root'. Then print out str(root).

LLM Generation

Query

class Node: def __init__(self, name, parent=None): self.name = name self.parent = parent self.children = [] if parent: self.parent.children.append(self) def __repr__(self): if self.children == []: return self.name return '('+self.name + ' ' + ' '.join(repr(c) for c in self.children)+')' Write a complete python file that will print the tree (1 (2 (3 4 5 6) (7 8)) (9 10 (11 12))) Call the root of the tree 'root'. Then print out str(root).

Output

#!/usr/bin/env python3 class Node: def __init__(self, name, parent=None): self.name = name self.parent = parent self.children = [] if parent: self.parent.children.append(self) def __repr__(self): if self.children == []: return self.name return '(' + self.name + ' ' + ' '.join(repr(c) for c in self.children) + ')' if __name__ == '__main__': # Build the tree corresponding to: # (1 (2 (3 4 5 6) (7 8)) (9 10 (11 12))) # # Explanation of the tree structure: # - The root node "1" has two children: "2" and "9". # - Node "2" has two children: # • "3" with three children "4", "5", and "6" # • "7" with one child "8" # - Node "9" has two children: # • "10" with no children # • "11" with one child "12" root = Node("1") # The root # First subtree under root node2 = Node("2", root) node3 = Node("3", node2) Node("4", node3) Node("5", node3) Node("6", node3) node7 = Node("7", node2) Node("8", node7) # Second subtree under root node9 = Node("9", root) Node("10", node9) node11 = Node("11", node9) Node("12", node11) # Print the tree using __repr__ of the root print(str(root))

Extract Code

I extracted the following code from that output: 

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#!/usr/bin/env python3

class Node:
    def __init__(self, name, parent=None):
        self.name = name
        self.parent = parent
        self.children = []
        if parent:
            self.parent.children.append(self)
    def __repr__(self):
        if self.children == []:
            return self.name
        return '(' + self.name + ' ' + ' '.join(repr(c) for c in self.children) + ')'

if __name__ == '__main__':
    # Build the tree corresponding to:
    # (1 (2 (3 4 5 6) (7 8)) (9 10 (11 12)))
    #
    # Explanation of the tree structure:
    # - The root node "1" has two children: "2" and "9".
    # - Node "2" has two children:
    #     • "3" with three children "4", "5", and "6"
    #     • "7" with one child "8"
    # - Node "9" has two children:
    #     • "10" with no children
    #     • "11" with one child "12"
    
    root = Node("1")    # The root
    
    # First subtree under root
    node2 = Node("2", root)
    node3 = Node("3", node2)
    Node("4", node3)
    Node("5", node3)
    Node("6", node3)
    node7 = Node("7", node2)
    Node("8", node7)
    
    # Second subtree under root
    node9 = Node("9", root)
    Node("10", node9)
    node11 = Node("11", node9)
    Node("12", node11)
    
    # Print the tree using __repr__ of the root
    print(str(root))

Run Code Interpreter

Running the following program: 

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#!/usr/bin/env python3

class Node:
    def __init__(self, name, parent=None):
        self.name = name
        self.parent = parent
        self.children = []
        if parent:
            self.parent.children.append(self)
    def __repr__(self):
        if self.children == []:
            return self.name
        return '(' + self.name + ' ' + ' '.join(repr(c) for c in self.children) + ')'

if __name__ == '__main__':
    # Build the tree corresponding to:
    # (1 (2 (3 4 5 6) (7 8)) (9 10 (11 12)))
    #
    # Explanation of the tree structure:
    # - The root node "1" has two children: "2" and "9".
    # - Node "2" has two children:
    #     • "3" with three children "4", "5", and "6"
    #     • "7" with one child "8"
    # - Node "9" has two children:
    #     • "10" with no children
    #     • "11" with one child "12"
    
    root = Node("1")    # The root
    
    # First subtree under root
    node2 = Node("2", root)
    node3 = Node("3", node2)
    Node("4", node3)
    Node("5", node3)
    Node("6", node3)
    node7 = Node("7", node2)
    Node("8", node7)
    
    # Second subtree under root
    node9 = Node("9", root)
    Node("10", node9)
    node11 = Node("11", node9)
    Node("12", node11)
    
    # Print the tree using __repr__ of the root
    print(str(root))
And got the output: (1 (2 (3 4 5 6) (7 8)) (9 10 (11 12)))

Substring Evaluation

Testing if the previous output contains the string (1 (2 (3 4 5 6) (7 8)) (9 10 (11 12))): True

Initial Query

class Node: def __init__(self, name, parent=None): self.name = name self.parent = parent self.children = [] if parent: self.parent.children.append(self) def __repr__(self): if self.children == []: return self.name return '('+self.name + ' ' + ' '.join(repr(c) for c in self.children)+')' Write a complete python file that will print the tree (1 (2 (3 4 5 6) (7 8)) (9 10 (11 12))) Call the root of the tree 'root'. Then print out str(root).

LLM Generation

Query

class Node: def __init__(self, name, parent=None): self.name = name self.parent = parent self.children = [] if parent: self.parent.children.append(self) def __repr__(self): if self.children == []: return self.name return '('+self.name + ' ' + ' '.join(repr(c) for c in self.children)+')' Write a complete python file that will print the tree (1 (2 (3 4 5 6) (7 8)) (9 10 (11 12))) Call the root of the tree 'root'. Then print out str(root).

Output

#!/usr/bin/env python3 class Node: def __init__(self, name, parent=None): self.name = name self.parent = parent self.children = [] if parent: parent.children.append(self) def __repr__(self): if not self.children: return self.name return '(' + self.name + ' ' + ' '.join(repr(child) for child in self.children) + ')' if __name__ == '__main__': # Build the tree: # Root is "1" root = Node("1") # Children of root "1" node2 = Node("2", root) node9 = Node("9", root) # Children of node2, for subtree (2 (3 4 5 6) (7 8)) node3 = Node("3", node2) node7 = Node("7", node2) # Children of node3 --> (3 4 5 6) Node("4", node3) Node("5", node3) Node("6", node3) # Child of node7 --> (7 8) Node("8", node7) # Children of node9 --> (9 10 (11 12)) Node("10", node9) node11 = Node("11", node9) # Child of node11 --> (11 12) Node("12", node11) # Print the tree string representation. print(str(root))

Extract Code

I extracted the following code from that output: 

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#!/usr/bin/env python3

class Node:
    def __init__(self, name, parent=None):
        self.name = name
        self.parent = parent
        self.children = []
        if parent:
            parent.children.append(self)
    
    def __repr__(self):
        if not self.children:
            return self.name
        return '(' + self.name + ' ' + ' '.join(repr(child) for child in self.children) + ')'

if __name__ == '__main__':
    # Build the tree:
    # Root is "1"
    root = Node("1")
    
    # Children of root "1"
    node2 = Node("2", root)
    node9 = Node("9", root)

    # Children of node2, for subtree (2 (3 4 5 6) (7 8))
    node3 = Node("3", node2)
    node7 = Node("7", node2)
    
    # Children of node3 --> (3 4 5 6)
    Node("4", node3)
    Node("5", node3)
    Node("6", node3)
    
    # Child of node7 --> (7 8)
    Node("8", node7)

    # Children of node9 --> (9 10 (11 12))
    Node("10", node9)
    node11 = Node("11", node9)
    
    # Child of node11 --> (11 12)
    Node("12", node11)
    
    # Print the tree string representation.
    print(str(root))

Run Code Interpreter

Running the following program: 

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#!/usr/bin/env python3

class Node:
    def __init__(self, name, parent=None):
        self.name = name
        self.parent = parent
        self.children = []
        if parent:
            parent.children.append(self)
    
    def __repr__(self):
        if not self.children:
            return self.name
        return '(' + self.name + ' ' + ' '.join(repr(child) for child in self.children) + ')'

if __name__ == '__main__':
    # Build the tree:
    # Root is "1"
    root = Node("1")
    
    # Children of root "1"
    node2 = Node("2", root)
    node9 = Node("9", root)

    # Children of node2, for subtree (2 (3 4 5 6) (7 8))
    node3 = Node("3", node2)
    node7 = Node("7", node2)
    
    # Children of node3 --> (3 4 5 6)
    Node("4", node3)
    Node("5", node3)
    Node("6", node3)
    
    # Child of node7 --> (7 8)
    Node("8", node7)

    # Children of node9 --> (9 10 (11 12))
    Node("10", node9)
    node11 = Node("11", node9)
    
    # Child of node11 --> (11 12)
    Node("12", node11)
    
    # Print the tree string representation.
    print(str(root))
And got the output: (1 (2 (3 4 5 6) (7 8)) (9 10 (11 12)))

Substring Evaluation

Testing if the previous output contains the string (1 (2 (3 4 5 6) (7 8)) (9 10 (11 12))): True