Fix this tokenizer keeping it as similar as possible class Tokenizer: def __init__(self, input_str): self.tokens = re.findall(r'\d+|(\+|\-|\*|/|sin|cos|\(|\))', input_str) self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position]
Fix this tokenizer keeping it as similar as possible class Tokenizer: def __init__(self, input_str): self.tokens = re.findall(r'\d+|(\+|\-|\*|/|sin|cos|\(|\))', input_str) self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position]
Here's a fixed version of the tokenizer that handles numbers and operators more reliably while maintaining a similar structure:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 | import re class Tokenizer: def __init__(self, input_str): # Remove whitespace and create a pattern that matches numbers and operators pattern = r'(\d*\.?\d+)|(\+|\-|\*|/|sin|cos|\(|\))' # findall returns a list of tuples, so we need to filter out empty matches matches = re.finditer(pattern, input_str.replace(' ', '')) self.tokens = [match.group() for match in matches] self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position] |
1 2 3 4 5 6 7 | # Test the tokenizer tokenizer = Tokenizer("3.14 + sin(2) * 5") while True: token = tokenizer.get_next_token() if token is None: break print(token) |
1 2 3 4 5 6 7 8 | 3.14 + sin ( 2 ) * 5 |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 | import re class Tokenizer: def __init__(self, input_str): # Remove whitespace and create a pattern that matches numbers and operators pattern = r'(\d*\.?\d+)|(\+|\-|\*|/|sin|cos|\(|\))' # findall returns a list of tuples, so we need to filter out empty matches matches = re.finditer(pattern, input_str.replace(' ', '')) self.tokens = [match.group() for match in matches] self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position] |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 | import re class Tokenizer: def __init__(self, input_str): # Remove whitespace and create a pattern that matches numbers and operators pattern = r'(\d*\.?\d+)|(\+|\-|\*|/|sin|cos|\(|\))' # findall returns a list of tuples, so we need to filter out empty matches matches = re.finditer(pattern, input_str.replace(' ', '')) self.tokens = [match.group() for match in matches] self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position] answer = Tokenizer('sin(3+2*4)-cos(15)').tokens expected = ['sin', '(', '3', '+', '2', '*', '4', ')', '-', 'cos', '(', '15', ')'] assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' print('All tests passed') |
All tests passed
Testing if the previous output contains the string All tests passed
: True
Fix this tokenizer keeping it as similar as possible class Tokenizer: def __init__(self, input_str): self.tokens = re.findall(r'\d+|(\+|\-|\*|/|sin|cos|\(|\))', input_str) self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position]
Fix this tokenizer keeping it as similar as possible class Tokenizer: def __init__(self, input_str): self.tokens = re.findall(r'\d+|(\+|\-|\*|/|sin|cos|\(|\))', input_str) self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position]
Here's a fixed version of the tokenizer that handles numbers and operators more reliably:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 | import re class Tokenizer: def __init__(self, input_str): # Updated regex pattern to properly capture numbers and operators # Remove whitespace from input string first input_str = input_str.replace(' ', '') pattern = r'(?:\d*\.?\d+)|sin|cos|\+|\-|\*|/|\(|\)' self.tokens = re.findall(pattern, input_str) self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position] |
1 2 3 4 5 6 | tokenizer = Tokenizer("3.14 + sin(2) * 10") while True: token = tokenizer.get_next_token() if token is None: break print(token) |
1 2 3 4 5 6 7 8 | 3.14 + sin ( 2 ) * 10 |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 | import re class Tokenizer: def __init__(self, input_str): # Updated regex pattern to properly capture numbers and operators # Remove whitespace from input string first input_str = input_str.replace(' ', '') pattern = r'(?:\d*\.?\d+)|sin|cos|\+|\-|\*|/|\(|\)' self.tokens = re.findall(pattern, input_str) self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position] |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 | import re class Tokenizer: def __init__(self, input_str): # Updated regex pattern to properly capture numbers and operators # Remove whitespace from input string first input_str = input_str.replace(' ', '') pattern = r'(?:\d*\.?\d+)|sin|cos|\+|\-|\*|/|\(|\)' self.tokens = re.findall(pattern, input_str) self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position] answer = Tokenizer('sin(3+2*4)-cos(15)').tokens expected = ['sin', '(', '3', '+', '2', '*', '4', ')', '-', 'cos', '(', '15', ')'] assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' print('All tests passed') |
All tests passed
Testing if the previous output contains the string All tests passed
: True
Fix this tokenizer keeping it as similar as possible class Tokenizer: def __init__(self, input_str): self.tokens = re.findall(r'\d+|(\+|\-|\*|/|sin|cos|\(|\))', input_str) self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position]
Fix this tokenizer keeping it as similar as possible class Tokenizer: def __init__(self, input_str): self.tokens = re.findall(r'\d+|(\+|\-|\*|/|sin|cos|\(|\))', input_str) self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position]
Here's a fixed version of the tokenizer that handles numbers and operators more reliably:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 | import re class Tokenizer: def __init__(self, input_str): # Remove whitespace and find all tokens input_str = input_str.replace(' ', '') # Modified pattern to properly capture numbers and operators pattern = r'(\d*\.?\d+)|(\+|\-|\*|/|sin|cos|\(|\))' self.tokens = [t[0] or t[1] for t in re.findall(pattern, input_str) if t[0] or t[1]] self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position] |
1 2 3 4 5 6 | tokenizer = Tokenizer("123.45 + sin(30) * 2") while True: token = tokenizer.get_next_token() if token is None: break print(token) |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 | import re class Tokenizer: def __init__(self, input_str): # Remove whitespace and find all tokens input_str = input_str.replace(' ', '') # Modified pattern to properly capture numbers and operators pattern = r'(\d*\.?\d+)|(\+|\-|\*|/|sin|cos|\(|\))' self.tokens = [t[0] or t[1] for t in re.findall(pattern, input_str) if t[0] or t[1]] self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position] |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 | import re class Tokenizer: def __init__(self, input_str): # Remove whitespace and find all tokens input_str = input_str.replace(' ', '') # Modified pattern to properly capture numbers and operators pattern = r'(\d*\.?\d+)|(\+|\-|\*|/|sin|cos|\(|\))' self.tokens = [t[0] or t[1] for t in re.findall(pattern, input_str) if t[0] or t[1]] self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position] answer = Tokenizer('sin(3+2*4)-cos(15)').tokens expected = ['sin', '(', '3', '+', '2', '*', '4', ')', '-', 'cos', '(', '15', ')'] assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' print('All tests passed') |
All tests passed
Testing if the previous output contains the string All tests passed
: True
Fix this tokenizer keeping it as similar as possible class Tokenizer: def __init__(self, input_str): self.tokens = re.findall(r'\d+|(\+|\-|\*|/|sin|cos|\(|\))', input_str) self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position]
Fix this tokenizer keeping it as similar as possible class Tokenizer: def __init__(self, input_str): self.tokens = re.findall(r'\d+|(\+|\-|\*|/|sin|cos|\(|\))', input_str) self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position]
Here's a fixed version of the tokenizer that handles a few common issues while keeping the structure similar:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 | import re class Tokenizer: def __init__(self, input_str): # Remove whitespace and find all tokens # Capture numbers, operators, functions, and parentheses # The + after \d+ ensures we capture multi-digit numbers pattern = r'\d+\.?\d*|[\+\-\*\/\(\)]|sin|cos' self.tokens = [t for t in re.findall(pattern, input_str.replace(' ', '')) if t] self.position = 0 def get_next_token(self): """ Returns the next token and advances the position. Returns None if there are no more tokens. """ if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): """ Returns the next token without advancing the position. Returns None if there are no more tokens. """ if self.position >= len(self.tokens): return None return self.tokens[self.position] def has_more_tokens(self): """ Returns True if there are more tokens to process. """ return self.position < len(self.tokens) |
1 2 3 4 | # Example usage tokenizer = Tokenizer("3 + 4.5 * sin(2)") while tokenizer.has_more_tokens(): print(tokenizer.get_next_token()) |
1 2 3 | tokenizer = Tokenizer("3.14 + 2 * sin(30)") print(tokenizer.peek_next_token()) # Shows next token without advancing print(tokenizer.get_next_token()) # Gets token and advances |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 | import re class Tokenizer: def __init__(self, input_str): # Remove whitespace and find all tokens # Capture numbers, operators, functions, and parentheses # The + after \d+ ensures we capture multi-digit numbers pattern = r'\d+\.?\d*|[\+\-\*\/\(\)]|sin|cos' self.tokens = [t for t in re.findall(pattern, input_str.replace(' ', '')) if t] self.position = 0 def get_next_token(self): """ Returns the next token and advances the position. Returns None if there are no more tokens. """ if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): """ Returns the next token without advancing the position. Returns None if there are no more tokens. """ if self.position >= len(self.tokens): return None return self.tokens[self.position] def has_more_tokens(self): """ Returns True if there are more tokens to process. """ return self.position < len(self.tokens) |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 | import re class Tokenizer: def __init__(self, input_str): # Remove whitespace and find all tokens # Capture numbers, operators, functions, and parentheses # The + after \d+ ensures we capture multi-digit numbers pattern = r'\d+\.?\d*|[\+\-\*\/\(\)]|sin|cos' self.tokens = [t for t in re.findall(pattern, input_str.replace(' ', '')) if t] self.position = 0 def get_next_token(self): """ Returns the next token and advances the position. Returns None if there are no more tokens. """ if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): """ Returns the next token without advancing the position. Returns None if there are no more tokens. """ if self.position >= len(self.tokens): return None return self.tokens[self.position] def has_more_tokens(self): """ Returns True if there are more tokens to process. """ return self.position < len(self.tokens) answer = Tokenizer('sin(3+2*4)-cos(15)').tokens expected = ['sin', '(', '3', '+', '2', '*', '4', ')', '-', 'cos', '(', '15', ')'] assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' print('All tests passed') |
All tests passed
Testing if the previous output contains the string All tests passed
: True
Fix this tokenizer keeping it as similar as possible class Tokenizer: def __init__(self, input_str): self.tokens = re.findall(r'\d+|(\+|\-|\*|/|sin|cos|\(|\))', input_str) self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position]
Fix this tokenizer keeping it as similar as possible class Tokenizer: def __init__(self, input_str): self.tokens = re.findall(r'\d+|(\+|\-|\*|/|sin|cos|\(|\))', input_str) self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position]
Here's a fixed version of the tokenizer that handles whitespace, properly captures numbers, and deals with None values from the regex matching:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 | import re class Tokenizer: def __init__(self, input_str): # Remove whitespace and find all tokens self.tokens = [t for t in re.findall(r'-?\d*\.?\d+|[\+\-\*/\(\)]|sin|cos', input_str.replace(" ", "")) if t] self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position] |
1 2 3 4 5 6 | tokenizer = Tokenizer("3.14 + sin(2) * -5.6") while True: token = tokenizer.get_next_token() if token is None: break print(token) |
I extracted the following code from that output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 | import re class Tokenizer: def __init__(self, input_str): # Remove whitespace and find all tokens self.tokens = [t for t in re.findall(r'-?\d*\.?\d+|[\+\-\*/\(\)]|sin|cos', input_str.replace(" ", "")) if t] self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position] |
Running the following program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 | import re class Tokenizer: def __init__(self, input_str): # Remove whitespace and find all tokens self.tokens = [t for t in re.findall(r'-?\d*\.?\d+|[\+\-\*/\(\)]|sin|cos', input_str.replace(" ", "")) if t] self.position = 0 def get_next_token(self): if self.position >= len(self.tokens): return None token = self.tokens[self.position] self.position += 1 return token def peek_next_token(self): if self.position >= len(self.tokens): return None return self.tokens[self.position] answer = Tokenizer('sin(3+2*4)-cos(15)').tokens expected = ['sin', '(', '3', '+', '2', '*', '4', ')', '-', 'cos', '(', '15', ')'] assert answer == expected, f'Wrong answer; got {answer} instead of {expected}' print('All tests passed') |
All tests passed
Testing if the previous output contains the string All tests passed
: True