Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

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import numpy as np
import re

def rle_to_arr(rle_string, height, width):
    """
    Convert a Game of Life pattern in RLE format to a numpy array.

    Args:
    rle_string (str): The RLE string representing the Game of Life pattern.
    height (int): The height of the numpy array.
    width (int): The width of the numpy array.

    Returns:
    numpy.ndarray: A 2D numpy array representing the Game of Life pattern.
    """
    # Create an empty array filled with zeros
    arr = np.zeros((height, width), dtype=int)

    # Remove the '$' characters from the RLE string
    rle_string = rle_string.replace('$', '')

    # Split the RLE string into lines
    lines = rle_string.split('\n')

    # Initialize the x and y coordinates
    x, y = 0, 0

    # Iterate over each line in the RLE string
    for line in lines:
        # Initialize the count of consecutive characters
        count = ''

        # Iterate over each character in the line
        for char in line:
            # If the character is a digit, add it to the count
            if char.isdigit():
                count += char
            # If the character is a letter, process the count and the letter
            elif char.isalpha():
                # If the count is empty, set it to 1
                if not count:
                    count = '1'

                # Convert the count to an integer
                count = int(count)

                # Process the letter
                if char == 'b':
                    # Move the x coordinate forward by the count
                    x += count
                elif char == 'o':
                    # Fill the array with 1s at the current position and the next count-1 positions
                    for i in range(count):
                        if 0 <= x + i < width and 0 <= y < height:
                            arr[y, x + i] = 1
                    # Move the x coordinate forward by the count
                    x += count
                elif char == '!':
                    # Do nothing for the '!' character
                    pass

                # Reset the count
                count = ''

        # Move to the next line
        x = 0
        y += 1

    return arr

# Example usage:
rle_string = """26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b
2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$
60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b
o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b
o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b
2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"""

height = 100
width = 100

arr = rle_to_arr(rle_string, height, width)
print(arr)
This code defines a function `rle_to_arr` that takes an RLE string, a height, and a width as input and returns a 2D numpy array representing the Game of Life pattern. The function processes the RLE string line by line, filling the array with 1s at the positions specified by the 'o' characters and moving the x coordinate forward by the count specified by the 'b' characters. The function also handles the '!'' character, which marks the end of the pattern. The example usage demonstrates how to use the function to convert an RLE string to a numpy array.

Extract Code

I extracted the following code from that output: 

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import numpy as np
import re

def rle_to_arr(rle_string, height, width):
    """
    Convert a Game of Life pattern in RLE format to a numpy array.

    Args:
    rle_string (str): The RLE string representing the Game of Life pattern.
    height (int): The height of the numpy array.
    width (int): The width of the numpy array.

    Returns:
    numpy.ndarray: A 2D numpy array representing the Game of Life pattern.
    """
    # Create an empty array filled with zeros
    arr = np.zeros((height, width), dtype=int)

    # Remove the '$' characters from the RLE string
    rle_string = rle_string.replace('$', '')

    # Split the RLE string into lines
    lines = rle_string.split('\n')

    # Initialize the x and y coordinates
    x, y = 0, 0

    # Iterate over each line in the RLE string
    for line in lines:
        # Initialize the count of consecutive characters
        count = ''

        # Iterate over each character in the line
        for char in line:
            # If the character is a digit, add it to the count
            if char.isdigit():
                count += char
            # If the character is a letter, process the count and the letter
            elif char.isalpha():
                # If the count is empty, set it to 1
                if not count:
                    count = '1'

                # Convert the count to an integer
                count = int(count)

                # Process the letter
                if char == 'b':
                    # Move the x coordinate forward by the count
                    x += count
                elif char == 'o':
                    # Fill the array with 1s at the current position and the next count-1 positions
                    for i in range(count):
                        if 0 <= x + i < width and 0 <= y < height:
                            arr[y, x + i] = 1
                    # Move the x coordinate forward by the count
                    x += count
                elif char == '!':
                    # Do nothing for the '!' character
                    pass

                # Reset the count
                count = ''

        # Move to the next line
        x = 0
        y += 1

    return arr

# Example usage:
rle_string = """26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b
2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$
60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b
o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b
o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b
2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"""

height = 100
width = 100

arr = rle_to_arr(rle_string, height, width)
print(arr)

Run Code Interpreter

Running the following program: 

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import numpy as np
import re

def rle_to_arr(rle_string, height, width):
    """
    Convert a Game of Life pattern in RLE format to a numpy array.

    Args:
    rle_string (str): The RLE string representing the Game of Life pattern.
    height (int): The height of the numpy array.
    width (int): The width of the numpy array.

    Returns:
    numpy.ndarray: A 2D numpy array representing the Game of Life pattern.
    """
    # Create an empty array filled with zeros
    arr = np.zeros((height, width), dtype=int)

    # Remove the '$' characters from the RLE string
    rle_string = rle_string.replace('$', '')

    # Split the RLE string into lines
    lines = rle_string.split('\n')

    # Initialize the x and y coordinates
    x, y = 0, 0

    # Iterate over each line in the RLE string
    for line in lines:
        # Initialize the count of consecutive characters
        count = ''

        # Iterate over each character in the line
        for char in line:
            # If the character is a digit, add it to the count
            if char.isdigit():
                count += char
            # If the character is a letter, process the count and the letter
            elif char.isalpha():
                # If the count is empty, set it to 1
                if not count:
                    count = '1'

                # Convert the count to an integer
                count = int(count)

                # Process the letter
                if char == 'b':
                    # Move the x coordinate forward by the count
                    x += count
                elif char == 'o':
                    # Fill the array with 1s at the current position and the next count-1 positions
                    for i in range(count):
                        if 0 <= x + i < width and 0 <= y < height:
                            arr[y, x + i] = 1
                    # Move the x coordinate forward by the count
                    x += count
                elif char == '!':
                    # Do nothing for the '!' character
                    pass

                # Reset the count
                count = ''

        # Move to the next line
        x = 0
        y += 1

    return arr

# Example usage:
rle_string = """26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b
2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$
60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b
o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b
o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b
2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"""

height = 100
width = 100

arr = rle_to_arr(rle_string, height, width)
print(arr)





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: [[0 0 0 ... 0 0 0] [1 1 0 ... 0 0 0] [0 0 0 ... 0 0 0] ... [0 0 0 ... 0 0 0] [0 0 0 ... 0 0 0] [0 0 0 ... 0 0 0]] Traceback (most recent call last): File "/usr/src/app/main.py", line 107, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 88371 instead of 1563304

Substring Evaluation

Testing if the previous output contains the string All tests passed: False