Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

Sure, here's a Python function that converts the RLE (Run Length Encoded) string into a numpy array: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
import numpy as np

def rle_to_arr(pattern, h, w):
    arr = np.zeros((h, w), dtype=int)
    row = 0
    col = 0
    number = ''
    
    for char in pattern:
        if char.isdigit():
            number += char
        else:
            if number:
                repeat = int(number)
                number = ''
            else:
                repeat = 1
            
            if char == 'b':
                col += repeat
            elif char == 'o':
                arr[row, col] = 1
                col += 1
            elif char == '$':
                row += 1
                col = 0
            elif char == '!':
                break
    
    return arr

# Example usage
pattern = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
h = 77
w = 77

arr = rle_to_arr(pattern, h, w)
print(arr)
This function `rle_to_arr` takes three arguments: - `pattern`: The RLE string representing the pattern. - `h`: The desired height of the output array. - `w`: The desired width of the output array. The function initializes an empty numpy array `arr` with dimensions `(h, w)` and filled with zeros. It then iterates through the RLE string character by character, keeping track of the current row and column in the array. If the character is a digit, it appends it to the `number` string, representing the repetition count for the next character. If the character is not a digit, it processes the current `number` (or uses 1 if `number` is empty) and the current character: - If the character is `'b'`, it moves the column index forward by the repetition count. - If the character is `'o'`, it sets the corresponding cell in the array to 1 and moves the column index forward by 1. - If the character is `'$'`, it moves to the next row and resets the column index to 0. - If the character is `'!'`, it breaks out of the loop. After processing the entire pattern string, the function returns the populated numpy array `arr`. In the example usage, the provided RLE pattern is converted into a numpy array with shape `(77, 77)`, and the resulting array is printed.

Extract Code

I extracted the following code from that output: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
import numpy as np

def rle_to_arr(pattern, h, w):
    arr = np.zeros((h, w), dtype=int)
    row = 0
    col = 0
    number = ''
    
    for char in pattern:
        if char.isdigit():
            number += char
        else:
            if number:
                repeat = int(number)
                number = ''
            else:
                repeat = 1
            
            if char == 'b':
                col += repeat
            elif char == 'o':
                arr[row, col] = 1
                col += 1
            elif char == '$':
                row += 1
                col = 0
            elif char == '!':
                break
    
    return arr

# Example usage
pattern = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
h = 77
w = 77

arr = rle_to_arr(pattern, h, w)
print(arr)

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
import numpy as np

def rle_to_arr(pattern, h, w):
    arr = np.zeros((h, w), dtype=int)
    row = 0
    col = 0
    number = ''
    
    for char in pattern:
        if char.isdigit():
            number += char
        else:
            if number:
                repeat = int(number)
                number = ''
            else:
                repeat = 1
            
            if char == 'b':
                col += repeat
            elif char == 'o':
                arr[row, col] = 1
                col += 1
            elif char == '$':
                row += 1
                col = 0
            elif char == '!':
                break
    
    return arr

# Example usage
pattern = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
h = 77
w = 77

arr = rle_to_arr(pattern, h, w)
print(arr)





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 38, in <module> arr = rle_to_arr(pattern, h, w) ^^^^^^^^^^^^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 23, in rle_to_arr arr[row, col] = 1 ~~~^^^^^^^^^^ IndexError: index 84 is out of bounds for axis 1 with size 77

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

Sure, here's a Python function that takes an RLE string, height, and width as input and returns a NumPy array with the corresponding pattern: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
import numpy as np

def rle_to_arr(pattern, h, w):
    # Initialize an empty array with the given height and width
    arr = np.zeros((h, w), dtype=int)
    
    # Split the RLE pattern into rows
    rows = pattern.split('$')
    
    # Keep track of the current row and column
    row = 0
    col = 0
    
    for r in rows:
        # Skip empty rows
        if not r:
            continue
        
        # Extract the run-length values and counts
        values = []
        counts = []
        num_iter = iter(r)
        for c in num_iter:
            if c.isdigit():
                count = int(c)
                value = next(num_iter)
                if value == 'b':
                    values.append(0)
                else:
                    values.append(1)
                counts.append(count)
        
        # Fill the array with the run-length values
        for val, count in zip(values, counts):
            arr[row, col:col+count] = val
            col += count
        
        # Move to the next row
        row += 1
        col = 0
    
    return arr
To use this function, you can call it with the RLE string, height, and width: 
1
2
3
4
5
6
pattern = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
h = 100  # Replace with the desired height
w = 100  # Replace with the desired width

arr = rle_to_arr(pattern, h, w)
print(arr)
This will create a NumPy array `arr` with the given pattern, where 1s represent live cells and 0s represent dead cells. Note: Make sure to replace `h` and `w` with the desired height and width of the array, respectively. If the RLE pattern extends beyond the array boundaries, it will be truncated.

Extract Code

I extracted the following code from that output: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
import numpy as np

def rle_to_arr(pattern, h, w):
    arr = np.zeros((h, w), dtype=int)
    rows = pattern.split('$')
    row = 0
    col = 0
    
    for r in rows:
        if not r:
            continue
        
        values = []
        counts = []
        num_iter = iter(r)
        for c in num_iter:
            if c.isdigit():
                count = int(c)
                value = next(num_iter)
                if value == 'b':
                    values.append(0)
                else:
                    values.append(1)
                counts.append(count)
        
        for val, count in zip(values, counts):
            arr[row, col:col+count] = val
            col += count
        
        row += 1
        col = 0
    
    return arr

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
import numpy as np

def rle_to_arr(pattern, h, w):
    arr = np.zeros((h, w), dtype=int)
    rows = pattern.split('$')
    row = 0
    col = 0
    
    for r in rows:
        if not r:
            continue
        
        values = []
        counts = []
        num_iter = iter(r)
        for c in num_iter:
            if c.isdigit():
                count = int(c)
                value = next(num_iter)
                if value == 'b':
                    values.append(0)
                else:
                    values.append(1)
                counts.append(count)
        
        for val, count in zip(values, counts):
            arr[row, col:col+count] = val
            col += count
        
        row += 1
        col = 0
    
    return arr





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 40, in <module> answer = (np.array(rle_to_arr(''' ^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 20, in rle_to_arr value = next(num_iter) ^^^^^^^^^^^^^^ StopIteration

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

Sure, here's a Python function that takes a Run Length Encoded (RLE) pattern string from Conway's Game of Life and converts it to a numpy array: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
import numpy as np

def rle_to_arr(string, h, w):
    pattern = []
    nums = []
    for c in string:
        if c.isdigit():
            nums.append(int(c))
        else:
            if nums:
                pattern.extend([int(''.join(nums))])
                nums = []
            pattern.append(c)

    arr = np.zeros((h, w), dtype=int)
    row, col = 0, 0
    for i in range(len(pattern)):
        if pattern[i] == 'b':
            row += 1
        elif pattern[i] == '$':
            row = 0
            col += 1
        elif pattern[i] == 'o':
            arr[row, col] = 1
            col += 1
        else:
            num_repeat = pattern[i]
            for _ in range(num_repeat):
                arr[row, col] = 1
                col += 1

    return arr
You can use this function like this: 
1
2
3
4
rle_string = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o"
h, w = 80, 80
arr = rle_to_arr(rle_string, h, w)
print(arr.shape)  # (80, 80)
The `rle_to_arr` function takes three arguments: 1. `string`: The RLE pattern string. 2. `h`: The desired height of the output array. 3. `w`: The desired width of the output array. It returns a numpy array of shape `(h, w)` with 1s representing live cells and 0s representing dead cells. Here's how the function works: 1. The RLE pattern string is parsed into a list of characters and numbers. 2. A numpy array of shape `(h, w)` is initialized with all elements set to 0. 3. The function iterates through the parsed pattern and updates the array accordingly: - `'b'` moves to the next row. - `'$'` moves to the next column and resets the row to 0. - `'o'` sets the current cell to 1 and moves to the next column. - A number `n` sets the next `n` cells to 1 and moves the column pointer `n` steps forward. Note that this implementation assumes that the input RLE pattern string is valid and fits within the specified array dimensions.

Extract Code

I extracted the following code from that output: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
import numpy as np

def rle_to_arr(string, h, w):
    pattern = []
    nums = []
    for c in string:
        if c.isdigit():
            nums.append(int(c))
        else:
            if nums:
                pattern.extend([int(''.join(nums))])
                nums = []
            pattern.append(c)

    arr = np.zeros((h, w), dtype=int)
    row, col = 0, 0
    for i in range(len(pattern)):
        if pattern[i] == 'b':
            row += 1
        elif pattern[i] == '$':
            row = 0
            col += 1
        elif pattern[i] == 'o':
            arr[row, col] = 1
            col += 1
        else:
            num_repeat = pattern[i]
            for _ in range(num_repeat):
                arr[row, col] = 1
                col += 1

    return arr

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
import numpy as np

def rle_to_arr(string, h, w):
    pattern = []
    nums = []
    for c in string:
        if c.isdigit():
            nums.append(int(c))
        else:
            if nums:
                pattern.extend([int(''.join(nums))])
                nums = []
            pattern.append(c)

    arr = np.zeros((h, w), dtype=int)
    row, col = 0, 0
    for i in range(len(pattern)):
        if pattern[i] == 'b':
            row += 1
        elif pattern[i] == '$':
            row = 0
            col += 1
        elif pattern[i] == 'o':
            arr[row, col] = 1
            col += 1
        else:
            num_repeat = pattern[i]
            for _ in range(num_repeat):
                arr[row, col] = 1
                col += 1

    return arr





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 39, in <module> answer = (np.array(rle_to_arr(''' ^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 12, in rle_to_arr pattern.extend([int(''.join(nums))]) ^^^^^^^^^^^^^ TypeError: sequence item 0: expected str instance, int found

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

Here's a Python function that converts the given Game of Life pattern represented in run-length encoding (RLE) format to a NumPy array: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
import numpy as np

def rle_to_arr(rle_string, h, w):
    """
    Convert a Run Length Encoded pattern string to a NumPy array.
    
    Args:
        rle_string (str): The pattern string in RLE format.
        h (int): The height of the output array.
        w (int): The width of the output array.
        
    Returns:
        np.ndarray: A NumPy array of shape (h, w) with 1s representing live cells
                    and 0s representing dead cells.
    """
    arr = np.zeros((h, w), dtype=int)
    pattern = rle_string.split('$')
    
    for row, rle in enumerate(pattern[:-1]):
        x = 0
        for run in rle.split('b'):
            if run:
                count = int(run) if run.isdigit() else 1
                arr[row, x:x+count] = 1
                x += count
            x += 1
    
    return arr
To use this function, you can call it with the provided RLE string and the desired height and width of the output array: 
1
2
3
4
5
6
rle_string = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o"
height = 55
width = 76

arr = rle_to_arr(rle_string, height, width)
print(arr)
This will print the resulting NumPy array with 1s representing live cells and 0s representing dead cells.

Extract Code

I extracted the following code from that output: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
import numpy as np

def rle_to_arr(rle_string, h, w):
    """
    Convert a Run Length Encoded pattern string to a NumPy array.
    
    Args:
        rle_string (str): The pattern string in RLE format.
        h (int): The height of the output array.
        w (int): The width of the output array.
        
    Returns:
        np.ndarray: A NumPy array of shape (h, w) with 1s representing live cells
                    and 0s representing dead cells.
    """
    arr = np.zeros((h, w), dtype=int)
    pattern = rle_string.split('$')
    
    for row, rle in enumerate(pattern[:-1]):
        x = 0
        for run in rle.split('b'):
            if run:
                count = int(run) if run.isdigit() else 1
                arr[row, x:x+count] = 1
                x += count
            x += 1
    
    return arr

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
import numpy as np

def rle_to_arr(rle_string, h, w):
    """
    Convert a Run Length Encoded pattern string to a NumPy array.
    
    Args:
        rle_string (str): The pattern string in RLE format.
        h (int): The height of the output array.
        w (int): The width of the output array.
        
    Returns:
        np.ndarray: A NumPy array of shape (h, w) with 1s representing live cells
                    and 0s representing dead cells.
    """
    arr = np.zeros((h, w), dtype=int)
    pattern = rle_string.split('$')
    
    for row, rle in enumerate(pattern[:-1]):
        x = 0
        for run in rle.split('b'):
            if run:
                count = int(run) if run.isdigit() else 1
                arr[row, x:x+count] = 1
                x += count
            x += 1
    
    return arr





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 52, in <module> assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' ^^^^^^^^^^^^^^^^^^ AssertionError: Wrong answer; got 6518120 instead of 1563304

Substring Evaluation

Testing if the previous output contains the string All tests passed: False

Initial Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

LLM Generation

Query

Convert this game of life pattern 26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b 2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$ 60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5b o15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2b o$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o 3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o! to a numpy array. Call the function `rle_to_arr(string, h, w)` which should return a numpy array with .shape (h,w). Fill the array with 1s, and empty with 0.

Output

Here's a Python function that takes an RLE string, height, and width as input, and returns a NumPy array filled with 1s for live cells and 0s for dead cells: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
import numpy as np

def rle_to_arr(rle_string, h, w):
    arr = np.zeros((h, w), dtype=int)
    row = 0
    col = 0

    for pattern in rle_string.split('$'):
        if not pattern:
            continue

        if pattern.endswith('b'):
            row += int(pattern[:-1])
        else:
            rep = int(pattern[:-1]) if pattern[-1].isdigit() else 1
            for _ in range(rep):
                arr[row, col] = 1
                col += 1

    return arr
To use this function, you can call it with the RLE string, height, and width: 
1
2
3
4
5
6
rle_string = "26$13b2o$14bo$14bobo$15b2o14$31b2o$30b2o$32bo13$46b2o$45b2o$47bo13$61b2o$60b2o$62bo4$52b2o$52b2o$71bo$66b2ob3o$66bobobo$68bo$67b2o3$76b2o$60b3o12b2o10bobo$52b3o7bo14bo8bo2bo4bo$51bo3bo5bo10b2o11b2o5b2o$50bo5bo15bobo8b2o3bo8b2o$51bo3bo11b2o6bo9b2o10b2o$52b3o8b2obo2bo2bo2bo10bo2bo$52bo2bo7b2o2b2o6bo11bobo$53b3o16bobo$53b2obo15b2o$54bobo$55bo3$52b2o3b2o$52bobobobo$53b5o$54b3o$55bo7$54b2o$54b2o!"
h = 80
w = 80

arr = rle_to_arr(rle_string, h, w)
print(arr)
This will print a NumPy array with the specified dimensions, with 1s for live cells and 0s for dead cells. Note that this implementation assumes that the input RLE string is valid and follows the Life 1.06 format. It also assumes that the specified height and width are large enough to accommodate the pattern described by the RLE string.

Extract Code

I extracted the following code from that output: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
import numpy as np

def rle_to_arr(rle_string, h, w):
    arr = np.zeros((h, w), dtype=int)
    row = 0
    col = 0

    for pattern in rle_string.split('$'):
        if not pattern:
            continue

        if pattern.endswith('b'):
            row += int(pattern[:-1])
        else:
            rep = int(pattern[:-1]) if pattern[-1].isdigit() else 1
            for _ in range(rep):
                arr[row, col] = 1
                col += 1

    return arr

Run Code Interpreter

Running the following program: 

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
import numpy as np

def rle_to_arr(rle_string, h, w):
    arr = np.zeros((h, w), dtype=int)
    row = 0
    col = 0

    for pattern in rle_string.split('$'):
        if not pattern:
            continue

        if pattern.endswith('b'):
            row += int(pattern[:-1])
        else:
            rep = int(pattern[:-1]) if pattern[-1].isdigit() else 1
            for _ in range(rep):
                arr[row, col] = 1
                col += 1

    return arr





answer = (np.array(rle_to_arr('''
16b2o3b2o$2o$2o$19b2o$17b5o$21bo$17b3o$o16bo$o17b2o$bo16b2o$b2o$3bo$o
17b2o3b2o$2b2o14bobobobo$11bobo5b5o$11b2o7b3o$2o10bo8bo$b2o$b2o2$2o$bo
2$6bobo$2o3bo$bo3bo$o4bo2bo7bo$5b3o7b2o7bo$15bobo5b3o$22b5o$21b2o3b2o$
22b5o$22b5o$14b2o6bo2bo$14bobo4bo3bo$11b2obobo4bo$11bobobo5bob2o$13bo
8bo$4bobo6b2o$7bo5b3o50bo$7bo5b3o3b2o3b2o40b4o$4bo2bo5b3o3bo5bo41b4o$
5b3o5b2o35bo16bo2bo$13bo6bo3bo24bobo15b4o4b2o$11bobobo5b3o15b2o7bob2o
14b4o5b2o$11b2obobo21bobo6b2ob2o14bo8b2o$14bobo20bo6b3obob2o$14b2o12b
2o7bo2bo2bo2bo2bobo$28b2o7bo6b2o4bo16bobo$38bobo26b2o$39b2o27bo4b2o$
21b2o49bo2bo$21b2o28bobo18b3o$52b2o21b2o$52bo21bo$74b2o$59bo$62bo$59bo
14bo$62bo$61bob3o8bo$59b4o2bo9b2o$64bo$52bo$51b2o$40b2o8b2o4b2o5bo$40b
2o7b3o4b2o3bobo$50b2o4b2o2bobo11b2o$4bobo44b2o6bo2bo11b2o$7bo44bo7bobo
$o6bo53bobo$o3bo2bo55bo$5b3o5$4b4o$3bo3bo$7bo$3bo2bo3$o2b3o2b2o$2b5o2b
o64b3o$9o67bo$9b3o63bo$o7bo2bo$9b2o3$4b2o$o3b3o$o5b2obo5b2o$bo4bo2bo5b
2o$2o4b2obo$o3b3o$4b2o2$59b3o12b2o$61bo12b2o!
''', 101, 77),dtype=np.uint32).flatten() * np.arange(77*101)).sum()
expected = 1563304
assert answer == expected, f'Wrong answer; got {answer} instead of {expected}'
print('All tests passed')
And got the output: Traceback (most recent call last): File "/usr/src/app/main.py", line 27, in <module> answer = (np.array(rle_to_arr(''' ^^^^^^^^^^^^^^ File "/usr/src/app/main.py", line 16, in rle_to_arr rep = int(pattern[:-1]) if pattern[-1].isdigit() else 1 ^^^^^^^^^^^^^^^^^ ValueError: invalid literal for int() with base 10: 'b2o'

Substring Evaluation

Testing if the previous output contains the string All tests passed: False