Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

To convert the given RLE (Run Length Encoded) string of a Game of Life pattern to a numpy array, we'll follow these steps: 1. Parse the RLE string to understand how the pattern is encoded. 2. Implement the `rle_to_arr` function that takes the RLE string, height `h`, and width `w` of the desired output numpy array. 3. Decode the RLE string and populate the numpy array accordingly. Parsing RLE: - The RLE encoding describes the pattern in a compact form. Each part of the RLE consists of a number (optional, defaults to 1 if absent) followed by a character. The character indicates what to do: - 'b' means a run of dead cells (0s). - 'o' means a run of alive cells (1s). - '$' indicates the end of a line, moving down to the next row. - '!' marks the end of the pattern (not present in your string but typically used in RLEs). Let's implement the `rle_to_arr` function: 

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import numpy as np

def rle_to_arr(rle_string, h, w):
    # Initialize an empty numpy array of the specified height and width
    arr = np.zeros((h, w), dtype=int)
    
    # Variables to keep track of the current position
    x, y = 0, 0
    
    # Variable to store the current run length as we parse it
    run_length = ''
    
    for char in rle_string:
        if char.isdigit():
            # If the character is a digit, add it to the run_length string
            run_length += char
        elif char == 'b':
            # 'b' indicates a run of dead cells. We can essentially skip these,
            # but we need to move x accordingly.
            length = int(run_length) if run_length else 1
            x += length
            run_length = ''
        elif char == 'o':
            # 'o' indicates a run of alive cells. Fill these in the array.
            length = int(run_length) if run_length else 1
            for _ in range(length):
                if y >= h or x >= w:
                    break  # Safety check
                arr[y, x] = 1
                x += 1
            run_length = ''
        elif char == '$':
            # Move down to the next line
            y += 1
            x = 0
            run_length = ''
        # We ignore the '!' since your pattern doesn't seem to use it to mark the end.

    return arr

# Convert the RLE to numpy array with specified dimensions
rle_string = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
h = 80  # height of the array
w = 80  # width of the array

# Call the function with the given RLE string and dimensions
arr = rle_to_arr(rle_string, h, w)

# Checking the shape of the array to ensure it's correct
print(arr.shape)
This function should correctly parse the provided RLE string and fill a numpy array of the specified dimensions with the pattern. Make sure to adjust `h` and `w` to fit the entire pattern if needed.

Extract Code

I extracted the following code from that output: 

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import numpy as np

def rle_to_arr(rle_string, h, w):
    # Initialize an empty numpy array of the specified height and width
    arr = np.zeros((h, w), dtype=int)
    
    # Variables to keep track of the current position
    x, y = 0, 0
    
    # Variable to store the current run length as we parse it
    run_length = ''
    
    for char in rle_string:
        if char.isdigit():
            # If the character is a digit, add it to the run_length string
            run_length += char
        elif char == 'b':
            # 'b' indicates a run of dead cells. We can essentially skip these,
            # but we need to move x accordingly.
            length = int(run_length) if run_length else 1
            x += length
            run_length = ''
        elif char == 'o':
            # 'o' indicates a run of alive cells. Fill these in the array.
            length = int(run_length) if run_length else 1
            for _ in range(length):
                if y >= h or x >= w:
                    break  # Safety check
                arr[y, x] = 1
                x += 1
            run_length = ''
        elif char == '$':
            # Move down to the next line
            y += 1
            x = 0
            run_length = ''
        # We ignore the '!' since your pattern doesn't seem to use it to mark the end.

    return arr

# Convert the RLE to numpy array with specified dimensions
rle_string = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
h = 80  # height of the array
w = 80  # width of the array

# Call the function with the given RLE string and dimensions
arr = rle_to_arr(rle_string, h, w)

# Checking the shape of the array to ensure it's correct
print(arr.shape)

Run Code Interpreter

Running the following program: 

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import numpy as np

def rle_to_arr(rle_string, h, w):
    # Initialize an empty numpy array of the specified height and width
    arr = np.zeros((h, w), dtype=int)
    
    # Variables to keep track of the current position
    x, y = 0, 0
    
    # Variable to store the current run length as we parse it
    run_length = ''
    
    for char in rle_string:
        if char.isdigit():
            # If the character is a digit, add it to the run_length string
            run_length += char
        elif char == 'b':
            # 'b' indicates a run of dead cells. We can essentially skip these,
            # but we need to move x accordingly.
            length = int(run_length) if run_length else 1
            x += length
            run_length = ''
        elif char == 'o':
            # 'o' indicates a run of alive cells. Fill these in the array.
            length = int(run_length) if run_length else 1
            for _ in range(length):
                if y >= h or x >= w:
                    break  # Safety check
                arr[y, x] = 1
                x += 1
            run_length = ''
        elif char == '$':
            # Move down to the next line
            y += 1
            x = 0
            run_length = ''
        # We ignore the '!' since your pattern doesn't seem to use it to mark the end.

    return arr

# Convert the RLE to numpy array with specified dimensions
rle_string = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
h = 80  # height of the array
w = 80  # width of the array

# Call the function with the given RLE string and dimensions
arr = rle_to_arr(rle_string, h, w)

# Checking the shape of the array to ensure it's correct
print(arr.shape)





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: (80, 80) Traceback (most recent call last): File "/usr/src/app/main.py", line 74, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 1468671 instead of 1563304

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

To convert a Game of Life pattern given in RLE (Run Length Encoded) format into a numpy array, we need to first parse the RLE string and then fill a numpy array of the specified height (`h`) and width (`w`) with 1s and 0s based on the pattern. Here's a Python function that does this: 

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import numpy as np

def rle_to_arr(rle_string, h, w):
    # Initialize an empty numpy array of the given dimensions
    arr = np.zeros((h, w), dtype=int)
    
    # Remove any whitespace or newlines from the RLE string
    rle_string = rle_string.replace('\n', '').replace(' ', '')
    
    # Split the RLE string into its components (ignoring metadata if present)
    parts = rle_string.split('$')
    
    # Variables to keep track of the current position in the array
    x, y = 0, 0
    
    for part in parts:
        if not part:  # Skip empty strings resulting from consecutive $ signs
            y += 1
            x = 0
            continue
        
        i = 0
        while i < len(part):
            if part[i].isdigit():
                # If the current character is a digit, find the full number
                # and the next character after the number
                start = i
                while i + 1 < len(part) and part[i + 1].isdigit():
                    i += 1
                num = int(part[start:i + 1])
                i += 1  # Move to the character after the number
                
                if part[i] == 'b':
                    # 'b' means dead cells
                    x += num
                elif part[i] == 'o':
                    # 'o' means alive cells, fill with 1s
                    arr[y, x:x + num] = 1
                    x += num
            else:
                if part[i] == 'b':
                    x += 1
                elif part[i] == 'o':
                    arr[y, x] = 1
                    x += 1
                i += 1
        
        # Move to the next line after each part
        y += 1
        x = 0
    
    return arr

# Example usage
rle_string = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
height = 110  # Estimated height for the pattern
width = 80    # Estimated width for the pattern

arr = rle_to_arr(rle_string, height, width)
print(arr.shape)
# The output will be (110, 80), which is the shape of the numpy array
This function assumes that the RLE string provided does not have metadata (like name, author, or comments) and that the pattern itself starts immediately. Adjust the `height` and `width` parameters as necessary for the specific pattern you're converting.

Extract Code

I extracted the following code from that output: 

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import numpy as np

def rle_to_arr(rle_string, h, w):
    # Initialize an empty numpy array of the given dimensions
    arr = np.zeros((h, w), dtype=int)
    
    # Remove any whitespace or newlines from the RLE string
    rle_string = rle_string.replace('\n', '').replace(' ', '')
    
    # Split the RLE string into its components (ignoring metadata if present)
    parts = rle_string.split('$')
    
    # Variables to keep track of the current position in the array
    x, y = 0, 0
    
    for part in parts:
        if not part:  # Skip empty strings resulting from consecutive $ signs
            y += 1
            x = 0
            continue
        
        i = 0
        while i < len(part):
            if part[i].isdigit():
                # If the current character is a digit, find the full number
                # and the next character after the number
                start = i
                while i + 1 < len(part) and part[i + 1].isdigit():
                    i += 1
                num = int(part[start:i + 1])
                i += 1  # Move to the character after the number
                
                if part[i] == 'b':
                    # 'b' means dead cells
                    x += num
                elif part[i] == 'o':
                    # 'o' means alive cells, fill with 1s
                    arr[y, x:x + num] = 1
                    x += num
            else:
                if part[i] == 'b':
                    x += 1
                elif part[i] == 'o':
                    arr[y, x] = 1
                    x += 1
                i += 1
        
        # Move to the next line after each part
        y += 1
        x = 0
    
    return arr

# Example usage
rle_string = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
height = 110  # Estimated height for the pattern
width = 80    # Estimated width for the pattern

arr = rle_to_arr(rle_string, height, width)
print(arr.shape)
# The output will be (110, 80), which is the shape of the numpy array

Run Code Interpreter

Running the following program: 

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import numpy as np

def rle_to_arr(rle_string, h, w):
    # Initialize an empty numpy array of the given dimensions
    arr = np.zeros((h, w), dtype=int)
    
    # Remove any whitespace or newlines from the RLE string
    rle_string = rle_string.replace('\n', '').replace(' ', '')
    
    # Split the RLE string into its components (ignoring metadata if present)
    parts = rle_string.split('$')
    
    # Variables to keep track of the current position in the array
    x, y = 0, 0
    
    for part in parts:
        if not part:  # Skip empty strings resulting from consecutive $ signs
            y += 1
            x = 0
            continue
        
        i = 0
        while i < len(part):
            if part[i].isdigit():
                # If the current character is a digit, find the full number
                # and the next character after the number
                start = i
                while i + 1 < len(part) and part[i + 1].isdigit():
                    i += 1
                num = int(part[start:i + 1])
                i += 1  # Move to the character after the number
                
                if part[i] == 'b':
                    # 'b' means dead cells
                    x += num
                elif part[i] == 'o':
                    # 'o' means alive cells, fill with 1s
                    arr[y, x:x + num] = 1
                    x += num
            else:
                if part[i] == 'b':
                    x += 1
                elif part[i] == 'o':
                    arr[y, x] = 1
                    x += 1
                i += 1
        
        # Move to the next line after each part
        y += 1
        x = 0
    
    return arr

# Example usage
rle_string = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
height = 110  # Estimated height for the pattern
width = 80    # Estimated width for the pattern

arr = rle_to_arr(rle_string, height, width)
print(arr.shape)
# The output will be (110, 80), which is the shape of the numpy array





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 60, in <module> arr = rle_to_arr(rle_string, height, width) ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 34, in rle_to_arr if part[i] == 'b': ~~~~^^^ IndexError: string index out of range

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

To convert the given Game of Life pattern in RLE (Run Length Encoded) format to a NumPy array, we need to first understand the RLE format and then write a function to parse it into a grid. The given RLE string encodes a pattern where `$` is used to denote the end of a line (row), `b` represents a dead cell, and `o` represents a live cell. Numbers before a character indicate how many of that character there are in a row. If there's no number, it means there's just one of that character. Below is the Python function `rle_to_arr` that takes an RLE string and dimensions (height `h` and width `w`) as input and returns a NumPy array with the specified dimensions, filled according to the pattern: 

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import numpy as np

def rle_to_arr(rle_string, h, w):
    # Initialize an empty array.
    arr = np.zeros((h, w), dtype=int)
    
    # Split the RLE string into lines.
    lines = rle_string.split('$')
    
    row = 0
    for line in lines:
        col = 0
        while col < len(line):
            c = line[col]
            
            # Determine the run length (default is 1).
            run_length = 1
            if c.isdigit():
                # Extract the full number.
                num_start = col
                while col + 1 < len(line) and line[col + 1].isdigit():
                    col += 1
                run_length = int(line[num_start:col+1])
                col += 1
                c = line[col]
            
            # Fill the array based on the character.
            if c == 'b':
                # 'b' means dead cells, which are already 0 in the initialized array.
                pass
            elif c == 'o':
                arr[row, col:col+run_length] = 1
            
            col += run_length
        
        row += 1
    
    return arr

# Example usage:
rle_string = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
h, w = 100, 100  # Example dimensions; adjust as necessary for the pattern

arr = rle_to_arr(rle_string, h, w)
print(arr.shape)
# Output should be (100, 100)
Please note that the dimensions (height `h` and width `w`) need to be adjusted according to the expected size of the output array to ensure the entire pattern fits. The example dimensions `(100, 100)` used above might not perfectly match the pattern's actual size, so you might need to adjust them based on the pattern's requirements.

Extract Code

I extracted the following code from that output: 

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import numpy as np

def rle_to_arr(rle_string, h, w):
    # Initialize an empty array.
    arr = np.zeros((h, w), dtype=int)
    
    # Split the RLE string into lines.
    lines = rle_string.split('$')
    
    row = 0
    for line in lines:
        col = 0
        while col < len(line):
            c = line[col]
            
            # Determine the run length (default is 1).
            run_length = 1
            if c.isdigit():
                # Extract the full number.
                num_start = col
                while col + 1 < len(line) and line[col + 1].isdigit():
                    col += 1
                run_length = int(line[num_start:col+1])
                col += 1
                c = line[col]
            
            # Fill the array based on the character.
            if c == 'b':
                # 'b' means dead cells, which are already 0 in the initialized array.
                pass
            elif c == 'o':
                arr[row, col:col+run_length] = 1
            
            col += run_length
        
        row += 1
    
    return arr

# Example usage:
rle_string = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
h, w = 100, 100  # Example dimensions; adjust as necessary for the pattern

arr = rle_to_arr(rle_string, h, w)
print(arr.shape)
# Output should be (100, 100)

Run Code Interpreter

Running the following program: 

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import numpy as np

def rle_to_arr(rle_string, h, w):
    # Initialize an empty array.
    arr = np.zeros((h, w), dtype=int)
    
    # Split the RLE string into lines.
    lines = rle_string.split('$')
    
    row = 0
    for line in lines:
        col = 0
        while col < len(line):
            c = line[col]
            
            # Determine the run length (default is 1).
            run_length = 1
            if c.isdigit():
                # Extract the full number.
                num_start = col
                while col + 1 < len(line) and line[col + 1].isdigit():
                    col += 1
                run_length = int(line[num_start:col+1])
                col += 1
                c = line[col]
            
            # Fill the array based on the character.
            if c == 'b':
                # 'b' means dead cells, which are already 0 in the initialized array.
                pass
            elif c == 'o':
                arr[row, col:col+run_length] = 1
            
            col += run_length
        
        row += 1
    
    return arr

# Example usage:
rle_string = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
h, w = 100, 100  # Example dimensions; adjust as necessary for the pattern

arr = rle_to_arr(rle_string, h, w)
print(arr.shape)
# Output should be (100, 100)





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 45, in <module> arr = rle_to_arr(rle_string, h, w) ^^^^^^^^^^^^^^^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 26, in rle_to_arr c = line[col] ~~~~^^^^^ IndexError: string index out of range

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

To convert the given Game of Life pattern from RLE (Run Length Encoded) format to a NumPy array, we need to first understand the RLE format and then write a function to decode this format into a 2D array of the specified height (`h`) and width (`w`). The provided RLE string represents the pattern, where `$` separates rows, numbers before a letter indicate the number of times that letter should be repeated (with `b` representing a dead cell or 0, and `o` representing a live cell or 1), and `!` marks the end of the pattern. Here's how to do it: 1. Install NumPy if you haven't yet. You can do this using pip: 

1
pip install numpy
2. Use the following Python code to define the function `rle_to_arr`: 
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import numpy as np

def rle_to_arr(rle_str, h, w):
    # Initialize an empty numpy array of given dimensions
    arr = np.zeros((h, w), dtype=int)
    
    # Split the RLE string into rows
    rows = rle_str.split('$')
    
    row_idx = 0
    for row in rows:
        col_idx = 0
        # Iterate through each character in a row
        i = 0
        while i < len(row):
            if row[i].isdigit():
                # If the character is a digit, find the full number
                num_start = i
                while i + 1 < len(row) and row[i + 1].isdigit():
                    i += 1
                num = int(row[num_start:i + 1])
            else:
                num = 1

            if row[i] == 'b':
                # 'b' represents dead cells, so we skip these (they're already 0)
                col_idx += num
            elif row[i] == 'o':
                # 'o' represents live cells
                arr[row_idx, col_idx:col_idx + num] = 1
                col_idx += num
            i += 1
        
        row_idx += 1
    
    return arr

# Your RLE string
rle_str = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"

# Specify the dimensions of the output array
height = 100  # Example height
width = 100   # Example width

# Convert the RLE to a numpy array
arr = rle_to_arr(rle_str, height, width)

# Print or use the numpy array as needed
print(arr)
Make sure you adjust the `height` and `width` variables to fit the actual dimensions of the pattern you're trying to convert. The code above initializes an all-zero NumPy array and then fills in `1`s where the RLE string indicates live cells. This solution assumes you have a basic understanding of Python and NumPy.

Extract Code

I extracted the following code from that output: 

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import numpy as np

def rle_to_arr(rle_str, h, w):
    # Initialize an empty numpy array of given dimensions
    arr = np.zeros((h, w), dtype=int)
    
    # Split the RLE string into rows
    rows = rle_str.split('$')
    
    row_idx = 0
    for row in rows:
        col_idx = 0
        # Iterate through each character in a row
        i = 0
        while i < len(row):
            if row[i].isdigit():
                # If the character is a digit, find the full number
                num_start = i
                while i + 1 < len(row) and row[i + 1].isdigit():
                    i += 1
                num = int(row[num_start:i + 1])
            else:
                num = 1

            if row[i] == 'b':
                # 'b' represents dead cells, so we skip these (they're already 0)
                col_idx += num
            elif row[i] == 'o':
                # 'o' represents live cells
                arr[row_idx, col_idx:col_idx + num] = 1
                col_idx += num
            i += 1
        
        row_idx += 1
    
    return arr

Run Code Interpreter

Running the following program: 

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import numpy as np

def rle_to_arr(rle_str, h, w):
    # Initialize an empty numpy array of given dimensions
    arr = np.zeros((h, w), dtype=int)
    
    # Split the RLE string into rows
    rows = rle_str.split('$')
    
    row_idx = 0
    for row in rows:
        col_idx = 0
        # Iterate through each character in a row
        i = 0
        while i < len(row):
            if row[i].isdigit():
                # If the character is a digit, find the full number
                num_start = i
                while i + 1 < len(row) and row[i + 1].isdigit():
                    i += 1
                num = int(row[num_start:i + 1])
            else:
                num = 1

            if row[i] == 'b':
                # 'b' represents dead cells, so we skip these (they're already 0)
                col_idx += num
            elif row[i] == 'o':
                # 'o' represents live cells
                arr[row_idx, col_idx:col_idx + num] = 1
                col_idx += num
            i += 1
        
        row_idx += 1
    
    return arr





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 60, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 884523 instead of 1563304

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

To convert a Run Length Encoded (RLE) representation of a Game of Life pattern to a numpy array, you can follow these steps: 1. **Initialize an empty numpy array** with the given height `h` and width `w`, filled with zeros. 2. **Parse the RLE string**: The RLE string consists of numbers followed by characters (`b` for empty space, `o` for a live cell, `$` for a new line). Numbers indicate how many times the following character repeats. If there's no number, it means the character repeats once. 3. **Fill the numpy array** accordingly: Iterate through the parsed RLE string, updating the numpy array with 1s for live cells and leaving 0s for empty spaces. Here's a Python function that does this: 

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import numpy as np

def rle_to_arr(rle_string, h, w):
    # Initialize an empty array with given dimensions, filled with zeros
    arr = np.zeros((h, w), dtype=int)

    # Current position in the array
    x, y = 0, 0

    # Parse the RLE string
    count = ''
    for char in rle_string:
        if char.isdigit():
            # If the character is a digit, add it to the count
            count += char
        else:
            # If the character is not a digit, process the count (if any)
            # and the character
            if count == '':
                num = 1
            else:
                num = int(count)
            count = ''  # Reset count for the next sequence

            if char == 'b':
                # b for empty space, just move x
                x += num
            elif char == 'o':
                # o for a live cell, fill the array with 1s and move x
                for _ in range(num):
                    arr[y, x] = 1
                    x += 1
            elif char == '$':
                # $ for a new line, move y and reset x
                y += num
                x = 0

    return arr

# Example usage (with a small example for brevity)
rle_string = "3o$2bo$3b2o!"
h, w = 3, 4  # Height and width of the resulting array
arr = rle_to_arr(rle_string, h, w)
print(arr)
Replace the example `rle_string` with your actual RLE string and adjust `h` and `w` accordingly to convert your specific Game of Life pattern. Note that the function assumes the RLE string does not contain metadata (like comments starting with `#`), as in the given example.

Extract Code

I extracted the following code from that output: 

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import numpy as np

def rle_to_arr(rle_string, h, w):
    # Initialize an empty array with given dimensions, filled with zeros
    arr = np.zeros((h, w), dtype=int)

    # Current position in the array
    x, y = 0, 0

    # Parse the RLE string
    count = ''
    for char in rle_string:
        if char.isdigit():
            # If the character is a digit, add it to the count
            count += char
        else:
            # If the character is not a digit, process the count (if any)
            # and the character
            if count == '':
                num = 1
            else:
                num = int(count)
            count = ''  # Reset count for the next sequence

            if char == 'b':
                # b for empty space, just move x
                x += num
            elif char == 'o':
                # o for a live cell, fill the array with 1s and move x
                for _ in range(num):
                    arr[y, x] = 1
                    x += 1
            elif char == '$':
                # $ for a new line, move y and reset x
                y += num
                x = 0

    return arr

# Example usage (with a small example for brevity)
rle_string = "3o$2bo$3b2o!"
h, w = 3, 4  # Height and width of the resulting array
arr = rle_to_arr(rle_string, h, w)
print(arr)

Run Code Interpreter

Running the following program: 

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import numpy as np

def rle_to_arr(rle_string, h, w):
    # Initialize an empty array with given dimensions, filled with zeros
    arr = np.zeros((h, w), dtype=int)

    # Current position in the array
    x, y = 0, 0

    # Parse the RLE string
    count = ''
    for char in rle_string:
        if char.isdigit():
            # If the character is a digit, add it to the count
            count += char
        else:
            # If the character is not a digit, process the count (if any)
            # and the character
            if count == '':
                num = 1
            else:
                num = int(count)
            count = ''  # Reset count for the next sequence

            if char == 'b':
                # b for empty space, just move x
                x += num
            elif char == 'o':
                # o for a live cell, fill the array with 1s and move x
                for _ in range(num):
                    arr[y, x] = 1
                    x += 1
            elif char == '$':
                # $ for a new line, move y and reset x
                y += num
                x = 0

    return arr

# Example usage (with a small example for brevity)
rle_string = "3o$2bo$3b2o!"
h, w = 3, 4  # Height and width of the resulting array
arr = rle_to_arr(rle_string, h, w)
print(arr)





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 44, in <module> arr = rle_to_arr(rle_string, h, w) ^^^^^^^^^^^^^^^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 32, in rle_to_arr arr[y, x] = 1 ~~~^^^^^^ IndexError: index 4 is out of bounds for axis 1 with size 4

Substring Evaluation

Testing if the previous output contains the string All tests passed: False