Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

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import numpy as np

def rle_to_arr(string, h, w):
  """Converts a RLE string to a numpy array.

  Args:
    string: The RLE string.
    h: The height of the array.
    w: The width of the array.

  Returns:
    A numpy array with shape (h, w).
  """

  arr = np.zeros((h, w), dtype=np.int8)
  i = 0
  j = 0
  while i < len(string):
    if string[i] == '$':
      j += int(string[i+1:i+3])
      i += 3
    elif string[i] == 'o':
      arr[i, j] = 1
      j += 1
      i += 1
    elif string[i] == 'b':
      arr[i, j:j+int(string[i+1:i+3])] = 1
      j += int(string[i+1:i+3])
      i += 3
  return arr

string = '26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!'
h = 77
w = 77
arr = rle_to_arr(string, h, w)

Extract Code

I extracted the following code from that output:

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import numpy as np

def rle_to_arr(string, h, w):
  """Converts a RLE string to a numpy array.

  Args:
    string: The RLE string.
    h: The height of the array.
    w: The width of the array.

  Returns:
    A numpy array with shape (h, w).
  """

  arr = np.zeros((h, w), dtype=np.int8)
  i = 0
  j = 0
  while i < len(string):
    if string[i] == '$':
      j += int(string[i+1:i+3])
      i += 3
    elif string[i] == 'o':
      arr[i, j] = 1
      j += 1
      i += 1
    elif string[i] == 'b':
      arr[i, j:j+int(string[i+1:i+3])] = 1
      j += int(string[i+1:i+3])
      i += 3
  return arr

string = '26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!'
h = 77
w = 77
arr = rle_to_arr(string, h, w)

Run Code Interpreter

Running the following program:

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import numpy as np

def rle_to_arr(string, h, w):
  """Converts a RLE string to a numpy array.

  Args:
    string: The RLE string.
    h: The height of the array.
    w: The width of the array.

  Returns:
    A numpy array with shape (h, w).
  """

  arr = np.zeros((h, w), dtype=np.int8)
  i = 0
  j = 0
  while i < len(string):
    if string[i] == '$':
      j += int(string[i+1:i+3])
      i += 3
    elif string[i] == 'o':
      arr[i, j] = 1
      j += 1
      i += 1
    elif string[i] == 'b':
      arr[i, j:j+int(string[i+1:i+3])] = 1
      j += int(string[i+1:i+3])
      i += 3
  return arr

string = '26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!'
h = 77
w = 77
arr = rle_to_arr(string, h, w)





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Timeout: function took too long to complete

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

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import numpy as np

def rle_to_arr(string, h, w):
  """Converts a run-length encoded string to a numpy array.

  Args:
    string: The run-length encoded string.
    h: The height of the array.
    w: The width of the array.

  Returns:
    A numpy array with shape (h, w).
  """

  # Initialize the array with 0s.
  arr = np.zeros((h, w), dtype=np.int8)

  # Parse the run-length encoded string.
  i = 0
  while i < len(string):
    # Get the number of consecutive cells.
    count = int(string[i])

    # Get the value of the consecutive cells.
    value = 1 if string[i+1] == "b" else 0

    # Set the consecutive cells to the value.
    arr[i//w:(i+count)//w, i%w:(i+count)%w] = value

    # Increment the index.
    i += 2

  return arr


# Convert the game of life pattern to a numpy array.
arr = rle_to_arr("26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b\
2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b\
o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b\
o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o\
3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!", 76, 66)

# Print the array.
print(arr)

Extract Code

I extracted the following code from that output:

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import numpy as np

def rle_to_arr(string, h, w):
  """Converts a run-length encoded string to a numpy array.

  Args:
    string: The run-length encoded string.
    h: The height of the array.
    w: The width of the array.

  Returns:
    A numpy array with shape (h, w).
  """

  # Initialize the array with 0s.
  arr = np.zeros((h, w), dtype=np.int8)

  # Parse the run-length encoded string.
  i = 0
  while i < len(string):
    # Get the number of consecutive cells.
    count = int(string[i])

    # Get the value of the consecutive cells.
    value = 1 if string[i+1] == "b" else 0

    # Set the consecutive cells to the value.
    arr[i//w:(i+count)//w, i%w:(i+count)%w] = value

    # Increment the index.
    i += 2

  return arr


# Convert the game of life pattern to a numpy array.
arr = rle_to_arr("26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b\
2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b\
o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b\
o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o\
3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!", 76, 66)

# Print the array.
print(arr)

Run Code Interpreter

Running the following program:

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import numpy as np

def rle_to_arr(string, h, w):
  """Converts a run-length encoded string to a numpy array.

  Args:
    string: The run-length encoded string.
    h: The height of the array.
    w: The width of the array.

  Returns:
    A numpy array with shape (h, w).
  """

  # Initialize the array with 0s.
  arr = np.zeros((h, w), dtype=np.int8)

  # Parse the run-length encoded string.
  i = 0
  while i < len(string):
    # Get the number of consecutive cells.
    count = int(string[i])

    # Get the value of the consecutive cells.
    value = 1 if string[i+1] == "b" else 0

    # Set the consecutive cells to the value.
    arr[i//w:(i+count)//w, i%w:(i+count)%w] = value

    # Increment the index.
    i += 2

  return arr


# Convert the game of life pattern to a numpy array.
arr = rle_to_arr("26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b\
2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b\
o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b\
o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o\
3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!", 76, 66)

# Print the array.
print(arr)





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 38, in <module> arr = rle_to_arr("26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b\ ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 23, in rle_to_arr count = int(string[i]) ^^^^^^^^^^^^^^ ValueError: invalid literal for int() with base 10: '$'

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

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import numpy as np

def rle_to_arr(string, h, w):
  arr = np.zeros((h, w), dtype=int)
  i = 0
  j = 0
  while i < len(string):
    if string[i] == '$':
      i += 1
      j = 0
      continue
    elif string[i] == 'b':
      arr[i, j] = 1
      j += 1
      i += 1
    elif string[i] == 'o':
      num_zeros = int(string[i+1:i+3])
      j += num_zeros
      i += 3
    else:
      i += 1
  return arr

arr = rle_to_arr('26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b\
2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$\
52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o\
10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55b\
o3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!', 76, 80)

print(arr)

Extract Code

I extracted the following code from that output:

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import numpy as np

def rle_to_arr(string, h, w):
  arr = np.zeros((h, w), dtype=int)
  i = 0
  j = 0
  while i < len(string):
    if string[i] == '$':
      i += 1
      j = 0
      continue
    elif string[i] == 'b':
      arr[i, j] = 1
      j += 1
      i += 1
    elif string[i] == 'o':
      num_zeros = int(string[i+1:i+3])
      j += num_zeros
      i += 3
    else:
      i += 1
  return arr

arr = rle_to_arr('26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b\
2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$\
52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o\
10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55b\
o3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!', 76, 80)

print(arr)

Run Code Interpreter

Running the following program:

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import numpy as np

def rle_to_arr(string, h, w):
  arr = np.zeros((h, w), dtype=int)
  i = 0
  j = 0
  while i < len(string):
    if string[i] == '$':
      i += 1
      j = 0
      continue
    elif string[i] == 'b':
      arr[i, j] = 1
      j += 1
      i += 1
    elif string[i] == 'o':
      num_zeros = int(string[i+1:i+3])
      j += num_zeros
      i += 3
    else:
      i += 1
  return arr

arr = rle_to_arr('26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b\
2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$\
52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o\
10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55b\
o3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!', 76, 80)

print(arr)





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 25, in <module> arr = rle_to_arr('26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b\ ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 18, in rle_to_arr num_zeros = int(string[i+1:i+3]) ^^^^^^^^^^^^^^^^^^^^ ValueError: invalid literal for int() with base 10: '$1'

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

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import numpy as np

def rle_to_arr(string, h, w):
  """Converts a run-length encoded string to a numpy array.

  Args:
    string: The run-length encoded string.
    h: The height of the array.
    w: The width of the array.

  Returns:
    A numpy array with shape (h, w).
  """

  arr = np.zeros((h, w), dtype=np.int8)
  i = 0
  j = 0
  while i < len(string):
    char = string[i]
    if char.isdigit():
      count = int(char)
      i += 1
      if string[i] == 'b':
        arr[j:j+count, :] = 1
        j += count
      elif string[i] == 'o':
        j += count
      else:
        raise ValueError("Invalid character in RLE string: {}".format(string[i]))
    else:
      raise ValueError("Invalid character in RLE string: {}".format(char))
    i += 1

  return arr

pattern = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b\
2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$\
60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b\
o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b\
o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o\
3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"

arr = rle_to_arr(pattern, 76, 76)
print(arr)

Extract Code

I extracted the following code from that output:

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import numpy as np

def rle_to_arr(string, h, w):
  """Converts a run-length encoded string to a numpy array.

  Args:
    string: The run-length encoded string.
    h: The height of the array.
    w: The width of the array.

  Returns:
    A numpy array with shape (h, w).
  """

  arr = np.zeros((h, w), dtype=np.int8)
  i = 0
  j = 0
  while i < len(string):
    char = string[i]
    if char.isdigit():
      count = int(char)
      i += 1
      if string[i] == 'b':
        arr[j:j+count, :] = 1
        j += count
      elif string[i] == 'o':
        j += count
      else:
        raise ValueError("Invalid character in RLE string: {}".format(string[i]))
    else:
      raise ValueError("Invalid character in RLE string: {}".format(char))
    i += 1

  return arr

pattern = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b\
2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$\
60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b\
o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b\
o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o\
3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"

arr = rle_to_arr(pattern, 76, 76)
print(arr)

Run Code Interpreter

Running the following program:

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import numpy as np

def rle_to_arr(string, h, w):
  """Converts a run-length encoded string to a numpy array.

  Args:
    string: The run-length encoded string.
    h: The height of the array.
    w: The width of the array.

  Returns:
    A numpy array with shape (h, w).
  """

  arr = np.zeros((h, w), dtype=np.int8)
  i = 0
  j = 0
  while i < len(string):
    char = string[i]
    if char.isdigit():
      count = int(char)
      i += 1
      if string[i] == 'b':
        arr[j:j+count, :] = 1
        j += count
      elif string[i] == 'o':
        j += count
      else:
        raise ValueError("Invalid character in RLE string: {}".format(string[i]))
    else:
      raise ValueError("Invalid character in RLE string: {}".format(char))
    i += 1

  return arr

pattern = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b\
2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$\
60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b\
o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b\
o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o\
3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"

arr = rle_to_arr(pattern, 76, 76)
print(arr)





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 44, in <module> arr = rle_to_arr(pattern, 76, 76) ^^^^^^^^^^^^^^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 30, in rle_to_arr raise ValueError("Invalid character in RLE string: {}".format(string[i])) ValueError: Invalid character in RLE string: 6

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

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import numpy as np

def rle_to_arr(string, h, w):
  """Converts a run-length encoded string to a numpy array.

  Args:
    string: The run-length encoded string.
    h: The height of the array.
    w: The width of the array.

  Returns:
    A numpy array with shape (h, w).
  """

  # Create an empty array to store the pattern.
  arr = np.zeros((h, w), dtype=np.int8)

  # Parse the string and fill the array.
  i = 0
  j = 0
  while i < len(string):
    # Get the next character.
    char = string[i]

    # Check if the character is a number.
    if char.isdigit():
      # Get the number of empty cells.
      num_empty = int(char)

      # Fill the next cells with empty.
      for k in range(num_empty):
        arr[j, i + k] = 0

      # Increment the column index.
      i += num_empty

    # Check if the character is a 'b'.
    elif char == 'b':
      # Get the number of filled cells.
      num_filled = int(string[i + 1])

      # Fill the next cells with filled.
      for k in range(num_filled):
        arr[j, i + k] = 1

      # Increment the column index.
      i += 2

    # Increment the row index.
    j += 1

  # Return the array.
  return arr

# Example usage.
string = '26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!'
h = 76
w = 80
arr = rle_to_arr(string, h, w)
print(arr)

Extract Code

I extracted the following code from that output:

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import numpy as np

def rle_to_arr(string, h, w):
  """Converts a run-length encoded string to a numpy array.

  Args:
    string: The run-length encoded string.
    h: The height of the array.
    w: The width of the array.

  Returns:
    A numpy array with shape (h, w).
  """

  # Create an empty array to store the pattern.
  arr = np.zeros((h, w), dtype=np.int8)

  # Parse the string and fill the array.
  i = 0
  j = 0
  while i < len(string):
    # Get the next character.
    char = string[i]

    # Check if the character is a number.
    if char.isdigit():
      # Get the number of empty cells.
      num_empty = int(char)

      # Fill the next cells with empty.
      for k in range(num_empty):
        arr[j, i + k] = 0

      # Increment the column index.
      i += num_empty

    # Check if the character is a 'b'.
    elif char == 'b':
      # Get the number of filled cells.
      num_filled = int(string[i + 1])

      # Fill the next cells with filled.
      for k in range(num_filled):
        arr[j, i + k] = 1

      # Increment the column index.
      i += 2

    # Increment the row index.
    j += 1

  # Return the array.
  return arr

# Example usage.
string = '26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!'
h = 76
w = 80
arr = rle_to_arr(string, h, w)
print(arr)

Run Code Interpreter

Running the following program:

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import numpy as np

def rle_to_arr(string, h, w):
  """Converts a run-length encoded string to a numpy array.

  Args:
    string: The run-length encoded string.
    h: The height of the array.
    w: The width of the array.

  Returns:
    A numpy array with shape (h, w).
  """

  # Create an empty array to store the pattern.
  arr = np.zeros((h, w), dtype=np.int8)

  # Parse the string and fill the array.
  i = 0
  j = 0
  while i < len(string):
    # Get the next character.
    char = string[i]

    # Check if the character is a number.
    if char.isdigit():
      # Get the number of empty cells.
      num_empty = int(char)

      # Fill the next cells with empty.
      for k in range(num_empty):
        arr[j, i + k] = 0

      # Increment the column index.
      i += num_empty

    # Check if the character is a 'b'.
    elif char == 'b':
      # Get the number of filled cells.
      num_filled = int(string[i + 1])

      # Fill the next cells with filled.
      for k in range(num_filled):
        arr[j, i + k] = 1

      # Increment the column index.
      i += 2

    # Increment the row index.
    j += 1

  # Return the array.
  return arr

# Example usage.
string = '26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!'
h = 76
w = 80
arr = rle_to_arr(string, h, w)
print(arr)





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Timeout: function took too long to complete

Substring Evaluation

Testing if the previous output contains the string All tests passed: False