Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
The function won't work as expected because of a potential **index error** when accessing `config[1]` in the recursive call `make_op_with_history(config[1])`. If `config` has fewer than 2 elements, `config[1]` will raise an `IndexError`. Specifically, the line `make_op_with_history(config[1])` assumes that `config[1]` exists, but if `config` is empty or contains only one item, this will result in an error.
I asked a question about why some code was incorrect. The answer is "because because the code uses append instead of extend". Does this student answer say that? Giving multiple answers is okay as long as it also says somewhere that the code should replace the append with extend. The function won't work as expected because of a potential **index error** when accessing `config[1]` in the recursive call `make_op_with_history(config[1])`. If `config` has fewer than 2 elements, `config[1]` will raise an `IndexError`. Specifically, the line `make_op_with_history(config[1])` assumes that `config[1]` exists, but if `config` is empty or contains only one item, this will result in an error. Answer either 'The student passes' or 'The student fails'.
The student fails.
Testing if the previous output contains the string student passes
: False
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
One reason the function won't work as expected is that there's a potential issue in the recursive call `make_op_with_history(config[1])`. The `config[1]` in this context is likely a single argument (not a complete configuration list), which can cause the function to fail because it expects a list similar to `config` with a specific structure. To illustrate, the function expects `config` to be a list where the first element is a string (operation type) and the remaining elements are either arguments or configurations for further operations. However, `config[1]` is just a single element from the original `config`, likely causing the function to break due to unexpected input. Additionally, there's a similar issue in the loop at the end where `arg` is passed to `make_op_with_history(arg)`, which might not follow the expected `config` structure. This could also result in an error if `arg` is not a configuration list. To fix this issue, you need to ensure that the recursive calls receive properly structured configuration lists.
I asked a question about why some code was incorrect. The answer is "because because the code uses append instead of extend". Does this student answer say that? Giving multiple answers is okay as long as it also says somewhere that the code should replace the append with extend. One reason the function won't work as expected is that there's a potential issue in the recursive call `make_op_with_history(config[1])`. The `config[1]` in this context is likely a single argument (not a complete configuration list), which can cause the function to fail because it expects a list similar to `config` with a specific structure. To illustrate, the function expects `config` to be a list where the first element is a string (operation type) and the remaining elements are either arguments or configurations for further operations. However, `config[1]` is just a single element from the original `config`, likely causing the function to break due to unexpected input. Additionally, there's a similar issue in the loop at the end where `arg` is passed to `make_op_with_history(arg)`, which might not follow the expected `config` structure. This could also result in an error if `arg` is not a configuration list. To fix this issue, you need to ensure that the recursive calls receive properly structured configuration lists. Answer either 'The student passes' or 'The student fails'.
The student fails.
Testing if the previous output contains the string student passes
: False
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
One reason why the function might not work as expected is that in the second `if` clause:
1 2 | if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) |
1 2 | if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(args) |
I asked a question about why some code was incorrect. The answer is "because because the code uses append instead of extend". Does this student answer say that? Giving multiple answers is okay as long as it also says somewhere that the code should replace the append with extend. One reason why the function might not work as expected is that in the second `if` clause:
1 2 | if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) |
1 2 | if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(args) |
The student fails.
Testing if the previous output contains the string student passes
: False
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
The function `make_op_with_history` won't work as expected because of the line:
1 | return [(how, make_op(config))] + make_op_with_history(config[1]) |
I asked a question about why some code was incorrect. The answer is "because because the code uses append instead of extend". Does this student answer say that? Giving multiple answers is okay as long as it also says somewhere that the code should replace the append with extend. The function `make_op_with_history` won't work as expected because of the line:
1 | return [(how, make_op(config))] + make_op_with_history(config[1]) |
The student fails.
Testing if the previous output contains the string student passes
: False
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
Why won't this function work as expected? List exactly one reason.
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history(config[1]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
The function will not work as expected because in the second `if` condition, `make_op_with_history(config[1])` should be `make_op_with_history([config[1]])`. This is because `config[1]` will be a single element from the `config` list, not a list itself, and the function expects a list as its input. Here's the corrected code snippet:
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history([config[1]]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
I asked a question about why some code was incorrect. The answer is "because because the code uses append instead of extend". Does this student answer say that? Giving multiple answers is okay as long as it also says somewhere that the code should replace the append with extend. The function will not work as expected because in the second `if` condition, `make_op_with_history(config[1])` should be `make_op_with_history([config[1]])`. This is because `config[1]` will be a single element from the `config` list, not a list itself, and the function expects a list as its input. Here's the corrected code snippet:
1 2 3 4 5 6 7 8 9 10 11 12 13 | def make_op_with_history(config): how = config[0] args = config[1:] if how.split()[0] == 'dot_from_papers': return [(how, make_op(config))] if how.split()[0] in ['const_add', 'const_mul']: return [(how, make_op(config))] + make_op_with_history([config[1]]) out = [] for arg in args: hist = make_op_with_history(arg) out.append(hist) return [(how, make_op(config))] + out |
The student fails.
Testing if the previous output contains the string student passes
: False