Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.
Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.
To convert the given Game of Life pattern in Run-Length Encoding (RLE) format to a NumPy array, we can write a function `rle_to_arr` that parses the RLE string and fills a 2D NumPy array with 1s for live cells and 0s for dead cells. Here's how you can implement this:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 | import numpy as np def rle_to_arr(rle_string, h, w): # Initialize an empty array with zeros arr = np.zeros((h, w), dtype=int) # Split the RLE string into lines lines = rle_string.strip().split('$') # Initialize the current row and column row = 0 col = 0 for line in lines: # Initialize the current column to 0 for each new line col = 0 # Split the line into segments segments = line.split('b') for segment in segments: if segment == '': # Empty segment means a dead cell, so we skip it col += 1 else: # Split the segment into count and pattern if 'o' in segment: count, pattern = segment.split('o') count = int(count) if count else 1 # Fill the array with 1s for the live cells arr[row, col:col+count] = 1 col += count else: # If there's no 'o', it's a dead cell count = int(segment) if segment else 1 col += count # Move to the next row row += 1 return arr # Example usage: rle_string = """ 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! """ # Define the height and width of the array h = 80 w = 80 # Convert the RLE string to a NumPy array arr = rle_to_arr(rle_string, h, w) # Print the resulting array print(arr) |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 | import numpy as np def rle_to_arr(rle_string, h, w): # Initialize an empty array with zeros arr = np.zeros((h, w), dtype=int) # Split the RLE string into lines lines = rle_string.strip().split('$') # Initialize the current row and column row = 0 col = 0 for line in lines: # Initialize the current column to 0 for each new line col = 0 # Split the line into segments segments = line.split('b') for segment in segments: if segment == '': # Empty segment means a dead cell, so we skip it col += 1 else: # Split the segment into count and pattern if 'o' in segment: count, pattern = segment.split('o') count = int(count) if count else 1 # Fill the array with 1s for the live cells arr[row, col:col+count] = 1 col += count else: # If there's no 'o', it's a dead cell count = int(segment) if segment else 1 col += count # Move to the next row row += 1 return arr # Example usage: rle_string = """ 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! """ # Define the height and width of the array h = 80 w = 80 # Convert the RLE string to a NumPy array arr = rle_to_arr(rle_string, h, w) # Print the resulting array print(arr) |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 | import numpy as np def rle_to_arr(rle_string, h, w): # Initialize an empty array with zeros arr = np.zeros((h, w), dtype=int) # Split the RLE string into lines lines = rle_string.strip().split('$') # Initialize the current row and column row = 0 col = 0 for line in lines: # Initialize the current column to 0 for each new line col = 0 # Split the line into segments segments = line.split('b') for segment in segments: if segment == '': # Empty segment means a dead cell, so we skip it col += 1 else: # Split the segment into count and pattern if 'o' in segment: count, pattern = segment.split('o') count = int(count) if count else 1 # Fill the array with 1s for the live cells arr[row, col:col+count] = 1 col += count else: # If there's no 'o', it's a dead cell count = int(segment) if segment else 1 col += count # Move to the next row row += 1 return arr # Example usage: rle_string = """ 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! """ # Define the height and width of the array h = 80 w = 80 # Convert the RLE string to a NumPy array arr = rle_to_arr(rle_string, h, w) # Print the resulting array print(arr) answer = (np.array(rle_to_arr(''' 16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o 17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo 2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$ 22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo 8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$ 5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o 14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b 2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$ 21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo 14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b 2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo $o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b 2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o! ''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum() expected = 1563304 assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' print('All tests passed') |
Traceback (most recent call last):
File "/usr/src/app/main.py", line 59, in <module>
arr = rle_to_arr(rle_string, h, w)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/src/app/main.py", line 30, in rle_to_arr
count = int(count) if count else 1
^^^^^^^^^^
ValueError: invalid literal for int() with base 10: '\n'
Testing if the previous output contains the string All tests passed: False