Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

Sure! Below is a Python function `rle_to_arr` that converts a Run-Length Encoded (RLE) Game of Life pattern into a NumPy array of shape `(h, w)`. The array is filled with `1`s for live cells (`o`) and `0`s for dead cells (`b`). 

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import numpy as np
import re

def rle_to_arr(rle_string, h, w):
    """
    Convert a Game of Life RLE pattern to a numpy array.

    Parameters:
    - rle_string: str, the RLE encoded pattern.
    - h: int, height of the output array.
    - w: int, width of the output array.

    Returns:
    - np.ndarray of shape (h, w) with 1s and 0s.
    """
    # Initialize the array with zeros
    arr = np.zeros((h, w), dtype=int)
    
    # Remove any whitespace and the terminating '!'
    rle_string = rle_string.strip().rstrip('!')
    
    # Initialize cursor position
    x, y = 0, 0
    
    # Regular expression to find all runs
    pattern = re.compile(r'(\d*)([bo\$])')
    
    for count, symbol in pattern.findall(rle_string):
        count = int(count) if count else 1  # Default count is 1
        
        if symbol == 'b':
            # Dead cells; just move the cursor
            x += count
        elif symbol == 'o':
            # Live cells; set to 1 and move the cursor
            if x + count > w:
                raise ValueError(f"Pattern exceeds width at row {y}.")
            arr[y, x:x+count] = 1
            x += count
        elif symbol == '$':
            # New line; move to the next row
            y += count
            if y >= h:
                break  # Stop if we've reached the desired height
            x = 0
    
    return arr

# Example usage:
rle_pattern = (
    "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$"
    "60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b"
    "o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b"
    "o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o"
    "3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
)

# Define the desired height and width
height = 100  # Example height
width = 100   # Example width

# Convert RLE to array
game_of_life_array = rle_to_arr(rle_pattern, height, width)

# To visualize the array (optional)
# import matplotlib.pyplot as plt
# plt.imshow(game_of_life_array, cmap='binary')
# plt.show()
### Explanation: 1. **Import Statements**: - `numpy` is used for array manipulations. - `re` (regular expressions) is used to parse the RLE string. 2. **Function `rle_to_arr`**: - **Initialization**: - Creates a NumPy array filled with `0`s of shape `(h, w)`. - Cleans the RLE string by removing whitespace and the terminating `!`. - Sets the initial cursor position at the top-left corner `(x, y) = (0, 0)`. - **Parsing the RLE String**: - Uses a regular expression to find all occurrences of counts followed by symbols (`b`, `o`, or `$`). - Iterates through each match: - **`b` (dead cell)**: Moves the cursor to the right by the count. - **`o` (live cell)**: Sets the corresponding cells to `1` and moves the cursor. - **`$` (end of line)**: Moves the cursor down by the count and resets the horizontal position. - **Boundary Checks**: - Ensures that the pattern does not exceed the specified width and height. Raises a `ValueError` if it does. - **Return**: - Returns the populated NumPy array. 3. **Example Usage**: - An example RLE pattern is provided. - The desired height and width are specified (you should adjust these based on your pattern). - The function is called to convert the RLE pattern into a NumPy array. - Optional visualization code is provided using `matplotlib` (commented out). ### Notes: - **Adjusting `h` and `w`**: Ensure that the height (`h`) and width (`w`) parameters are large enough to accommodate the RLE pattern. If the pattern exceeds the specified dimensions, the function will raise an error. - **Visualization**: You can visualize the resulting array using libraries like `matplotlib` to see the Game of Life pattern. Let me know if you need further assistance!

Extract Code

I extracted the following code from that output: 

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import numpy as np
import re

def rle_to_arr(rle_string, h, w):
    """
    Convert a Game of Life RLE pattern to a numpy array.

    Parameters:
    - rle_string: str, the RLE encoded pattern.
    - h: int, height of the output array.
    - w: int, width of the output array.

    Returns:
    - np.ndarray of shape (h, w) with 1s and 0s.
    """
    # Initialize the array with zeros
    arr = np.zeros((h, w), dtype=int)
    
    # Remove any whitespace and the terminating '!'
    rle_string = rle_string.strip().rstrip('!')
    
    # Initialize cursor position
    x, y = 0, 0
    
    # Regular expression to find all runs
    pattern = re.compile(r'(\d*)([bo\$])')
    
    for count, symbol in pattern.findall(rle_string):
        count = int(count) if count else 1  # Default count is 1
        
        if symbol == 'b':
            # Dead cells; just move the cursor
            x += count
        elif symbol == 'o':
            # Live cells; set to 1 and move the cursor
            if x + count > w:
                raise ValueError(f"Pattern exceeds width at row {y}.")
            arr[y, x:x+count] = 1
            x += count
        elif symbol == '$':
            # New line; move to the next row
            y += count
            if y >= h:
                break  # Stop if we've reached the desired height
            x = 0
    
    return arr

# Example usage:
rle_pattern = (
    "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$"
    "60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b"
    "o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b"
    "o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o"
    "3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
)

# Define the desired height and width
height = 100  # Example height
width = 100   # Example width

# Convert RLE to array
game_of_life_array = rle_to_arr(rle_pattern, height, width)

# To visualize the array (optional)
# import matplotlib.pyplot as plt
# plt.imshow(game_of_life_array, cmap='binary')
# plt.show()

Run Code Interpreter

Running the following program: 

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import numpy as np
import re

def rle_to_arr(rle_string, h, w):
    """
    Convert a Game of Life RLE pattern to a numpy array.

    Parameters:
    - rle_string: str, the RLE encoded pattern.
    - h: int, height of the output array.
    - w: int, width of the output array.

    Returns:
    - np.ndarray of shape (h, w) with 1s and 0s.
    """
    # Initialize the array with zeros
    arr = np.zeros((h, w), dtype=int)
    
    # Remove any whitespace and the terminating '!'
    rle_string = rle_string.strip().rstrip('!')
    
    # Initialize cursor position
    x, y = 0, 0
    
    # Regular expression to find all runs
    pattern = re.compile(r'(\d*)([bo\$])')
    
    for count, symbol in pattern.findall(rle_string):
        count = int(count) if count else 1  # Default count is 1
        
        if symbol == 'b':
            # Dead cells; just move the cursor
            x += count
        elif symbol == 'o':
            # Live cells; set to 1 and move the cursor
            if x + count > w:
                raise ValueError(f"Pattern exceeds width at row {y}.")
            arr[y, x:x+count] = 1
            x += count
        elif symbol == '$':
            # New line; move to the next row
            y += count
            if y >= h:
                break  # Stop if we've reached the desired height
            x = 0
    
    return arr

# Example usage:
rle_pattern = (
    "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$"
    "60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b"
    "o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b"
    "o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o"
    "3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
)

# Define the desired height and width
height = 100  # Example height
width = 100   # Example width

# Convert RLE to array
game_of_life_array = rle_to_arr(rle_pattern, height, width)

# To visualize the array (optional)
# import matplotlib.pyplot as plt
# plt.imshow(game_of_life_array, cmap='binary')
# plt.show()





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: All tests passed

Substring Evaluation

Testing if the previous output contains the string All tests passed: True

Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

Certainly! Below is a Python function `rle_to_arr` that converts a Run-Length Encoded (RLE) Game of Life pattern string into a NumPy array of specified height (`h`) and width (`w`). The array will contain `1`s for live cells and `0`s for dead cells. ### Function Explanation 1. **Initialization**: - Create a NumPy array `arr` of zeros with shape `(h, w)` to represent the grid. - Initialize `rows` and `cols` to keep track of the current position in the grid. 2. **Preprocessing**: - Remove any trailing `!` character from the RLE string, as it's typically used to signify the end of the pattern. - Split the RLE string by `$` to process each line separately. 3. **Parsing the RLE String**: - Iterate through each line obtained from splitting by `$`. - Use a `count` variable to accumulate digits that specify the number of consecutive cells. - For each character in the line: - If it's a digit, append it to `count`. - If it's `b` (dead cell) or `o` (live cell): - Determine the number of cells (`n`) based on `count`. If no number is specified, default to `1`. - For `b`: Increment the `cols` by `n` to skip dead cells. - For `o`: Set the corresponding positions in `arr` to `1` to mark live cells and increment `cols` by `n`. - Reset `count` after processing a symbol. - After processing a line, move to the next row and reset `cols` to `0`. - Stop processing if the number of rows exceeds `h`. 4. **Return the Array**: - After parsing the entire RLE string or filling the specified height, return the resulting NumPy array. ### Implementation 

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import numpy as np
import re

def rle_to_arr(string, h, w):
    """
    Convert a Game of Life RLE string to a NumPy array.

    Parameters:
    - string: str, the RLE encoded Game of Life pattern.
    - h: int, the height of the resulting array.
    - w: int, the width of the resulting array.

    Returns:
    - arr: np.ndarray of shape (h, w), with 1s for live cells and 0s for dead cells.
    """
    arr = np.zeros((h, w), dtype=int)
    rows = 0
    cols = 0
    # Remove any trailing '!' if present
    string = string.rstrip('!')
    # Split the string by '$' to get lines
    lines = string.split('$')
    for line in lines:
        count = ''
        for char in line:
            if char.isdigit():
                count += char
            else:
                if count == '':
                    n = 1
                else:
                    n = int(count)
                if char == 'b':
                    cols += n  # Dead cells; move the column pointer
                elif char == 'o':
                    if cols + n > w:
                        n = w - cols  # Prevent overflow
                    arr[rows, cols:cols + n] = 1  # Live cells
                    cols += n
                # Reset count after processing a symbol
                count = ''
        # After processing a line, move to the next row
        rows += 1
        cols = 0
        if rows >= h:
            break  # Prevent exceeding the array height
    return arr
### Example Usage Let's convert the provided RLE string into a NumPy array. Suppose you want the resulting array to have a height and width that can accommodate the pattern. 
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rle_string = (
    "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b"
    "2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$"
    "60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b"
    "o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b"
    "o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o"
    "3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
)

# Determine appropriate height and width.
# For this example, let's assume h=80 and w=80
h, w = 80, 80
game_of_life_array = rle_to_arr(rle_string, h, w)

# To visualize the array, you can print it or use matplotlib
print(game_of_life_array)

# Optional: Visualize using matplotlib
import matplotlib.pyplot as plt

plt.imshow(game_of_life_array, cmap='binary')
plt.title("Game of Life Pattern")
plt.show()
This will convert the RLE pattern into a NumPy array and display it visually. Adjust the `h` and `w` parameters as needed to fit the pattern within your desired grid size. ### Additional Notes - **Error Handling**: This function assumes that the RLE string is well-formed. For production use, you might want to add error handling to manage malformed strings or out-of-bounds issues more gracefully. - **Performance**: For very large grids or complex patterns, there might be more efficient ways to parse and populate the array, especially by handling runs of `b` and `o` more effectively. - **Extensions**: You can modify the function to handle additional RLE features, such as comments or metadata, depending on your requirements.

Extract Code

I extracted the following code from that output: 

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import numpy as np
import re

def rle_to_arr(string, h, w):
    """
    Convert a Game of Life RLE string to a NumPy array.

    Parameters:
    - string: str, the RLE encoded Game of Life pattern.
    - h: int, the height of the resulting array.
    - w: int, the width of the resulting array.

    Returns:
    - arr: np.ndarray of shape (h, w), with 1s for live cells and 0s for dead cells.
    """
    arr = np.zeros((h, w), dtype=int)
    rows = 0
    cols = 0
    # Remove any trailing '!' if present
    string = string.rstrip('!')
    # Split the string by '$' to get lines
    lines = string.split('$')
    for line in lines:
        count = ''
        for char in line:
            if char.isdigit():
                count += char
            else:
                if count == '':
                    n = 1
                else:
                    n = int(count)
                if char == 'b':
                    cols += n  # Dead cells; move the column pointer
                elif char == 'o':
                    if cols + n > w:
                        n = w - cols  # Prevent overflow
                    arr[rows, cols:cols + n] = 1  # Live cells
                    cols += n
                # Reset count after processing a symbol
                count = ''
        # After processing a line, move to the next row
        rows += 1
        cols = 0
        if rows >= h:
            break  # Prevent exceeding the array height
    return arr

Run Code Interpreter

Running the following program: 

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import numpy as np
import re

def rle_to_arr(string, h, w):
    """
    Convert a Game of Life RLE string to a NumPy array.

    Parameters:
    - string: str, the RLE encoded Game of Life pattern.
    - h: int, the height of the resulting array.
    - w: int, the width of the resulting array.

    Returns:
    - arr: np.ndarray of shape (h, w), with 1s for live cells and 0s for dead cells.
    """
    arr = np.zeros((h, w), dtype=int)
    rows = 0
    cols = 0
    # Remove any trailing '!' if present
    string = string.rstrip('!')
    # Split the string by '$' to get lines
    lines = string.split('$')
    for line in lines:
        count = ''
        for char in line:
            if char.isdigit():
                count += char
            else:
                if count == '':
                    n = 1
                else:
                    n = int(count)
                if char == 'b':
                    cols += n  # Dead cells; move the column pointer
                elif char == 'o':
                    if cols + n > w:
                        n = w - cols  # Prevent overflow
                    arr[rows, cols:cols + n] = 1  # Live cells
                    cols += n
                # Reset count after processing a symbol
                count = ''
        # After processing a line, move to the next row
        rows += 1
        cols = 0
        if rows >= h:
            break  # Prevent exceeding the array height
    return arr





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 71, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' AssertionError: Wrong answer; got 1468671 instead of 1563304

Substring Evaluation

Testing if the previous output contains the string All tests passed: False